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04-BS-1 · Undated paper

Question 2 of 7: Critically-Damped Forced Oscillator (Initial Value Problem)

Nivaar worked solution (AI-drafted; not reviewed by a licensed engineer)

Notes on this paper

National Exams — 04-BS-1 Mathematics. Three-hour, closed-book exam. Format: seven questions offered; Question 1 is split (a) 7, (b) 7, (c) 6 marks, Questions 2–7 are 20 marks each; any five questions constitute a complete paper and only the first five appearing in the answer book are marked. All seven are solved below for completeness.

Reference texts: Kreyszig, Advanced Engineering Mathematics (10th ed., Wiley) — ODEs, Laplace transforms and Fourier series for periodic forcing, tangent lines to surface intersections, line/surface integrals; Stewart, Calculus: Early Transcendentals (9th ed., Cengage) — spherical coordinates and volumes, vector line integrals.

Question 2: Critically-Damped Forced Oscillator (Initial Value Problem) (20 marks)

Question text not reproduced: the examination questions are © Engineers and Geoscientists BC. Open the official past paper (linked at the top of this page) to read the question, then follow the worked solution below.

Given. A critically damped, constant-coefficient second-order ODE with cosine forcing and initial conditions $y(0)=2$, $y'(0)=0$.

Find. $y(t)$.

Approach. Solve the repeated-root homogeneous equation, find a particular solution by undetermined coefficients, then fix the two constants from the initial conditions.

  1. Homogeneous solution. $r^2+4r+4=(r+2)^2=0\Rightarrow r=-2$ (double root): $$y_h=(C_1+C_2t)e^{-2t}.$$
  2. Particular solution. Try $y_p=A\cos2t+B\sin2t$. Substituting, $y_p''+4y_p'+4y_p=8B\cos2t-8A\sin2t$. Matching to $\cos2t$ gives $8B=1$, $-8A=0$, so $A=0,\ B=\tfrac18$: $$y_p=\tfrac18\sin2t.$$
  3. General solution and initial conditions. $$y(t)=(C_1+C_2t)e^{-2t}+\tfrac18\sin2t.$$ $y(0)=C_1=2$. Differentiating, $y'(t)=C_2e^{-2t}-2(C_1+C_2t)e^{-2t}+\tfrac14\cos2t$, so $y'(0)=C_2-2C_1+\tfrac14=0\Rightarrow C_2=2(2)-\tfrac14=\tfrac{15}{4}$.

$$y(t)=\boxed{\left(2+\tfrac{15}{4}t\right)e^{-2t}+\tfrac18\sin2t}$$

QuantityResult
Homogeneous roots$r=-2$ (double)
$C_1,\ C_2$$2,\ 15/4$
$y(t)$$(2+\tfrac{15}{4}t)e^{-2t}+\tfrac18\sin2t$