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04-BS-7 · December 2018

Question 2 of 13: Equilibrium Level in a Discharging Tank — Gasoline vs Lubricating Oil

Nivaar worked solution (AI-drafted; not reviewed by a licensed engineer)

Notes on this paper

Reference texts: White, F.M., Fluid Mechanics (8th ed.) — fluid statics and hydrostatic force on plane/curved surfaces incl. gravity-dam stability (Ch. 2), buoyancy and Archimedes' principle (Ch. 2), orifice/nozzle discharge and jet momentum forces (Ch. 3, 6), viscous flow in ducts and the Moody chart (Ch. 6), open-channel flow and the hydraulic jump (Ch. 10), drag and stability of bluff bodies (Ch. 7), turbomachinery and jet propulsion (Ch. 11).

Question 2: Equilibrium Level in a Discharging Tank — Gasoline vs Lubricating Oil (5 marks)

Question text not reproduced: the examination questions are © Engineers and Geoscientists BC. Open the official past paper (linked at the top of this page) to read the question, then follow the worked solution below.

Given.

QuantityValue
Tank diameter / height300 mm / 500 mm
Inflow rate, $Q_{in}$0.20 L/s
Orifice diameter, $d_o$10 mm
$C_d$ gasoline / oil0.90 / 0.75
h (equilibrium level) Q_in = 0.20 L/s orifice, d=10 mm
Tank fills until the orifice outflow $C_dA_o\sqrt{2gh}$ balances the constant inflow $Q_{in}$; the balance level is the equilibrium level.

Find. The equilibrium level $h$ for gasoline and for oil; compare, and discuss the effect of raising the temperature to 40°C.

Approach. At equilibrium the orifice discharge (Torricelli's law scaled by $C_d$) exactly balances the constant inflow, $Q_{in}=C_dA_o\sqrt{2gh}$; solve for $h$ for each fluid's $C_d$ and compare against the 500 mm tank height.

  1. Part (a) — gasoline equilibrium level. Orifice area $A_o=\tfrac{\pi}{4}(0.010)^2=7.854\times10^{-5}\ \text{m}^2$. Solving $Q_{in}=C_dA_o\sqrt{2gh}$ for $h$, $$h_{gas}=\frac{1}{2g}\left(\frac{Q_{in}}{C_dA_o}\right)^2=\frac{1}{2(9.81)}\left(\frac{2.0\times10^{-4}}{(0.90)(7.854\times10^{-5})}\right)^2=\boxed{0.408\ \text{m} = 408\ \text{mm}}$$ which is below the 500 mm rim, so gasoline reaches a genuine steady equilibrium.
  2. Part (b) — oil equilibrium level. With $C_d=0.75$, $$h_{oil}=\frac{1}{2(9.81)}\left(\frac{2.0\times10^{-4}}{(0.75)(7.854\times10^{-5})}\right)^2=\boxed{0.588\ \text{m} = 588\ \text{mm}}$$ which EXCEEDS the 500 mm tank height. Checking the outflow at the rim itself confirms this: at $h=0.500$ m the oil orifice can only pass $C_dA_o\sqrt{2gh}=0.75(7.854\times10^{-5})\sqrt{2(9.81)(0.5)}=1.845\times10^{-4}\ \text{m}^3/\text{s}=0.1845\ \text{L/s}$, which is less than the 0.20 L/s inflow, so $\boxed{\text{oil never reaches equilibrium — the tank overflows}}$.
  3. Part (c) — comparison. Gasoline settles to a stable 408 mm level, comfortably inside the tank, whereas oil's lower discharge coefficient (0.75 vs 0.90, a consequence of its much higher viscosity giving a lower orifice Reynolds number and more velocity-profile contraction/friction loss at the vena contracta) means even a completely full 500 mm tank cannot pass the required 0.20 L/s — the oil case overflows continuously rather than settling.
  4. Part (d) — effect of raising the temperature to 40°C. Both fluids' viscosities fall with rising temperature (SAE 30 oil far more steeply than gasoline, per the Absolute-Viscosity attachment), which raises the orifice Reynolds number and pushes $C_d$ upward toward its high-Re asymptote for both fluids — more so for the oil, whose $C_d$ is furthest from that asymptote at 20°C. The parameter that changes is therefore $C_d$ itself (via viscosity/Reynolds number), not the driving head relation. Quantitatively, the oil would need $C_d$ to rise only to $$C_{d,need}=\frac{Q_{in}}{A_o\sqrt{2gH_{tank}}}=\frac{2.0\times10^{-4}}{(7.854\times10^{-5})\sqrt{2(9.81)(0.5)}}=\boxed{0.813}$$ (an 8.4% rise from 0.75) to just avoid overflowing at the full 500 mm level, which is a plausible outcome of the substantial viscosity drop SAE 30 oil undergoes between 20°C and 40°C; gasoline's $C_d$ is already close to its high-Re ceiling, so its equilibrium level would drop only slightly below 408 mm.
QuantityValue
Gasoline equilibrium level0.408 m (408 mm)
Oil equilibrium level (unconstrained)0.588 m — exceeds tank, overflows
Oil outflow at full tank (h=0.5 m)0.1845 L/s < 0.20 L/s inflow
Cd oil would need at 40°C to just avoid overflow0.813