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23-Chem-B5 Pulp and Paper Technology · Undated paper

Question 1 of 6: ECF Bleach Chemistry, Oxygen Delignification & Chlorine Dioxide Generation/Dosing

Nivaar worked solution (AI-drafted; not reviewed by a licensed engineer)

Notes on this paper

National Exam 16-Chem-B5, Pulp and Paper Technology — May 2019. 3 hours, CLOSED BOOK exam (Casio or Sharp approved calculators only). Per the exam notes, any FIVE of the six questions constitute a complete paper (only the first five as they appear in the candidate's answer book are marked); for completeness this solution answers all SIX questions in full. Most parts require an essay-format answer — clarity and organization of the answer are explicitly marked.

Every specific reconstruction is flagged inline at the point it is used; the underlying arithmetic for all boxed numbers.

Reference texts: Smook (rev. Kocurek), Handbook for Pulp & Paper Technologists, 4th ed.; Biermann, Handbook of Pulp and Paper Technology, 2nd ed.; Perry's Chemical Engineers' Handbook, 9th ed. (generic mass/energy-balance and heat-exchanger methods).

Question 1: ECF Bleach Chemistry, Oxygen Delignification & Chlorine Dioxide Generation/Dosing (a)–(c) 10 marks each, (d)–(f) 20 marks each (2 of 3 required)

Question text not reproduced: the examination questions are © Engineers and Geoscientists BC. Open the official past paper (linked at the top of this page) to read the question, then follow the worked solution below.

"solution… from 4°C to 46°C in a heat exchanger that uses D2 stage outlet at 75°C… incoming D2 [D1] Kappa Number = 4.0", plus the separately-legible given list "D1 Stage Kappa Factor = 0.20; Bleach Plant production rate = 1000 ADMT/d; D1 Stage operating consistency = 10% AD; ClO2 Solution Strength = 12.0 g/L" and "temperature of stock from preceding extraction stage is 60°C, target D1 operating temperature 75°C". Parts (e) and (f) are therefore answered here as ONE merged, self-consistent calculation using that recovered data; this simultaneously satisfies the "2 of 3" requirement together with part (d).

(a) D–Eop–D1–D2 bleach sequence

D = chlorine dioxide (ClO2) delignification/brightening stage; E = alkaline extraction stage (NaOH washes out the chlorinated/oxidized lignin fragments solubilized by the preceding D stage); the subscript o denotes that this extraction stage is reinforced with oxygen — i.e. "Eop" (or, where peroxide is also dosed, "Eop") is a single alkaline extraction vessel given extra delignifying/brightening power without a separate tower. Reading the sequence left to right: D0 (first ClO2 stage) → Eop (O2-reinforced extraction) → D1 → D2 (final brightening stage) — a standard 4-stage ECF (elemental-chlorine-free) sequence for a softwood Kraft pulp.

StageTemp.ConsistencypHChemical doseChemical residualKappa FactorResidence time
D0 (feed: 25 Kappa)50–60°C10–12% MC (or 30–35% HC)2–3 (acidic)≈19 kg ClO2/ODMT (KF≈0.20)2–5 g/L ClO2 residual at tower outlet0.18–0.2230–60 min
Eop70–85°C10–12%10–11 (alkaline)1.0–1.5% NaOH on pulp + O2 (200–400 kPa)≈1–2 g/L free NaOH at tower outlet—60–90 min
D170–75°C10–12%3.5–4.5≈3–6 kg ClO2/ODMT (KF≈0.10–0.20)0.2–0.5 g/L ClO2 residual0.10–0.20120–180 min

Every D-stage dose is set from the same Kappa Factor relation, $$\%\text{Cl}_2\text{-equivalent charge (on O.D. pulp)}=\text{Kappa Factor}\times\text{Kappa Number entering that stage},$$ applied to the Kappa Number the pulp actually carries INTO the stage being dosed — this is the single relation used throughout parts (d)–(f) below and in Question 2.

(b) Effluent parameters: BOD, AOX, Toxicity, TSS

BOD is measured by the standard 5-day BOD5 test: a diluted, microbially-seeded sample is incubated in the dark at 20°C and BOD is the drop in dissolved oxygen over 5 days (mg O2/L). AOX (adsorbable organic halogens) is measured by adsorbing a sample's organic content onto activated carbon, combusting the carbon, and measuring the total halide released (overwhelmingly chloride) by microcoulometric titration, reported as mg Cl/L. Toxicity is measured with standardized acute (96-h LC50, e.g. rainbow trout, Daphnia) and chronic (sub-lethal growth/reproduction) bioassays on whole final effluent. TSS is measured gravimetrically: a known volume is filtered through a pre-weighed glass-fibre filter, the residue dried at 103–105°C and weighed, reported in mg/L.

A Kraft bleach plant is historically the mill's largest single contributor to all four parameters: chlorinated/oxidized lignin and carbohydrate fragments solubilized in the D and E filtrates add BOD and (wherever elemental chlorine or hypochlorite is used) AOX and chlorophenolic toxicity; fibre fines lost during washing add TSS. Modern ECF sequences (ClO2 only, no Cl2/hypochlorite) cut AOX and toxicity dramatically relative to older chlorine-bleaching technology, though BOD and TSS remain significant simply from the sheer volume of organics solubilized.

Before discharge, combined mill effluent passes through primary clarification (settling/DAF removing TSS and fibre) and then secondary biological treatment — typically an aerated stabilization basin or activated-sludge system — where micro-organisms consume the biodegradable organic load (cutting BOD by roughly 90%+ and further degrading a portion of the AOX/toxic compounds), before discharge under a permit setting BOD, TSS, AOX, toxicity, pH and temperature limits.

(c) Oxygen delignification technologies

Two reactor configurations are in commercial use, distinguished by pulp consistency: (1) medium-consistency (MC) O2 delignification at 10–14% consistency, where the pumpable pulp slurry passes through a dedicated high-shear MC mixer that mechanically disperses gaseous O2 into fine bubbles throughout the fibre suspension before the mixture enters a pressurized upflow/downflow tower reactor (85–100°C, 600–700 kPa O2 partial pressure, NaOH charge); and (2) high-consistency (HC) O2 delignification at 25–30% consistency, where pulp is first fluffed (defibrated to a low-density, high-surface-area mass) and O2 gas plus steam are then blown directly into the fluffed pulp — mixing/diffusion here relies on the pulp's own porosity and exposed fibre surface area rather than mechanical shear. Both processes achieve broadly comparable delignification, typically 35–50% Kappa reduction; the practical ceiling is set by cellulose/carbohydrate degradation rather than any equipment limit — beyond about 50% delignification, O2-radical attack increasingly targets cellulose instead of residual lignin, causing unacceptable pulp-strength (viscosity) loss, so mills deliberately stop short of that point and let the D/E stages finish delignification to final brightness.

(d) SVP-Lite chlorine dioxide generation

1) Reducing agent: methanol (CH3OH) is the reducing agent in the R8/SVP-Lite process — it reduces chlorate (Cl(V)) to chlorine dioxide (Cl(IV)) under the strongly acidic conditions maintained by sulphuric acid, itself being partially oxidized to formic acid and CO2.

2) Role of chloride ion: Cl− is the catalytic intermediate that actually carries out the chlorate reduction — NaClO3 first reacts with Cl− (present from a small deliberate chloride charge or generated in situ) to form ClO2 and Cl2/HOCl, with the methanol then re-reducing any Cl2/HOCl back to Cl−, so the chloride ion is recycled rather than consumed, and the process runs at a much faster rate than direct chlorate/methanol reaction alone.

3) Typical generator concentrations: NaClO3 maintained near 550–650 g/L; H2SO4 maintained very strong, roughly 6–7 M (generator liquor operates below pH≈1, essential for good ClO2 yield and selectivity); sodium sesquisulphate (Na3H(SO4)2) is kept near its solubility limit in the hot, strongly acidic, high-ionic-strength liquor so that it continuously crystallizes out as it forms.

4) Typical feed strengths: NaClO3 solution fed at roughly 600–700 g/L; H2SO4 fed as concentrated (93–98%) acid; methanol fed as a dilute (typically 5–15%) aqueous solution, as in this problem (10%).

5) By-product separation: because sodium sesquisulphate has low solubility in the hot, strongly acidic, high-salinity generator liquor, it precipitates continuously as fine crystals ("saltcake") and is removed from the recirculating generator liquor by a vacuum filter or centrifuge.

6) Typical use: the sesquisulphate saltcake is fed to the Kraft recovery boiler as makeup sodium and sulphur — reduced to Na2S in the furnace exactly like the mill's normal Na2SO4→Na2S recovery chemistry — recycling it into the Kraft chemical cycle rather than discarding it.

7) Calculation — see below.

Check
As printed, the given net reaction shows "0.85 CH3OH" as a reactant and also lists "CH3OH" among the products, which cannot be a genuine net reaction (methanol appearing unchanged on both sides) — the equation as printed looks stoichiometrically unbalanced and may contain typos. The product-side "+ CH3OH" is treated as a duplicated entry and dropped; the reactant-side ratio (3 NaClO3 : 0.85 CH3OH : 3 ClO2) is used as printed, since it is the only self-consistent information available. Carbon's atomic weight (12.01) is used for the methanol molar mass since it is not among the constants supplied in the question's given list (only Cl, O, H, Na).

Given.

QuantityValue
Nameplate ClO2 plant capacity45 t/day
Plant efficiency98.0%
ClO2 product solution strength200 g/L
Methanol solution strength10%
Sodium chlorate solution strength8.2 M

Find. 10% methanol solution flowrate (kg/min); 8.2 M sodium chlorate solution flowrate (L/min).

Approach. Convert nameplate×efficiency to an actual ClO2 mass rate, then apply the reaction's molar ratios (3 NaClO3 : 0.85 CH3OH : 3 ClO2, i.e. 1:1 NaClO3:ClO2 and 0.2833:1 CH3OH:ClO2) to size the two reagent feeds.

  1. Actual ClO2 production. $$\dot m_{ClO_2}=45\times0.98=44.1\ \text{t/day}=\boxed{30.63\ \text{kg/min}}$$ M(ClO2)=35.45+2(16.0)=67.45, so $n_{ClO_2}=30{,}625/67.45=454.0\ \text{mol/min}$.
  2. Methanol solution flowrate. M(CH3OH)=12.01+4(1.008)+16.0=32.04. The reaction needs 0.85 mol CH3OH per 3 mol ClO2: $$n_{CH_3OH}=454.0\times\frac{0.85}{3}=128.6\ \text{mol/min}\ \Rightarrow\ \dot m_{100\%}=128.6\times32.04/1000=4.123\ \text{kg/min}$$ $$\dot m_{10\%\ soln}=4.123/0.10=\boxed{41.2\ \text{kg/min}}$$
  3. Sodium chlorate solution flowrate. M(NaClO3)=23.0+35.45+3(16.0)=106.45; the reaction needs 1 mol NaClO3 per mol ClO2 (3:3 ratio), so $n_{NaClO_3}=454.0$ mol/min. At 8.2 mol/L: $$\dot V_{NaClO_3}=\frac{454.0}{8.2}=\boxed{55.4\ \text{L/min}}\qquad(\dot m=454.0\times106.45/1000=48.3\ \text{kg/min})$$
QuantityValue
Actual ClO2 production30.63 kg/min
10% methanol solution feed41.2 kg/min
8.2 M NaClO3 solution feed55.4 L/min (48.3 kg/min)

(e)+(f) D1 Kappa-Factor dosing, ClO2 preheat heat exchanger & steam savings

Given.

QuantityValue
Incoming D1 Kappa Number (i)4.0
D1 Stage Kappa Factor (ii)0.20
Bleach Plant production rate (iii)1000 ADMT/day
D1 operating consistency (iv)10% AD
ClO2 solution strength (v)12.0 g/L
ClO2 solution in / out of HX4°C / 46°C
D2-stage filtrate in (hot side)75°C
Stock from preceding extraction / D1 target60°C / 75°C

Find. (i) ClO2 solution flow to D1; (ii) D1 filtrate chemicals content; (iii) D1 filtrate temperature out of the heat exchanger; (iv) steam savings achieved by the heat exchanger relative to heating the stock directly with steam.

Approach. Size the D1 ClO2 dose from the Kappa-Factor relation, then find the total D1 stock/filtrate flow from the stated 10% operating consistency (dilution-water mass balance). An energy balance on the ClO2 preheat exchanger (heat lost by hot D2 filtrate = heat gained by cold ClO2 solution) gives the filtrate outlet temperature and the recovered heat duty; comparing that duty against the duty needed to heat the FULL stock flow directly with steam (60→75°C) gives the steam savings.

Check
Steam is valued at its latent heat of vaporization, taken as hfg=2257 kJ/kg (saturated steam ≈100°C, a typical low-pressure mixer/injection condition).
  1. (i) D1 ClO2 dose and solution flow. $$\%\text{Cl}_2\text{-eq}=0.20\times4.0=0.80\%=8.0\ \text{kg/t}\ \Rightarrow\ \text{ClO}_2=8.0/2.63=3.04\ \text{kg/ODMT}$$ O.D. production $=1000\times0.90=900\ \text{ODMT/day}$ (90% AD convention) $=625.0\ \text{kg O.D. pulp/min}$: $$\dot m_{ClO_2}=3.04\times900/1440=1.901\ \text{kg/min}\ \Rightarrow\ \dot V_{D_1}=\frac{1.901\times1000}{12.0}=\boxed{158.4\ \text{L/min}}$$
  2. D1 total stock/filtrate flow (10% consistency). Total flow at 10% AD $=625.0/0.10=6250\ \text{kg/min}$; the filtrate (water) portion is the difference from the O.D. pulp flow: $$\dot m_{filtrate}=6250-625.0=\boxed{5625\ \text{kg/min}}$$
  3. (ii) D1 filtrate chemicals content. The dosed ClO2 diluted into the full filtrate/stock flow: $$C_{filtrate}=\frac{1.901\times1000}{5625}=\boxed{0.338\ \text{g/L}}$$
  4. HX heat duty. ClO2 solution mass flow ≈158.4 kg/min (ρ≈1.0 kg/L), heated 4→46°C: $$Q=158.4\times4.18\times(46-4)=\boxed{27{,}810\ \text{kJ/min}}$$
  5. (iii) D2-filtrate outlet temperature. Energy balance on the exchanger, filtrate loses what the ClO2 solution gains: $$\Delta T_{filtrate}=\frac{27{,}810}{5625\times4.18}=1.18^{\circ}\text{C}\ \Rightarrow\ T_{filtrate,out}=75-1.18=\boxed{73.8^{\circ}\text{C}}$$
  6. (iv) Steam savings. Direct steam heating of the FULL stock flow (6250 kg/min) from 60°C to the D1 mixer's 75°C target would need $$Q_{direct}=6250\times4.18\times(75-60)=391{,}875\ \text{kJ/min}\ \Rightarrow\ \dot m_{steam,direct}=391{,}875/2257=173.6\ \text{kg/min}.$$ Using the HX to preheat only the ClO2 makeup stream instead recovers $$\dot m_{steam,saved}=\frac{27{,}810}{2257}=\boxed{12.3\ \text{kg/min}}$$ of that direct-steam duty — a modest but "free" saving, since the D2 filtrate would otherwise be discharged at 75°C with its heat unused.
QuantityValue
(i) ClO2 solution flow to D1158.4 L/min
(ii) D1 filtrate chemicals content0.338 g/L
(iii) D1/D2-filtrate temperature out of HX73.8°C
Direct-steam duty (no HX)173.6 kg/min
(iv) Steam savings from the HX12.3 kg/min
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