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17-Phys-B5 Systems and Control · Undated paper

Question 4 of 8: Second-Order Dominant-Poles Models — s-Domain, Step, and Frequency Response

Nivaar worked solution (AI-drafted; not reviewed by a licensed engineer)

Notes on this paper

Paper format. 17-Phys-B5 Systems and Control, National Exam, May 2019 — a three-hour closed-book examination with one double-sided handwritten formula/notes sheet permitted and an approved calculator. Questions 1 and 2 are compulsory; candidates choose three of the remaining six (3–8). Every question is nonetheless answered in full below so the paper remains a complete study resource. All eight questions carry equal value (20 marks each).

Reference texts. N. S. Nise, Control Systems Engineering, 7th ed. (transient-response specifications, root locus, Routh–Hurwitz, frequency-response and lead compensator design, state-space representation, steady-state errors); K. Ogata, Modern Control Engineering, 5th ed. (root-locus construction, PID/rate-feedback compensator design, controllability/observability, Mason's Gain Formula on signal-flow graphs).

Question 4: Second-Order Dominant-Poles Models — s-Domain, Step, and Frequency Response (20 marks)

Question text not reproduced: the examination questions are © Engineers and Geoscientists BC. Open the official past paper (linked at the top of this page) to read the question, then follow the worked solution below.

Check
The source page's own printed denominator $(s+5.67)(s^2+1.33s+20.46)$ (page 8) does not algebraically match the cubic $s^3+17s^2+38s+96$ derived independently in Question 3, although BOTH share the identical numerator $2(s+42)$ — an internal rounding/illustration inconsistency in the source exam. This question is answered using the printed $G_{cl}(s)$ AS GIVEN, since Figures Q4.1–Q4.2 (the actual data these sub-parts read from) are generated from exactly this formula — its response matches every feature of the printed plots (peak $\approx1.07$ at $t\approx0.85$ s settling near $0.72$–$0.74$; resonant peak $\approx2.0$ near $\omega\approx4$ rad/s), so no figure-reading uncertainty is introduced.

Given. $G_{cl}(s)=\dfrac{2(s+42)}{(s+5.67)(s^2+1.33s+20.46)}$.

Find. Three second-order dominant-pole models built from three different characterizations of the same system, and a comparison.

Approach. Extract the exact poles for $G_{m1}$; simulate the exact step response and read percent-overshoot/peak-time for $G_{m2}$; simulate the exact frequency response and read the resonant peak/frequency for $G_{m3}$; compare all three against each other and against the full third-order response.

  1. Part 1) — why dominant-poles, and $G_{m1}(s)$. The denominator factors exactly as given: a real pole at $s=-5.67$ and a complex pair from $s^2+1.33s+20.46=0$, i.e. $s=-0.665\pm j4.4744$ ($\omega_n=\sqrt{20.46}=4.5233$, $\zeta=1.33/(2\times4.5233)=0.1470$). The real pole's magnitude ($5.67$) is $8.5\times$ the complex pair's real part ($0.665$) — well past the standard $5\times$-separation rule — so the complex pair dominates the transient and a 2nd-order model built purely from these poles is justified. Matching the exact DC gain $G_{cl}(0)=2(42)/[5.67\times20.46]=0.7241$: $$\boxed{G_{m1}(s)=\frac{0.7241\times20.46}{s^2+1.33s+20.46}=\frac{14.82}{s^2+1.33s+20.46}}.$$
  2. Part 2) — from the step response, $G_{m2}(s)$. Simulating $G_{cl}(s)$'s exact step response reproduces Figure Q4.1: peak $y_{max}=1.0678$ at $t_p=0.8430$ s, settling to $y_{ss}=0.7241$ (matching the plot's dashed reference band). $$PO=\frac{1.0678-0.7241}{0.7241}\times100\%=47.45\%.$$ $$\zeta=\frac{-\ln(PO/100)}{\sqrt{\pi^2+\ln^2(PO/100)}}=0.2309,\qquad \omega_n=\frac{\pi}{t_p\sqrt{1-\zeta^2}}=3.830\ \text{rad/s}.$$ $$\boxed{G_{m2}(s)=\frac{0.7241\times3.830^2}{s^2+2(0.2309)(3.830)s+3.830^2} =\frac{10.62}{s^2+1.769s+14.67}}.$$
  3. Part 3) — from $|G_{cl}(j\omega)|$, $G_{m3}(s)$. The exact frequency response reproduces Figure Q4.2: DC magnitude $0.7243$, resonant peak $M_r=1.9769$ at $\omega_r=4.3866$ rad/s. Solving the standard pair $M_r=\dfrac{1}{2\zeta\sqrt{1-\zeta^2}}$, $\omega_r=\omega_n\sqrt{1-2\zeta^2}$ simultaneously: $$\zeta=0.2621,\qquad \omega_n=4.723\ \text{rad/s}.$$ $$\boxed{G_{m3}(s)=\frac{0.7241\times4.723^2}{s^2+2(0.2621)(4.723)s+4.723^2} =\frac{16.15}{s^2+2.476s+22.31}}.$$
  4. Part 4) — comparison. Predicted transient specs from each model:
    Model$\zeta$$\omega_n$ (rad/s)Predicted POPredicted $T_s$(2%)
    $G_{m1}$ (exact poles)0.1474.52362.7%6.02 s
    $G_{m2}$ (step data)0.2313.83047.5% (exact, by construction)4.52 s
    $G_{m3}$ (freq. data)0.2624.72342.6%3.23 s
    $G_{m1}$, built from the exact dominant poles alone, OVER-predicts overshoot (62.7% vs. the true 47.5%) because it ignores the damping contribution of the third, non-dominant real pole at $-5.67$: even at an 8.5:1 separation the real pole is not entirely negligible for a precise PO estimate, only for the general shape/settling behaviour. $G_{m2}$ is exact for PO/peak-time by construction (it was fit to reproduce them) but its $\zeta,\omega_n$ still differ from the true pole location. $G_{m3}$, read from the resonant peak, is the closest of the three to the exact pole pair in $\omega_n$ but under-estimates $\zeta$. $G_{m2}$ is the most practically useful model (it reproduces the actual time-domain transient exactly, which is usually the design-relevant quantity), while $G_{m1}$ is the most theoretically correct (built from exact poles) but the least accurate for overshoot specifically.
Final results — Question 4
ItemResult
$G_{m1}(s)$ (from poles)$14.82/(s^2+1.33s+20.46)$
$G_{m2}(s)$ (from step response)$10.62/(s^2+1.769s+14.67)$
$G_{m3}(s)$ (from $|G_{cl}(j\omega)|$)$16.15/(s^2+2.476s+22.31)$
Most accurate for overshoot$G_{m2}$ (fit directly to the true transient)