16-Civ-B5 Water Supply and Wastewater Treatment · December 2017
Nivaar worked solution (AI-drafted; not reviewed by a licensed engineer)
Paper format. National Examination, December 2017 — 16-Civ-B5 Water Supply and Wastewater Treatment. Three hours; closed book with one aid sheet written on both sides; an approved calculator is permitted. Question 1 is compulsory and the candidate attempts any three of the remaining four questions. Every question carries 25 marks, so the paper is marked out of 100. A partial-flow chart for circular pipes is supplied on page 3 for use in Question 5. All five questions are solved below, because the set is a study resource rather than an exam script.
Reference texts for this subject.
Question text not reproduced: the examination questions are © Engineers and Geoscientists BC. Open the official past paper (linked at the top of this page) to read the question, then follow the worked solution below.
The paper labels both sub-parts "a."; the second is treated as part (b) below, as its mark allocation and content require.
Part (a) — Significance of ammonia, the reported forms, and the receiving-water cases (15 marks).
Given. A secondary effluent discharged to a surface water body; illustrative effluent total ammonia nitrogen 20 mg N/L with cBOD5 20 mg/L; receiving water at 20 °C. Find. Why ammonia matters, which analytical forms are reported, which form governs in each of the three receiver cases, and how pH controls the toxicity.
Ammonia matters for three distinct reasons, and keeping them separate is the whole of this question. First, it exerts an oxygen demand. Nitrifying bacteria oxidise ammonium to nitrate,
$$\mathrm{NH}_4^{+} + 2\,\mathrm{O}_2 \rightarrow \mathrm{NO}_3^{-} + 2\,\mathrm{H}^{+} + \mathrm{H}_2\mathrm{O}$$so the stoichiometric nitrogenous oxygen demand is \(2 \times 32.00/14.01 = 4.57\) g O2 per g N (about 4.33 g/g once cell synthesis is allowed for). For the illustrative effluent,
$$\mathrm{NOD} = 4.57 \times 20 = \boxed{91.4\ \mathrm{mg/L\ as\ O_2}}$$which is 4.6 times the carbonaceous demand of the same effluent. A discharge that meets a 20 mg/L cBOD5 permit can therefore still deoxygenate the reach, because the permit measures only the smaller of the two demands. Second, it is directly toxic through the un-ionised species, as developed below. Third, it is a nutrient, contributing to eutrophication and to nuisance algal growth in nitrogen-limited receivers such as estuaries and coastal waters. A fourth, plant-side significance is that ammonia consumes chlorine, so a chlorinated effluent leaves only a combined residual.
The forms usually determined and reported in an effluent analysis are:
The three receiver cases are then answered by asking which of the two mechanisms binds:
Impact of pH, and its control. The toxic fraction is set by the ammonium dissociation with pKa = 9.40 at 20 °C (Emerson). For the illustrative 20 mg N/L:
| pH (at 20 °C) | 7.0 | 8.0 | 9.0 |
|---|---|---|---|
| Un-ionised NH3-N, mg/L | 0.079 | 0.761 | 5.67 |
| Multiple of the CCME 0.019 mg/L guideline | 4.2 | 40 | 298 |
Temperature acts the same way, though more weakly: at pH 8.0 the free ammonia rises from 0.761 to 1.07 mg/L between 20 and 25 °C, because pKa falls with temperature. Control therefore has two routes. The direct route is to remove the ammonia: biological nitrification in the plant (the standard answer, and the one that also removes the NOD), or nitrification–denitrification where total nitrogen is capped, or breakpoint chlorination and air stripping for special cases. The indirect route is to manage the speciation: lower the effluent pH before discharge (chemical addition, or CO2 recarbonation), avoid discharging into a shallow, weed-choked reach where afternoon photosynthesis pushes the pH above 9, and design the outfall diffuser so that the plume mixes rapidly while its pH is still that of the effluent. Air stripping of ammonia is the reverse operation and makes the point plainly: it works only after the pH is raised to 10.5–11, precisely because that converts the ammonium to the volatile free form.
Part (b) — The four biochemical stages of anaerobic sludge digestion, and the rate-limiting step (10 marks).
Anaerobic digestion is a consortium process in which four groups of organisms act in series, each living on the products of the one before. The sequence is:
The methane yield that ties the four stages together is 0.35 m3 CH4 per kg COD stabilised at STP, or 0.395 m3/kg at a mesophilic 35 °C.
Which stage is rate-limiting, and why. The answer depends on the substrate, and saying so is what distinguishes a complete answer. For municipal sludge — the case this question is about — hydrolysis is rate-limiting, because the feed is predominantly particulate: primary sludge is fibrous and lipid-rich, and waste activated sludge is bacterial cell mass whose walls must be lysed before anything inside is available. Enzymatic attack on a solid surface proceeds at a rate set by the available surface area, not by a soluble-substrate concentration, so it follows first-order kinetics with a low rate constant. This is precisely why sludge pre-treatment technologies — thermal hydrolysis, ultrasonic and mechanical disintegration, alkaline lysis — target this step and can cut the required SRT roughly in half. For a soluble, readily fermentable feed (a food-industry wastewater in a UASB, say), hydrolysis is trivial and methanogenesis becomes rate-limiting instead.
Methanogenesis is, in either case, the most vulnerable stage, and the distinction between "slowest" and "most vulnerable" is worth marks. Acetoclastic methanogens have a maximum specific growth rate of roughly 0.3 d−1 at 35 °C, so their doubling time is
$$t_d = \frac{\ln 2}{\mu_{\max}} = \frac{0.693}{0.30} = 2.3\ \mathrm{d} \quad\Longrightarrow\quad \boxed{\ \theta_c \approx 6 t_d \approx 14\ \mathrm{d\ design\ SRT\ at\ 35\ ^\circ C}\ }$$which is the origin of the familiar 15–20 d mesophilic digester design. They are also inhibited by free ammonia above roughly 100 mg/L NH3-N, by sulphide, and by pH outside 6.8–7.4. If they are lost, the fast acidogens keep running, VFAs accumulate, the pH falls, and the digester "sours" — a failure whose signature (rising VFA/alkalinity ratio, falling methane fraction) is monitored precisely because the recovery takes weeks at a 2.3 d doubling time.
| Item | Result |
|---|---|
| Nitrogenous oxygen demand | 4.57 g O2/g N; 91.4 mg/L for a 20 mg N/L effluent, i.e. 4.6× its cBOD5 |
| Forms reported | TAN (measured), un-ionised NH3-N (calculated from pH and T), NH4+-N (by difference), TKN |
| Case (a) high DO, toxicity | Un-ionised NH3-N governs; compare with CCME 0.019 mg/L at summer pH and T |
| Case (b) low DO, no toxicity | Total ammonia nitrogen governs, as a mass load, through the 4.57 g O2/g N demand |
| Case (c) both | Both forms; the binding limit is the lower of the two, and full nitrification is the defensible answer |
| pH effect at 20 °C, TAN = 20 mg N/L | 0.079 / 0.761 / 5.67 mg/L NH3-N at pH 7 / 8 / 9 — a 72× rise over two pH units |
| Four stages | Hydrolysis → acidogenesis → acetogenesis → methanogenesis |
| Rate-limiting stage | Hydrolysis for particulate municipal sludge; methanogenesis for soluble feeds and always the most vulnerable (td = 2.3 d, design SRT ≈ 14 d at 35 °C) |
Check: the effluent quality (20 mg N/L TAN, 20 mg/L cBOD5) is the solver's own illustrative value for a non-nitrifying secondary plant; the question supplies no data. Methanogen kinetics vary with temperature and inhibition — \(\mu_{\max}\) is taken as 0.30 d−1 at 35 °C with a safety factor of 6 on the minimum SRT, which lands on the conventional 14–15 d and is why mesophilic digesters are designed at 15–20 d.