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04-BS-12 · May 2014

Question 5 of 5: Constitutional Isomers of C6H14 & Reaction Classification

Nivaar worked solution (AI-drafted; not reviewed by a licensed engineer)

Notes on this paper

National Exam 04-BS-12, Organic Chemistry — May 2014. 3 hours, closed-book examination; no calculator allowed. Answer ALL FIVE problems; each problem is of equal value (20 points), and the lettered/numbered sub-parts of a given problem may be treated independently.

Reference texts: McMurry, Organic Chemistry, 9th ed. (alkane/carbon classification, alkene stability and E/Z isomerism, electrophilic addition, electrophilic aromatic substitution and benzylic oxidation, Friedel–Crafts acylation, diazonium chemistry, constitutional isomerism).

a meta (1,3) relationship, matching the drawing convention used two questions later for Question 3(a)(i)'s explicitly-labelled meta compound. Solved below as meta; this changes the product from phthalic acid (ortho) to isophthalic acid (meta).

Question 5: Constitutional Isomers of C6H14 & Reaction Classification (20 marks)

Question text not reproduced: the examination questions are © Engineers and Geoscientists BC. Open the official past paper (linked at the top of this page) to read the question, then follow the worked solution below.

a) All five constitutional isomers of C6H14. Fixing the longest chain first (6, then 5, then 4 carbons) and placing all remaining branches on each length systematically finds exactly five distinct connectivities (no sixth arrangement exists): the straight chain, two singly-branched pentane-backbone isomers, and two doubly-branched butane-backbone isomers.

hexane2-methylpentane3-methylpentane2,2-dimethylbutane2,3-dimethylbutane
Fig. Q5a — all five constitutional isomers of C6H14
IsomerCondensed structural formula
hexaneCH3CH2CH2CH2CH2CH3
2-methylpentaneCH3CH(CH3)CH2CH2CH3
3-methylpentaneCH3CH2CH(CH3)CH2CH3
2,2-dimethylbutaneCH3C(CH3)2CH2CH3
2,3-dimethylbutaneCH3CH(CH3)CH(CH3)CH3

b) Reaction classification.

(i) CH3CH=CH2 + H2 → CH3CH2CH3: two new atoms (H, H) are added across the double bond and nothing leaves the molecule — this is an addition reaction (catalytic hydrogenation).

(ii) CH3CH2CH2OH $\xrightarrow{H_2SO_4}$ CH3CH=CH2 + H2O: a small molecule (H2O) is removed from the substrate and a new π bond forms in its place — this is an elimination reaction (acid-catalyzed E1 dehydration).

PartClassification
(i)addition (hydrogenation)
(ii)elimination (acid-catalyzed dehydration)
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