Question 4 of 5: Friedel–Crafts Acylation Mechanism & Alkene Stability
Nivaar worked solution (AI-drafted; not reviewed by a licensed engineer)
Notes on this paper
National Exam 04-BS-12, Organic Chemistry — May 2014. 3 hours, closed-book
examination; no calculator allowed. Answer ALL FIVE problems; each problem is of equal value
(20 points), and the lettered/numbered sub-parts of a given problem may be treated
independently.
a meta (1,3) relationship, matching the drawing
convention used two questions later for Question 3(a)(i)'s explicitly-labelled meta compound. Solved below as meta; this changes the product from phthalic acid (ortho) to isophthalic acid
(meta).
a) Friedel–Crafts acylation mechanism. AlCl3 activates acetyl
chloride toward ionization, generating a resonance-stabilized acylium ion that then attacks the
aromatic ring:
Acylium ion formation. AlCl3 (a strong Lewis acid) coordinates the
chlorine of acetyl chloride, and the C–Cl bond heterolyzes:
$$\mathrm{CH_3COCl + AlCl_3 \longrightarrow CH_3CO^+ + AlCl_4^-}$$
Electrophilic attack on the ring — the Wheland (arenium) intermediate.
The acylium ion's electrophilic carbon is attacked by a pair of π electrons from the aromatic
ring, breaking aromaticity and generating a resonance-stabilized cyclohexadienyl cation with the
positive charge delocalized over three ring positions.
Deprotonation restores aromaticity. AlCl4- removes the
proton from the sp3 ring carbon that bears the new acetyl group, regenerating the
aromatic ring and AlCl3:
$$\mathrm{C_6H_6 + CH_3CO^+ \longrightarrow [\text{arenium}]^+ \xrightarrow{-H^+} C_6H_5COCH_3}$$
Overall: $$\mathrm{C_6H_6 + CH_3COCl \xrightarrow{AlCl_3} C_6H_5COCH_3 + HCl}$$ (verified
atom-balanced, C8H9OCl on both sides). Product: acetophenone. Unlike
Friedel–Crafts alkylation, the acylium ion cannot rearrange (no hydride/alkyl shifts) and
the ring is deactivated after one acylation, so the reaction cleanly stops at mono-substitution.
b) Alkene stability by substitution count. All three are C8H16
constitutional isomers of dimethylhexene; the ranking depends on how many carbon substituents sit
directly on the two sp2 (alkene) carbons themselves — a branch one bond
away (allylic) does not count.
Fig. Q4b — the three hexene isomers (increasing stability left→right)
4,5-Dimethyl-2-hexene: disubstituted. The double bond is at C2=C3; the methyl
branches sit at C4 and C5, which are not on the alkene carbons (C4 is allylic to C3, one
bond removed). The alkene itself carries only its ordinary chain substituents (C1 on one side, C4
chain on the other) — a plain disubstituted alkene, same substitution level as a simple
internal alkene. Least stable.
3,4-Dimethyl-2-hexene: trisubstituted. The double bond is at C2=C3; C3 (an
alkene carbon) carries a directly-attached methyl branch in addition to the C4 chain
— three total alkyl substituents across the two alkene carbons (C1 on C2; methyl branch and
C4-chain on C3). Intermediate stability.
2,3-Dimethyl-2-hexene: tetrasubstituted. Both C2 and C3 carry a
directly-attached methyl branch as well as their chain continuations — every position on
both alkene carbons is a carbon substituent, none is H. Most stable (maximum
hyperconjugative stabilization from four alkyl groups).