Question 10 of 13: Markovnikov vs. Anti-Markovnikov HBr Addition: Rearrangement vs. Radical Mechanism
Nivaar worked solution (AI-drafted; not reviewed by a licensed engineer)
Notes on this paper
National Exam 04-BS-12, Organic Chemistry — December 2016. 3 hours, closed-book
examination (no non-communicating calculator restriction beyond the standard aid sheet, 8.5×11",
hand-written both sides). Ten questions constitute a complete exam paper (only the first 10 questions
as they appear in the answer book are marked, each of equal value) — the source paper in fact
prints thirteen questions; all thirteen are answered in full below.
Reference texts: McMurry, Organic Chemistry, 9th ed. (acid/base theory of
drugs, SN1/SN2 stereochemistry, carbocation rearrangements, alkyne synthesis via
acetylide alkylation, IR/NMR structure elucidation, electrophilic aromatic substitution and synthesis
design, amino-acid pKa); Clayden, Organic Chemistry, 2nd ed. (amide resonance and β-lactam
reactivity, radical vs. ionic HBr addition mechanisms); a standard biomaterials reference for the
poly(ester amide) drug-delivery polymer chemistry of Question 13 (Katsarava-type AABB poly(ester
amide)s built from diacids, diols, and protected diamino acids).
Question 10: Markovnikov vs. Anti-Markovnikov HBr Addition: Rearrangement vs. Radical Mechanism
Approach. The two conditions trigger completely different mechanisms — ionic
(Markovnikov, via a carbocation) without peroxide, and radical (anti-Markovnikov, via the
peroxide-initiated chain) with peroxide — and only the cationic intermediate is prone to
rearrangement.
3,3-dimethyl-1-butene
HBr alone — ionic (Markovnikov) addition through a secondary cation that
rearranges. H+ (from HBr) adds first to the terminal, less-substituted alkene
carbon (Markovnikov protonation), generating the more stable of the two possible carbocations: a
secondary cation at C2, immediately adjacent to a fully substituted (no H) neopentyl-type
carbon (C3, bearing three methyls).
secondary cation (C2) — adjacent to a quaternary-type carbon
This secondary cation sits directly next to a carbon bearing a methyl group that can migrate with its
bonding electron pair (a 1,2-methyl shift). Migration converts the secondary C2 cation into a
tertiary cation at C3 — a substantially more stable carbocation — so the
rearrangement is strongly downhill and occurs essentially instantaneously, faster than
Br− can capture the original secondary cation. Br− then captures the
rearranged, more stable tertiary cation, giving the rearranged, more highly substituted bromide as the
major product.
HBr + peroxide — radical chain (anti-Markovnikov) addition; no cation, no
rearrangement. Peroxide initiates a radical chain: RO• abstracts the H of H–Br to
generate Br•, which then adds to the alkene first — and it adds to the
less substituted (terminal) carbon, because that leaves the unpaired electron on the
more substituted, more stable secondary carbon radical (the same substitution-stability
preference as cations, but here it is a radical, not a cation, and it does not undergo skeletal
1,2-shifts the way a carbocation does). This secondary radical then abstracts an H atom from another
H–Br to give the product and propagate the chain, with Br ending up on the terminal carbon and no
rearrangement possible at any point.