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16-Civ-A6 Highway Design, Construction, and Maintenance · December 2015

Question 7 of 7: Multinomial Logit Mode Choice and the IIA Property

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Notes on this paper

Paper format: 98-Civ-A6 Transportation Planning & Engineering, National Examination, December 2015. Seven questions, each of equal value (20 marks); any five constitute a complete examination. Closed book, one two-sided aid sheet permitted. Three hours. All seven questions are solved below as a study resource.

Reference texts. Mannering, Washburn & Kilareski, Principles of Highway Engineering and Traffic Analysis (Wiley); Papacostas & Prevedouros, Transportation Engineering and Planning (Prentice Hall); Roess, Prassas & McShane, Traffic Engineering (Pearson); Ortúzar & Willumsen, Modelling Transport (Wiley) for the demand-model chapters (trip generation, distribution, mode choice, assignment).

Question 7: Multinomial Logit Mode Choice and the IIA Property (20 marks)

Question text not reproduced: the examination questions are © Engineers and Geoscientists BC. Open the official past paper (linked at the top of this page) to read the question, then follow the worked solution below.

Given. A linear-in-attributes utility with common coefficients across modes.

Given data — mode attributes
ModeC$X_1$ wait (min)$X_2$ travel (min)$X_3$ park (min)$X_4$ cost (cents)
Auto−0.330205225
Bus−0.2710350100
Light rail015250150

Find. Binary auto/bus split (a); three-way split with light rail (b); an IIA critique and remedy (c).

Approach. Evaluate each utility $V_m$, then apply the logit share $P_m=e^{V_m}/\sum_j e^{V_j}$. Only utility differences matter, so the answer is unchanged by any common shift.

  1. Mode utilities. Substituting each attribute set: $$V_{\text{auto}}=-0.33-0.13(20)-0.12(5)-0.0045(225)=-4.5425,$$ $$V_{\text{bus}}=-0.27-0.10(10)-0.13(35)-0.0045(100)=-6.2700.$$
  2. (a) Binary logit split. $$P_{\text{auto}}=\frac{e^{-4.5425}}{e^{-4.5425}+e^{-6.2700}}=\frac{1}{1+e^{-1.7275}}=0.849,$$ $$\boxed{P_{\text{auto}}=84.9\%,\qquad P_{\text{bus}}=15.1\%}$$
  3. (b) Add light rail. Its utility is $$V_{\text{LR}}=0-0.10(15)-0.13(25)-0.0045(150)=-5.4250.$$ With $\sum_j e^{V_j}=e^{-4.5425}+e^{-6.2700}+e^{-5.4250}$: $$\boxed{P_{\text{auto}}=62.8\%,\quad P_{\text{bus}}=11.2\%,\quad P_{\text{LR}}=26.0\%}$$
  4. (c) IIA check. The auto:bus odds are $0.849/0.151=5.62$ before light rail and $0.628/0.112=5.62$ after — identical. The logit model draws the new mode’s 26 % share from auto and bus in proportion to their existing shares, exactly as IIA requires.

(c) Interpretation and remedy. The prediction is not fully intuitive. Light rail and bus are both public-transit modes and share many unobserved attributes (transfers, schedule adherence, "transit" stigma), so a new rail line should draw disproportionately from the bus, not evenly from auto and bus. This is the classic red-bus/blue-bus failure of IIA: the multinomial logit treats all alternatives as equally substitutable because its error terms are independent. Here auto loses 22.1 percentage points (84.9 % → 62.8 %) while bus loses only 3.9 (15.1 % → 11.2 %), so the model overstates the diversion from auto and understates how much light rail would cannibalise the bus. Remedies: use a nested logit that groups bus and light rail under a "transit" nest (so they compete more closely with each other than with auto), or a cross-nested/mixed (random-parameters) logit or probit model that allows correlated error terms across the similar modes. Adding a mode-specific bus–rail correlation restores the intuitive result.

Question 7 — mode-choice results
ModeUtility $V$(a) Share(b) Share with LR
Auto−4.542584.9%62.8%
Bus−6.270015.1%11.2%
Light rail−5.4250—26.0%
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