Question 13 of 13: Identifying the Four Monomers of a Poly(ester amide) Drug-Delivery Copolymer
Nivaar worked solution (AI-drafted; not reviewed by a licensed engineer)
Notes on this paper
National Exam 04-BS-12, Organic Chemistry — December 2016. 3 hours, closed-book
examination (no non-communicating calculator restriction beyond the standard aid sheet, 8.5×11",
hand-written both sides). Ten questions constitute a complete exam paper (only the first 10 questions
as they appear in the answer book are marked, each of equal value) — the source paper in fact
prints thirteen questions; all thirteen are answered in full below.
Reference texts: McMurry, Organic Chemistry, 9th ed. (acid/base theory of
drugs, SN1/SN2 stereochemistry, carbocation rearrangements, alkyne synthesis via
acetylide alkylation, IR/NMR structure elucidation, electrophilic aromatic substitution and synthesis
design, amino-acid pKa); Clayden, Organic Chemistry, 2nd ed. (amide resonance and β-lactam
reactivity, radical vs. ionic HBr addition mechanisms); a standard biomaterials reference for the
poly(ester amide) drug-delivery polymer chemistry of Question 13 (Katsarava-type AABB poly(ester
amide)s built from diacids, diols, and protected diamino acids).
Question 13: Identifying the Four Monomers of a Poly(ester amide) Drug-Delivery Copolymer
[Figure not reproduced: poly(ester amide) A — one repeat unit, redrawn from the source structure. See the official exam paper.]
Approach. Walk the backbone bond-by-bond and classify every linkage as an amide
(C(=O)–N) or an ester (C(=O)–O), then group the atoms between consecutive amide/ester bonds
into the monomer that must have supplied them.
A four-carbon diacid links two different amine-bearing fragments. Reading from the
left, –C(=O)CH2CH2C(=O)– is flanked by amide bonds on both sides
(this exact fragment recurs twice in the repeat unit) — this is succinic acid,
HOOC–CH2CH2–COOH, condensed twice as a simple diacid monomer (no
stereocentre, not an amino acid).
succinic acid
An isobutyl-bearing amino-acid residue is esterified on both sides to a two-carbon diol.
The next fragment, –NH–CH(CH2CH(CH3)2)–C(=O)–O–CH2CH2–O–C(=O)–CH(CH2CH(CH3)2)–NH–,
is symmetric: two identical α-amino-acid residues, each bearing the isobutyl side chain
–CH2CH(CH3)2 diagnostic of leucine, each
contributing its free α-amine to an amide bond (to the succinic acid on either side) and its
α-carboxyl to an ester bond with a common central diol — ethylene
glycol, HO–CH2CH2–OH.
leucine
ethylene glycol
A four-methylene chain links directly into a benzyl-ester-capped stereocentre — both
belong to a single lysine residue. The final segment,
–NH–CH2CH2CH2CH2–CH(NH–)–C(=O)–O–CH2C6H5,
is one monomer, not two: the (CH2)4 chain is not a separate diamine
— it terminates directly in the same stereocentre that carries the benzyl ester, which is exactly
the connectivity of lysine used "in reverse": its side-chain (ε-) amine forms
the amide bond back to the preceding succinic acid unit, its α-amine continues the backbone
forward to the next repeat unit (via the amide bond at the chain's far right), and its α-carboxyl
is capped as a permanent benzyl ester — a protecting/pendant group rather than a
backbone linkage. This is the monomer actually used industrially as "lysine benzyl ester" in real
AABB-type poly(ester amide) biomaterials, precisely because both of lysine's amines are then free to
build the backbone while the carboxyl is safely capped, preventing unwanted branching/crosslinking.
lysine benzyl ester
Monomer
Role
Amino acid?
Succinic acid
simple diacid linker (2 amide bonds each occurrence)
no
Leucine
α-amine → amide to succinate; α-COOH → ester to ethylene glycol
yes
Ethylene glycol
simple diol linker (2 ester bonds)
no
Lysine (as its benzyl ester)
ε-amine → amide to succinate; α-amine → amide to next repeat; α-COOH capped as benzyl ester