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04-BS-12 · May 2016

Question 11 of 13: Total Synthesis of Proparacaine

Nivaar worked solution (AI-drafted; not reviewed by a licensed engineer)

Notes on this paper

National Exam 04-BS-12, Organic Chemistry — May 2016. 3 hours, closed-book examination; one aid sheet (8.5×11", both sides) and a Casio or Sharp calculator permitted. Ten questions constitute a complete exam paper (only the first 10 questions as they appear in the answer book are marked, each of equal value) — the source paper in fact prints thirteen questions; all thirteen are answered in full below.

Reference texts: McMurry, Organic Chemistry, 9th ed. (functional-group spectroscopy, amino-acid ionisation, conjugate addition, electrophilic/nucleophilic aromatic substitution, SN1/SN2 and epoxide-opening regiochemistry, stereochemistry and meso compounds, cyclohexane/bridged-ring conformational analysis, α-halogenation, and multi-step synthesis design); Atkins, Physical Chemistry, 11th ed. (Hughes–Ingold solvent-polarity rules).

Question 11: Total Synthesis of Proparacaine

Question text not reproduced: the examination questions are © Engineers and Geoscientists BC. Open the official past paper (linked at the top of this page) to read the question, then follow the worked solution below.

Target check. Proparacaine (proxymetacaine) is 2-(diethylamino)ethyl 3-amino-4-propoxybenzoate — a benzoate ester bearing NH2 meta to the ester and n-PrO para to the ester (ortho to the NH2). Working forward from 4-hydroxybenzoic acid (CO2H at C1, OH at C4, para) must therefore install NO2 (later reduced to NH2) at C3, and convert the C4–OH into the C4–OPr ether — exactly the two ring transformations available from steps 1→2 and 2→3.

  1. 1 → 2: nitration (HNO3) — the –OH directs, and both groups agree.
    1: 4-hydroxybenzoic acid
    2: 3-nitro-4-hydroxybenzoic acid
    –OH is a strong, activating ortho/para director; –CO2H is a deactivating meta director. On this para-disubstituted ring the position ortho to OH (C3, or equivalently C5 by the ring's own symmetry) is simultaneously meta to CO2H — the two groups' preferences reinforce rather than compete, giving one clean, dominant product. Mechanism: HNO3/H+ generates NO2+, which attacks C3; the resulting arenium (Wheland) intermediate is stabilised by direct oxygen lone-pair donation from the OH at C4 into the ring, and loss of H+ restores aromaticity, giving 3-nitro-4-hydroxybenzoic acid (2).
  2. 2 → 3: Williamson ether synthesis (base, n-PrCl) — alkylates the phenol only.
    3: 3-nitro-4-propoxybenzoic acid
    A mild base deprotonates the acidic phenolic –OH (pKa≈10) to the phenoxide, which performs a clean SN2 displacement of chloride from n-PrCl. Neither the carboxylic acid nor the nitro group is affected under these conditions, giving 3-nitro-4-propoxybenzoic acid (3).
  3. 3 → 4: SOCl2 — acid to acid chloride.
    4: the acid chloride
    Standard nucleophilic acyl substitution: the carboxylic acid oxygen attacks sulfur, forming a chlorosulfite leaving group in situ; chloride then displaces it at the carbonyl carbon, expelling SO2 and HCl (irreversible), giving acid chloride 4.
  4. Ethylene oxide + Et2NH → 5: uncatalysed SN2 epoxide opening.
    ethylene oxide
    diethylamine
    5: 2-(diethylamino)ethanol
    Diethylamine is nucleophilic enough to open the strained epoxide directly (ring-strain release is the driving force), attacking either (equivalent) carbon by backside SN2, giving 2-(diethylamino)ethanol (5) with no acid catalyst needed.
  5. 5 + 4 → 6: ester formation (nucleophilic acyl substitution).
    6: the nitro ester
    The alcohol oxygen of 5 attacks the electrophilic carbonyl carbon of acid chloride 4, forming a tetrahedral intermediate that collapses by expelling chloride, giving ester 6, the nitro-ester.
  6. 6 → proparacaine: H2/Pd/C, chemoselective nitro reduction.
    proparacaine
    Heterogeneous catalytic hydrogenation reduces aromatic nitro groups stepwise on the catalyst surface (ArNO2→ArNO→ArNHOH→ArNH2+H2O), one of the most facile transformations available under H2/Pd — far faster than any competing reduction of the ester carbonyl or the tertiary amine (both of which are untouched under these mild conditions; reducing an ester would require a much harsher hydride such as LiAlH4). This gives proparacaine directly.