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16-Civ-A1 Elementary Structural Analysis · May 2016

Question 1 of 8: Classify each structure — unstable / determinate / indeterminate

Nivaar worked solution (AI-drafted; not reviewed by a licensed engineer)

Notes on this paper

Reference texts: R.C. Hibbeler, Structural Analysis (10th ed., Pearson) — determinacy, method of joints/sections, virtual-work deflections, moment distribution / slope–deflection, influence lines; A. Kassimali, Structural Analysis (6th ed., Cengage) — internal hinges, compound (Gerber) beams and three-hinged frames. Sign convention: sagging bending moment positive; upward reactions positive; member tension positive (T), compression negative (C).

The paper directs candidates to answer Q1–Q5 and then one of Q6/Q7/Q8. For completeness all eight questions are worked here.

Question 1: Classify each structure — unstable / determinate / indeterminate (6 marks)

Question text not reproduced: the examination questions are © Engineers and Geoscientists BC. Open the official past paper (linked at the top of this page) to read the question, then follow the worked solution below.

Approach. For rigid (beam/frame) assemblies with no closed rings the degree of static indeterminacy is $\text{DSI}=r-3-c$, where $r$ is the number of reaction components and $c$ the internal condition equations (one per single hinge connecting two members). Where a closed ring is present, $\text{DSI}=3m+r-3n-c$ ($m$ members, $n$ nodes). For pin-jointed trusses $\text{DSI}=m+r-2n$. A negative count, or reactions that are parallel/concurrent, signals a mechanism (unstable) and overrides the count.

w(a) continuous beam, 2 internal hinges
(a) Pin + three rollers with two internal hinges under UDL $w$.
  1. (a) Continuous beam, two internal hinges. One pin (2) plus three rollers (1 each) give $r=5$; two single hinges give $c=2$. $\text{DSI}=5-3-2=\boxed{0}$ — statically determinate.
  2. (b) Cranked beam, fixed–roller–fixed with one hinge. A fixed end (3), an intermediate roller (1) and a second fixed end (3) give $r=7$; one internal hinge gives $c=1$. $\text{DSI}=7-3-1=\boxed{3}$ — indeterminate, 3°.
  3. (c) Triangular (A-frame) rigid frame, two pinned feet. Modelling the two legs and the horizontal tie gives $m=5$ members, $n=5$ nodes; two pins give $r=4$; all joints rigid, $c=0$. $\text{DSI}=3(5)+4-3(5)-0=\boxed{4}$ — indeterminate, 4° (one closed ring contributes 3, the redundant reaction adds 1).
  4. (d) Portal frame with a corner hinge. $m=3$, $n=4$; a pinned base (2) and a fixed base (3) give $r=5$; the hinge at the upper-left knee gives $c=1$. $\text{DSI}=3(3)+5-3(4)-1=\boxed{1}$ — indeterminate, 1°.
  5. P(e) truss
    (e) Five-joint truss with crossing diagonals.
    PPP(f) truss
    (f) Nine-joint symmetric roof truss.
  6. (e) Truss with crossing diagonals. $m=9$, $n=5$; pin + roller give $r=3$. $\text{DSI}=9+3-2(5)=\boxed{2}$ — indeterminate, 2° (the two crossing diagonals are the redundant members; the equilibrium matrix is full rank, so the truss is stable).
  7. (f) Symmetric roof truss. $m=15$, $n=9$; pin + roller give $r=3$. $\text{DSI}=15+3-2(9)=\boxed{0}$ — statically determinate.
StructureClassification
(a)Determinate
(b)Indeterminate, 3°
(c)Indeterminate, 4°
(d)Indeterminate, 1°
(e)Indeterminate, 2°
(f)Determinate
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