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17-Phys-B5 Systems and Control · May 2018

Question 3 of 8: Steady-State Error Design, Gain Margin, and Superposed Ramp Disturbance

Nivaar worked solution (AI-drafted; not reviewed by a licensed engineer)

Notes on this paper

Paper format. 17-Phys-B5 Systems and Control, National Exams May 2018 — a three-hour closed-book examination with one double-sided handwritten formula/notes sheet permitted and an approved calculator. Questions 1 and 2 are compulsory; candidates choose three of the remaining six (3–8). Every question is nonetheless answered in full below so the paper remains a complete study resource. All eight questions carry equal value (20 marks each).

Reference texts. N. S. Nise, Control Systems Engineering, 7th ed. (transient-response specifications, root locus, Routh–Hurwitz, frequency-response and lead compensator design, state-space representation, steady-state errors); K. Ogata, Modern Control Engineering, 5th ed. (root-locus and PID/rate-feedback compensator design, controllability/observability, Mason's Gain Formula on signal-flow graphs).

Question 3: Steady-State Error Design, Gain Margin, and Superposed Ramp Disturbance (20 marks)

Question text not reproduced: the examination questions are © Engineers and Geoscientists BC. Open the official past paper (linked at the top of this page) to read the question, then follow the worked solution below.

Given. Same signal-flow graph and $G_{cl}(s),G_d(s)$ as Question 1 (general $K_p$); design target $e_{ss(ramp)}=0.5$ V/V (step error is already zero for any stabilizing $K_p$, since the loop is Type 1).

Find. 1) $K_{op}$. 2) Stability and gain margin at $K_p=K_{op}$. 3)&4) Total steady-state error under superposed reference and disturbance ramps, at $K_p=1$ and $K_p=K_{op}$.

Approach. Use the general (symbolic-$K_p$) open-loop TF from Question 1 to get $K_v(K_p)$ and solve $1/K_v=0.5$ for $K_{op}$. The phase-crossover frequency of $G_{open}$ does not depend on $K_p$ (a real scalar gain only shifts magnitude, never phase), so it equals the $\omega_{osc}$ already found in Question 1 — giving the gain margin in one line. For parts 3–4, superpose the reference-tracking error and the disturbance-induced error via the final value theorem.

  1. Part 1) — required $K_{op}$. From Question 1's signal-flow-graph solution, the general (symbolic-$K_p$) open-loop transfer function (loop broken at the outer summing node) is $$G_{open}(s)=\frac{K_p(s+10)}{5s(s^2+2s+3)}\ \Rightarrow\ K_v=\lim_{s\to0}sG_{open}(s)=\frac{2K_p}{3}.$$ Setting $e_{ss(ramp)}=1/K_v=0.5$ gives $K_v=2\Rightarrow \boxed{K_{op}=3}$ — matching the $K_{op}=3.0$ already used in Question 2, confirming that paper's data is exactly the solution to THIS design requirement.
  2. Part 2) — stability and gain margin at $K_p=3$. Since $0<3<3.75$ (Question 1's stable range), the system IS stable. The phase of $G_{open}(j\omega)$ does not depend on $K_p$ (a positive real scalar), so the phase-crossover frequency is the same $\omega_{pc}=\sqrt{15}/2=1.9365$ rad/s found as $\omega_{osc}$ in Question 1. There, $|G_{open}(j\omega_{pc})|=K_{crit}\times(\text{unit gain factor})=1$ by definition of marginal stability, i.e. the "unit-gain factor" equals $1/K_{crit}=1/3.75$. At the OPERATING gain $K_p=3$: $$|G_{open}(j\omega_{pc})|=\frac{3}{3.75}=0.8\ \Rightarrow\ G_m=\frac{1}{0.8}=\boxed{1.25\ \text{V/V}}\ (\approx1.94\ \text{dB}).$$
  3. Part 3) — total SSE at $K_p=1$. By superposition, the error is $e(t)=\big[r(t)-y_r(t)\big]-y_d(t)$, where $y_r$ is the reference-driven output and $y_d$ the disturbance-driven output. For a unit-feedback loop, $$e_{ss}=\lim_{s\to0}s\left[\frac{R(s)}{1+G_{open}(s)}-G_d(s)T_d(s)\right].$$ With $R(s)=2/s^2$ (slope-2 ramp) this reference term is $2/K_v(K_p)$; with $T_d(s)=10/s^2$ the disturbance term uses $G_d(s)=-(s^2+s)/[10s^3+20s^2+(30+2K_p)s+20K_p]$ from Question 1, whose $s\to0$ limit gives $-\lim s\,G_d(s)T_d(s)=1/(2K_p)$. At $K_p=1$: $K_v=2/3$, so the reference term is $2/(2/3)=3$, and the disturbance term is $1/2=0.5$; both errors add (the disturbance opposes tracking in the same sense), giving $$e_{ss,total}=3+0.5=\boxed{3.5}.$$
  4. Part 4) — total SSE at $K_p=K_{op}=3$. Repeating with $K_p=3$: $K_v=2$, reference term $=2/2=1$; disturbance term $=1/(2\times3)=1/6$; total $$e_{ss,total}=1+\frac16=\boxed{\frac76\approx1.167}.$$
Final results — Question 3
ItemResult
$K_{op}$$3$
Stability at $K_p=K_{op}$Stable ($0<3<3.75$)
Gain Margin$1.25$ V/V ($\approx1.94$ dB)
$e_{ss,total}$, $K_p=1$$3.5$
$e_{ss,total}$, $K_p=K_{op}=3$$7/6\approx1.167$