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04-BS-12 · December 2016

Question 13 of 13: Identifying the Four Monomers of a Poly(ester amide) Drug-Delivery Copolymer

Nivaar worked solution (AI-drafted; not reviewed by a licensed engineer)

Notes on this paper

National Exam 04-BS-12, Organic Chemistry — December 2016. 3 hours, closed-book examination (no non-communicating calculator restriction beyond the standard aid sheet, 8.5×11", hand-written both sides). Ten questions constitute a complete exam paper (only the first 10 questions as they appear in the answer book are marked, each of equal value) — the source paper in fact prints thirteen questions; all thirteen are answered in full below.

Reference texts: McMurry, Organic Chemistry, 9th ed. (acid/base theory of drugs, SN1/SN2 stereochemistry, carbocation rearrangements, alkyne synthesis via acetylide alkylation, IR/NMR structure elucidation, electrophilic aromatic substitution and synthesis design, amino-acid pKa); Clayden, Organic Chemistry, 2nd ed. (amide resonance and β-lactam reactivity, radical vs. ionic HBr addition mechanisms); a standard biomaterials reference for the poly(ester amide) drug-delivery polymer chemistry of Question 13 (Katsarava-type AABB poly(ester amide)s built from diacids, diols, and protected diamino acids).

Question 13: Identifying the Four Monomers of a Poly(ester amide) Drug-Delivery Copolymer

Question text not reproduced: the examination questions are © Engineers and Geoscientists BC. Open the official past paper (linked at the top of this page) to read the question, then follow the worked solution below.

[Figure not reproduced: poly(ester amide) A — one repeat unit, redrawn from the source structure. See the official exam paper.]

Approach. Walk the backbone bond-by-bond and classify every linkage as an amide (C(=O)–N) or an ester (C(=O)–O), then group the atoms between consecutive amide/ester bonds into the monomer that must have supplied them.

  1. A four-carbon diacid links two different amine-bearing fragments. Reading from the left, –C(=O)CH2CH2C(=O)– is flanked by amide bonds on both sides (this exact fragment recurs twice in the repeat unit) — this is succinic acid, HOOC–CH2CH2–COOH, condensed twice as a simple diacid monomer (no stereocentre, not an amino acid).
    succinic acid
  2. An isobutyl-bearing amino-acid residue is esterified on both sides to a two-carbon diol. The next fragment, –NH–CH(CH2CH(CH3)2)–C(=O)–O–CH2CH2–O–C(=O)–CH(CH2CH(CH3)2)–NH–, is symmetric: two identical α-amino-acid residues, each bearing the isobutyl side chain –CH2CH(CH3)2 diagnostic of leucine, each contributing its free α-amine to an amide bond (to the succinic acid on either side) and its α-carboxyl to an ester bond with a common central diol — ethylene glycol, HO–CH2CH2–OH.
    leucine
    ethylene glycol
  3. A four-methylene chain links directly into a benzyl-ester-capped stereocentre — both belong to a single lysine residue. The final segment, –NH–CH2CH2CH2CH2–CH(NH–)–C(=O)–O–CH2C6H5, is one monomer, not two: the (CH2)4 chain is not a separate diamine — it terminates directly in the same stereocentre that carries the benzyl ester, which is exactly the connectivity of lysine used "in reverse": its side-chain (ε-) amine forms the amide bond back to the preceding succinic acid unit, its α-amine continues the backbone forward to the next repeat unit (via the amide bond at the chain's far right), and its α-carboxyl is capped as a permanent benzyl ester — a protecting/pendant group rather than a backbone linkage. This is the monomer actually used industrially as "lysine benzyl ester" in real AABB-type poly(ester amide) biomaterials, precisely because both of lysine's amines are then free to build the backbone while the carboxyl is safely capped, preventing unwanted branching/crosslinking.
    lysine benzyl ester
MonomerRoleAmino acid?
Succinic acidsimple diacid linker (2 amide bonds each occurrence)no
Leucineα-amine → amide to succinate; α-COOH → ester to ethylene glycolyes
Ethylene glycolsimple diol linker (2 ester bonds)no
Lysine (as its benzyl ester)ε-amine → amide to succinate; α-amine → amide to next repeat; α-COOH capped as benzyl esteryes (derivative)

The two amino acids are leucine and lysine.

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