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23-Chem-A5 Chemical Plant Design and Economics · Undated paper

Question 3 of 6: Production Cost per Kilogram of Total Product

Nivaar worked solution (AI-drafted; not reviewed by a licensed engineer)

Notes on this paper

National Exams / EGBC — May 2019 — 16-Chem-A5 Chemical Plant Design and Economics. Three-hour closed-book examination; one aid sheet (both sides) and an approved calculator are permitted. Six questions are printed and any five constitute a complete paper (each worth 20 marks); all six are solved below for completeness. Three questions carry numbers (Q1 route economics, Q3 production cost, Q4 depreciation); the other three (Q2 supercritical extraction, Q5 the design hierarchy intrinsic to a chemical process, Q6 VOC-abatement P&ID) are answered as structured description with a supporting diagram where the paper asks for one.

Reference texts: M. S. Peters, K. D. Timmerhaus & R. E. West, Plant Design and Economics for Chemical Engineers (5th ed., McGraw-Hill) — total-product-cost anatomy, straight-line depreciation, after-tax cash flow, profitability; R. Turton, R. C. Bailie, W. B. Whiting & J. A. Shaeiwitz, Analysis, Synthesis, and Design of Chemical Processes (4th ed., Prentice Hall) — the economic-potential screen, reaction-path selection and the process flow diagram; J. M. Douglas, Conceptual Design of Chemical Processes (McGraw-Hill) — the level-2 economic-potential hierarchy and the balanced vinyl-chloride process; G. Towler & R. Sinnott, Chemical Engineering Design (Coulson & Richardson Vol. 6, 2nd ed.) — utilities, VOC control and product recovery; R. H. Perry & D. W. Green, Perry’s Chemical Engineers’ Handbook (9th ed.) — supercritical-fluid extraction. Depreciation is worked in the U.S. MACRS/straight-line framework the question specifies; the Canadian CCA declining-balance analogue is noted where relevant.

Question 3: Production Cost per Kilogram of Total Product (20 marks)

Question text not reproduced: the examination questions are © Engineers and Geoscientists BC. Open the official past paper (linked at the top of this page) to read the question, then follow the worked solution below.

Given. The cost-data block, printed at the top of page 4 as the continuation of this question. The reaction-product slate (EDA 74%, PIP 4%, HEP 4%, DETA 8%, AEP 10%, summing to 100%) identifies the chemistry and confirms that the 10,000 t/yr is total product, which is the basis every cost below is quoted on; no individual product yield is needed for this question.

ItemValue
Fixed capital cost, FCI$10.3 million
Interest / return on capital10%/yr
Electricity$3.56\times10^{6}\,\text{J/kg}$ @ $4.17\times10^{-7}\,\text{cents/J}$
Steam (1 atm)18.1 kg/kg @ 0.0113 cents/kg
Cooling water$0.1528\,\text{m}^3/\text{kg}$ @ $3.17\,\text{cents/m}^3$
Operating labour$8.61/hr
Land + land development1.5% + 2.1% of depreciable capital
Raw materials80 cents/kg
Production rate / hours10,000 t/yr; 8000 h/yr (333 days)

Find. The production cost per kilogram of total product.

Check — stated assumptions

The recovered data fix the raw-material, utility and capital charges but omit the number of operators, maintenance, plant overhead, insurance and general expenses. To close the problem we assume (i) four operators are on the payroll continuously; (ii) straight-line depreciation over a 10-year life on the FCI; (iii) the 10% charge is a return on total capital investment (FCI + land + land development). The result is therefore a direct-plus-capital estimate; a full Peters–Timmerhaus total product cost (adding maintenance, supplies, overhead, insurance and general expenses) would be higher. The utility and labour rates are used exactly as printed and are mutually consistent for a paper of this vintage: $4.17\times10^{-7}$ cents/J is $1.50$ cents/kWh, alongside steam at $0.0113$ cents/kg, water at $3.17\ \text{cents/m}^3$ and labour at $8.61/hr. both were checked against the reassembled page and are wrong.)

Approach. Build the cost per kilogram additively — raw materials + utilities + operating labour + depreciation + capital charge — converting each annual figure to a per-kg basis with the 10,000 t/yr (= $10^{7}\,\text{kg/yr}$) output.

  1. Basis. Annual output $=10{,}000\,\text{t/yr}\times1000=10^{7}\,\text{kg/yr}$; operating time 8000 h/yr (the paper’s “333 days” of uninterrupted operation).
  2. Raw materials. Given directly: $c_{\text{RM}}=80\ \text{cents/kg}=\boxed{\$0.800/\text{kg}}$.
  3. Utilities (per kg of product). Electricity $=3.56\times10^{6}\times4.17\times10^{-7}=1.485\ \text{cents}$; steam $=18.1\times0.0113=0.205\ \text{cents}$; water $=0.1528\times3.17=0.484\ \text{cents}$. Total $c_{\text{util}}=2.173\ \text{cents/kg}=\boxed{\$0.02173/\text{kg}}$ — electricity is the largest of the three utilities, but all of them together are small beside the feedstock.
  4. Operating labour. With four operators on the payroll, $C_{\text{lab}}=4\times\$8.61/\text{h}\times8000\,\text{h}=\$275{,}520/\text{yr}$, so per kg $c_{\text{lab}}=275{,}520/10^{7}=\boxed{\$0.02755/\text{kg}}$.
  5. Depreciation (straight line, 10 yr). $D=\dfrac{\$10.3\times10^{6}}{10}=\$1.03\times10^{6}/\text{yr}$, so $c_{D}=1.03\times10^{6}/10^{7}=\boxed{\$0.1030/\text{kg}}$.
  6. Capital charge (10% on TCI). Land $=0.015(10.3\text{M})=\$0.1545\text{M}$ and land development $=0.021(10.3\text{M})=\$0.2163\text{M}$, so $\text{TCI}=10.3+0.1545+0.2163=\$10.671\text{M}$. The annual return $0.10\times10.671\text{M}=\$1.067\text{M/yr}$ gives $c_{i}=1.067\times10^{6}/10^{7}=\boxed{\$0.1067/\text{kg}}$.
  7. Total production cost. Summing, $$c=0.800+0.02173+0.02755+0.1030+0.10671=\$1.0590/\text{kg}.$$ Rounding, the production cost is $\boxed{\approx\$1.06\ \text{per kg of total product}}$. The answer is dominated by the 80 cents/kg of raw material; note also that it is insensitive to the operator count — going from four operators to eight would add only 2.8 cents/kg.
Cost component$/kgShare
Raw materials0.80075.5%
Utilities (electricity, steam, water)0.021732.1%
Operating labour (4 operators)0.027552.6%
Depreciation (SL, 10 yr)0.10309.7%
Capital charge (10% of TCI)0.1067110.1%
Production cost$1.06100%