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23-Chem-A5 Chemical Plant Design and Economics · Undated paper

Question 1 of 6: Vinyl-Chloride Reaction-Path Selection by Economic Potential

Nivaar worked solution (AI-drafted; not reviewed by a licensed engineer)

Notes on this paper

National Exams / EGBC — May 2019 — 16-Chem-A5 Chemical Plant Design and Economics. Three-hour closed-book examination; one aid sheet (both sides) and an approved calculator are permitted. Six questions are printed and any five constitute a complete paper (each worth 20 marks); all six are solved below for completeness. Three questions carry numbers (Q1 route economics, Q3 production cost, Q4 depreciation); the other three (Q2 supercritical extraction, Q5 the design hierarchy intrinsic to a chemical process, Q6 VOC-abatement P&ID) are answered as structured description with a supporting diagram where the paper asks for one.

Reference texts: M. S. Peters, K. D. Timmerhaus & R. E. West, Plant Design and Economics for Chemical Engineers (5th ed., McGraw-Hill) — total-product-cost anatomy, straight-line depreciation, after-tax cash flow, profitability; R. Turton, R. C. Bailie, W. B. Whiting & J. A. Shaeiwitz, Analysis, Synthesis, and Design of Chemical Processes (4th ed., Prentice Hall) — the economic-potential screen, reaction-path selection and the process flow diagram; J. M. Douglas, Conceptual Design of Chemical Processes (McGraw-Hill) — the level-2 economic-potential hierarchy and the balanced vinyl-chloride process; G. Towler & R. Sinnott, Chemical Engineering Design (Coulson & Richardson Vol. 6, 2nd ed.) — utilities, VOC control and product recovery; R. H. Perry & D. W. Green, Perry’s Chemical Engineers’ Handbook (9th ed.) — supercritical-fluid extraction. Depreciation is worked in the U.S. MACRS/straight-line framework the question specifies; the Canadian CCA declining-balance analogue is noted where relevant.

Question 1: Vinyl-Chloride Reaction-Path Selection by Economic Potential (20 marks)

Question text not reproduced: the examination questions are © Engineers and Geoscientists BC. Open the official past paper (linked at the top of this page) to read the question, then follow the worked solution below.

Given. Molar masses and market values of the materials, on a per-kmol basis:

MaterialMolar mass (kg/kmol)Value ($/kg)Value ($/kmol)
Acetylene C₂H₂261.00$26.00
Chlorine Cl₂710.23$16.33
Ethylene C₂H₄280.53$14.84
Hydrogen chloride HCl360.39$14.04
Vinyl chloride C₂H₃Cl620.46$28.52

Find. (a) the economically preferred path on a raw-material/by-product basis; (b) whether the combined ethylene + chlorine process whose only by-product is water is economically attractive (the flowsheet is devised on the way to answering it).

DirectChlorinationOxy-chlorinationEDCPyrolysisVCMSeparationC2H4Cl2C2H41/2 O2 (air)EDCEDC + H2OVCM + HClVCM productHCl recycle
Balanced vinyl-chloride process (answer to part b): direct chlorination and oxychlorination both feed a shared EDC pyrolysis furnace, and the HCl liberated in cracking is recycled to the oxychlorination reactor — overall $2\,\mathrm{C_2H_4} + \mathrm{Cl_2} + \tfrac12\mathrm{O_2} \rightarrow 2\,\mathrm{C_2H_3Cl} + \mathrm{H_2O}$, no net HCl.

Approach. Screen each path with the economic potential $\mathrm{EP}=\sum(\text{value of products})-\sum(\text{cost of raw materials})$ per kmol of vinyl chloride (the level-2 Douglas screen); then combine the two ethylene paths so that one path’s HCl feeds the other, eliminating the by-product.

  1. Define the economic potential (gross margin on materials). On a basis of 1 kmol vinyl chloride (VCM), $\mathrm{EP}=\sum \dot m_i v_i\big|_{\text{products}}-\sum \dot m_i v_i\big|_{\text{feeds}}$, where $\dot m_i$ is kg per kmol VCM and $v_i$ the market value. Oxygen is free and water has no value.
  2. Path #1 — acetylene route. $\mathrm{C_2H_2+HCl\rightarrow C_2H_3Cl}$. Feeds cost $26.00+14.04=\$40.04$ and the product is worth $\$28.52$, so $\mathrm{EP_1}=28.52-40.04=\boxed{-\$11.52\ \text{per kmol}}$. Both reactants are purchased and relatively dear (acetylene at $1.00/kg), so this path loses money on materials alone.
  3. Path #2 — direct chlorination with an HCl by-product. Overall $\mathrm{C_2H_4+Cl_2\rightarrow C_2H_3Cl+HCl}$. Feeds cost $14.84+16.33=\$31.17$; the products are VCM plus one mole of saleable HCl, worth $28.52+14.04=\$42.56$. With the by-product credit $\mathrm{EP_2}=42.56-31.17=\boxed{+\$11.39\ \text{per kmol}}$ — but if the HCl cannot be sold it becomes $28.52-31.17=-\$2.65$. The path is attractive only if there is a market for the HCl.
  4. Path #3 — oxychlorination. The two written steps combine (one HCl released in cracking is re-consumed) to the net $\mathrm{C_2H_4+\tfrac12 O_2+HCl\rightarrow C_2H_3Cl+H_2O}$. Feeds cost $14.84+14.04=\$28.88$ (oxygen free) and the product is worth $\$28.52$, so $\mathrm{EP_3}=28.52-28.88=\boxed{-\$0.36\ \text{per kmol}}$ — essentially break-even. It consumes rather than produces HCl.
  5. Answer to (a). On raw-material and by-product economics the ranking is Path #2 $(+\$11.39) >$ Path #3 $(-\$0.36) >$ Path #2 without an HCl market $(-\$2.65) >$ Path #1 $(-\$11.52)$. Path #2 (direct chlorination) makes the most sense — provided the by-product HCl can be sold; the acetylene route is clearly the worst.
  6. Answer to (b) — the balanced process. Path #2 produces one HCl per VCM and Path #3 consumes one HCl per VCM, so running them in a 1:1 ratio through a shared EDC pyrolysis furnace lets the cracking HCl feed the oxychlorination reactor. Adding the two overall reactions cancels HCl entirely: $$2\,\mathrm{C_2H_4}+\mathrm{Cl_2}+\tfrac12\mathrm{O_2}\;\rightarrow\;2\,\mathrm{C_2H_3Cl}+\mathrm{H_2O}$$ This uses only ethylene and chlorine as purchased feeds (oxygen is free) and rejects only water. Feeds for 2 kmol VCM cost $2(14.84)+16.33=\$46.01$ and the product is worth $2(28.52)=\$57.04$, giving $\mathrm{EP_{bal}}=(57.04-46.01)/2=\boxed{+\$5.52\ \text{per kmol}}$.
  7. Answer to (b) — is it economically attractive? Yes. The balanced process returns a positive material margin of $\$5.52$ per kmol of vinyl chloride (about $\$0.089$ per kg of product, or 19% of the product’s $\$28.52$/kmol market value) while rejecting only water, so it carries no by-product disposal burden and needs no merchant outlet. It is worth less than Path #2 if a full-price HCl buyer exists $(+\$11.39)$, but it beats Path #2 with no HCl market $(-\$2.65)$, Path #3 $(-\$0.36)$ and Path #1 $(-\$11.52)$ — and unlike Path #2 its margin does not move with a thin, volatile merchant-HCl price. A positive margin under every HCl market condition, on a feed slate of ethylene and chlorine alone, is exactly why the balanced process is the commercial route. The reservation is that it buys that robustness with two reaction systems instead of one, so the capital charge it must still cover is roughly double Path #2’s; the material margin is a screen, not a profit.
PathNet reactionEP ($/kmol VCM)Comment
#1 acetylene$\mathrm{C_2H_2+HCl}$−$11.52worst; both feeds purchased
#2 chlorination$\mathrm{C_2H_4+Cl_2}$+$11.39 (−$2.65 no HCl sale)best iff HCl sells
#3 oxychlorination$\mathrm{C_2H_4+\tfrac12O_2+HCl}$−$0.36break-even; consumes HCl
Balanced (b)$2\mathrm{C_2H_4+Cl_2+\tfrac12O_2}$+$5.52only by-product is water; market-independent
Check

Two points that decide the arithmetic. First, Path #3’s two printed steps consume 2 kmol HCl and release 1 kmol, so the net charge is 1 kmol HCl per kmol vinyl chloride; costing the printed 2 kmol would make the path look far worse than the break-even it actually is. Second, oxygen and water are correctly carried at zero value, as the page-3 line “There is no cost for oxygen because it is obtained from the atmosphere” instructs. The economic potential counts materials only — no capital, utility or conversion cost — so it is a screening figure: a route that fails it cannot be rescued by good engineering, but a route that passes it still has to earn its capital charge.

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