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04-BS-7 · December 2013

Question 3 of 13: Sliding Friction Required to Hold a Concrete Dam

Nivaar worked solution (AI-drafted; not reviewed by a licensed engineer)

Notes on this paper

04-BS-7 Mechanics of Fluids — National Examination, 2013-Dec. Three (3) hours duration, closed book. Section A (Calculative, 9 questions, do 7) and Section B (Analytical, 4 questions, do 3); every question is answered below regardless of the exam's "do N of M" instruction, so the set is a complete study resource.

Reference texts: Crowe, C.T., Elger, D.F. & Roberson, J.A., Engineering Fluid Mechanics; Douglas, J.F., Gasiorek, J.M., Swaffield, J.A. & Jack, L.B., Fluid Mechanics; White, F.M., Fluid Mechanics.

Check — assumptions used across this paper:
  • Air density is taken from the paper's own Constants table at the temperature each question states: 1.19 kg/m³ at 20°C (Q5's wind, Q7's inlet air).
  • Q1's touching-rod array is modelled as a repeating square unit cell of four mutually tangent rods (pitch = rod diameter, per the question's own "closely packed" wording), giving a curvilinear-square pore whose perimeter/area ratio drives the capillary rise.
  • Q8's Moody diagram and Q9's drag-coefficient diagram are supplied as attachments. Both are solved via the equations the charts themselves plot: the Colebrook–White equation for Q8 and the Morrison (2013) curve-fit for sphere drag vs. Reynolds number for Q9.

Question 3: Sliding Friction Required to Hold a Concrete Dam (5 marks)

Question text not reproduced: the examination questions are © Engineers and Geoscientists BC. Open the official past paper (linked at the top of this page) to read the question, then follow the worked solution below.

Given.

QuantityValue
Concrete density, ρc2400 kg/m³
Top width2 m
Base width6 m
Dam height5 m
Water depth, h4 m (vertical upstream face; no uplift)
waterbase = 6.0 mtop = 2.0 mH=5.0 mh=4.0 mDam cross-section (unit length)
Trapezoidal dam cross-section, unit length into the page; vertical upstream face carries the full hydrostatic thrust horizontally.

Find. Minimum coefficient of friction μ between the dam base and its foundation.

Approach. Because the upstream face is vertical, the hydrostatic resultant is purely horizontal; compute it and compare against the friction resistance available from the dam's own self-weight (no uplift, so the full weight bears on the base).

  1. Hydrostatic thrust. Per unit length, $F=\tfrac12\rho g h^{2}=\tfrac12(1000)(9.81)(4)^{2}=\boxed{78{,}480\ \text{N} = 78.48\ \text{kN}}$.
  2. Dam weight. Trapezoidal cross-sectional area $A=\tfrac12(2+6)(5)=20\ \text{m}^2$, so $$W = \rho_c g A = 2400\times9.81\times20 = \boxed{470{,}880\ \text{N} = 470.9\ \text{kN}}$$
  3. Minimum friction coefficient. With no uplift the base normal force equals the full weight, so sliding equilibrium ($\mu W = F$) requires $$\mu_{\min} = \frac{F}{W} = \frac{78{,}480}{470{,}880} = \boxed{0.167}$$
QuantityValue
Hydrostatic thrust, F78.48 kN
Dam self-weight, W470.9 kN
Minimum friction coefficient, μmin0.167