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17-Phys-B4 Signals and Communications · December 2016

Question 6 of 6: VCO-Based FM Modulator — Output Expression, Demodulation, Carson Bandwidth

Nivaar worked solution (AI-drafted; not reviewed by a licensed engineer)

Notes on this paper

Paper format. 98-Phys-B4 Communications, National Examination December 2016 — a three-hour closed-book examination (a standard non-programmable, no-text-storage calculator is the only aid permitted). The cover page states any five of the six questions constitute a complete paper, with only the first five as they appear in the answer book marked; every question is nonetheless answered in full below so the paper remains a complete study resource. All six questions carry equal value.

Reference texts. A. V. Oppenheim and A. S. Willsky, Signals and Systems, 2nd ed. (Fourier series, sampling, z-transform); S. Haykin and M. Moher, Communication Systems, 5th ed. (AM/DSB/FM modulation, PCM, mixers and frequency conversion); B. P. Lathi and Z. Ding, Modern Digital and Analog Communication Systems, 4th ed. (envelope detection, Carson's rule); J. G. Proakis and D. G. Manolakis, Digital Signal Processing, 4th ed. (z-transform stability, partial-fraction inversion).

Question 6: VCO-Based FM Modulator — Output Expression, Demodulation, Carson Bandwidth (1/6 of paper)

Question text not reproduced: the examination questions are © Engineers and Geoscientists BC. Open the official past paper (linked at the top of this page) to read the question, then follow the worked solution below.

Given. VCO characteristic: a straight line through $(f,V)=(f_c,0)$ with slope $dV/df=10^{-4}\text{ V/Hz}$. Modulator output power $=10$ (part a). Message bandwidth $W=10\text{ kHz}$, peak value $m_p=2\text{ V}$ (part c).

V f f_c slope = 10⁻⁴ V/Hz
VCO characteristic: V is linear in f near f_c, slope dV/df = 10⁻⁴ V/Hz.

Find. (a) FM modulator output $s(t)$ in terms of $m(t)$; (b) a demodulator block diagram; (c) approximate FM bandwidth.

Approach. Invert the VCO's given $V$-vs-$f$ slope to obtain its frequency sensitivity $K_v$ (in Hz/V, the quantity that actually drives instantaneous frequency); write the standard FM instantaneous-phase expression using $K_v\,m(t)$ as the frequency-deviation term, with amplitude set by the given output power; choose a standard FM discriminator for the demodulator; and apply Carson's rule with the peak deviation $K_v\times$(peak of $m$).

  1. Part (a) — FM modulator output. The given slope is $dV/df=10^{-4}\text{ V/Hz}$ (volts needed per hertz of shift); the VCO's frequency SENSITIVITY is its reciprocal, $$K_v=\frac{df}{dV}=\frac{1}{10^{-4}}=\boxed{10^4\text{ Hz/V}}$$ so driving the VCO with $m(t)$ volts produces an instantaneous frequency $f_i(t)=f_c+K_vm(t)$ and phase $\theta(t)=2\pi f_ct+2\pi K_v\int_0^tm(\lambda)\,d\lambda$. The output power is $A_c^2/2=10$, so $A_c=\sqrt{20}=2\sqrt5$: $$s(t)=\boxed{2\sqrt5\,\cos\!\Big[2\pi f_ct+2\pi\!\cdot\!10^4\!\int_0^tm(\lambda)\,d\lambda\Big]}$$
  2. Part (b) — FM demodulator. A standard non-coherent FM discriminator recovers $m(t)$ without needing a phase-locked local oscillator: limit the signal to remove amplitude noise/variation, differentiate (which converts instantaneous-frequency variation into amplitude variation, since $d\theta/dt=2\pi f_c+2\pi K_vm(t)$), envelope-detect, then low-pass filter to strip the DC term left by $f_c$: $$s_{FM}(t)\ \xrightarrow{\text{limiter}}\ \xrightarrow{d/dt}\ \xrightarrow{\text{envelope det.}}\ \xrightarrow{\text{LPF, no dc}}\ \propto m(t)$$ (a PLL-based demodulator, using a second VCO of the same $K_v$ locked to $s_{FM}(t)$, would be an equally standard alternative.)
  3. s_FM(t) Limiter d/dt differentiator Envelope detector LPF no dc m(t)
    FM discriminator: limiter → differentiator → envelope detector → LPF, recovering m(t).
  4. Part (c) — approximate FM bandwidth (Carson's rule). The peak frequency deviation is the VCO sensitivity times the message's peak value: $$\Delta f=K_v\times m_p=10^4\text{ Hz/V}\times2\text{ V}=\boxed{20\text{ kHz}}$$ Carson's rule then bounds the FM bandwidth using the message bandwidth $W=10\text{ kHz}$: $$BW_{FM}\approx2(\Delta f+W)=2(20+10)\text{ kHz}=\boxed{60\text{ kHz}}$$
Question 6 — final results
QuantityResult
VCO sensitivity $K_v$$10^4\text{ Hz/V}$
Modulator output $s(t)$$2\sqrt5\cos\big[2\pi f_ct+2\pi\cdot10^4\!\int m\,d\lambda\big]$
Demodulatorlimiter → differentiator → envelope det. → LPF
Peak deviation $\Delta f$$20\text{ kHz}$
FM bandwidth (Carson)$\approx60\text{ kHz}$
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