NivaarExam PrepOfficial exam papers ↗

18-Env-A2 Hydrology and Municipal Hydraulics Engineering · May 2016

Question 4 of 7: Watershed Abstractions, Hydrograph Shape and a Pump Impeller Diameter Change

Nivaar worked solution (AI-drafted; not reviewed by a licensed engineer)

Notes on this paper

National Exams — May 2016 — 04-Env-A2 / Hydrology and Municipal Hydraulics Engineering. 3 hours duration; closed book with a candidate-prepared 8½×11 in double-sided aid sheet; Casio or Sharp approved calculator only. Any five questions constitute a complete paper (first five answers marked, 20 marks each, 100 marks total); all seven are solved below for completeness.

Reference texts. Davis & Cornwell, Introduction to Environmental Engineering (6th ed.) — hydrology and water-distribution chapters; Metcalf & Eddy, Wastewater Engineering: Treatment and Resource Recovery (5th ed.) — sanitary sewer collection systems; MWH’s Water Treatment: Principles and Design (3rd ed.) — pipe-network analysis and pump selection; Chow, Open-Channel Hydraulics — Manning's n tables, specific-energy and sediment-transport theory; Linsley, Hydrology for Engineers — hydrologic cycle, hydrograph analysis and IDF curves; Walski, Advanced Water Distribution Modeling and Management — Hardy-Cross network solutions and pump affinity laws.

Problem 4: Watershed Abstractions, Hydrograph Shape and a Pump Impeller Diameter Change (20 marks)

Question text not reproduced: the examination questions are © Engineers and Geoscientists BC. Open the official past paper (linked at the top of this page) to read the question, then follow the worked solution below.

(i) Watershed Abstractions Determining the Runoff Hydrograph

Three important abstractions subtract from gross rainfall to leave the "rainfall excess" that actually becomes direct runoff and shapes the hydrograph: interception — rainfall caught on vegetation canopy that evaporates without ever reaching the ground; depression storage — water ponding in small surface depressions that must fill before overland flow can begin; and infiltration — water entering the soil profile, governed by soil type, antecedent moisture and land cover, typically the largest of the three abstractions in most storm events. Because these abstractions are satisfied first, a hydrograph's rising limb only begins once their combined capacity is exceeded, which is why a dry, permeable watershed produces a delayed, low peak while a saturated or impervious one produces an almost immediate, high peak for the same storm.

(ii) Watershed Factors Influencing Hydrograph Shape

Watershed factors affecting hydrograph shape
FactorDescriptionEffect on peak flowEffect on time to peak
Watershed shape & drainage-area sizeAn elongated watershed spreads tributary flow paths over a wide range of travel times; a compact, fan-shaped watershed concentrates them.Fan-shaped → higher, sharper peak (flows arrive together); elongated → lower, more attenuated peak.Fan-shaped → shorter time to peak; elongated → longer time to peak.
Slope & imperviousness (land cover)Steeper slopes and greater impervious cover increase overland-flow velocity and reduce infiltration losses.Steeper/more impervious → higher peak flow (more rainfall excess, faster delivery).Steeper/more impervious → shorter time to peak (faster travel time).

(iii) Impeller Diameter Change: New Operating Point via the Pump Affinity Laws

Given.

Given data
QuantitySymbolValue
Original impeller diameter$D_1$100 mm
New impeller diameter$D_2$140 mm
Speed$N$constant (same casing/motor)
Check: the pump chart gives axis ranges (head 0–45 m, capacity 0–0.030 m³/s) and iso-efficiency contours up to 77% at the family's overall centre, but not a digitized curve. The $D_1=100$ mm curve, a smaller trim within the family, is read to peak on the chart's own ~66% efficiency contour at $Q_1\approx0.0108$ m³/s, $H_1\approx12.5$ m — treat these two readings as the input to the calculation, ± chart-reading precision; the percent-capacity-improvement result below does not depend on this reading at all.

Find. The new BEP capacity $Q_2$, head $H_2$, brake power $P_2$, expected efficiency $\eta_2$, and the % capacity improvement.

Approach. At constant speed, geometrically similar impeller trims within the same casing obey the pump affinity laws: $Q\propto D$, $H\propto D^2$, $P\propto D^3$, with efficiency approximately unchanged for a modest trim ratio.

  1. Diameter ratio. $$r=\frac{D_2}{D_1}=\frac{140}{100}=\boxed{1.40}.$$
  2. New capacity (affinity law, $Q\propto D$). $$Q_2=Q_1\,r=0.0108\times1.40=\boxed{0.01512\ \text{m}^3/\text{s}}\ (15.1\ \text{L/s}).$$
  3. New head (affinity law, $H\propto D^2$). $$H_2=H_1\,r^2=12.5\times(1.40)^2=\boxed{24.5\ \text{m}}.$$
  4. Efficiency and brake power. Efficiency is assumed essentially unchanged for a geometrically similar trim, $\eta_2\approx\eta_1=\boxed{66\%}$. Brake power follows from $P=\rho g Q H/\eta$: $$P_2=\frac{\rho g Q_2 H_2}{\eta_2}=\frac{1000\times9.81\times0.01512\times24.5}{0.66}=\boxed{5.51\ \text{kW}}.$$
  5. Percent capacity improvement. This follows directly from the diameter ratio alone, independent of the assumed BEP reading: $$\%\ \text{improvement}=(r-1)\times100\%=\boxed{40.0\%}.$$
QuantityValue
New optimum capacity, $Q_2$0.01512 m³/s (15.1 L/s)
New head, $H_2$24.5 m
New brake power, $P_2$5.51 kW
Expected efficiency, $\eta_2$≈66% (unchanged from $D_1$)
% capacity improvement40.0%
Capacity, Q (m³/s) Head, H (m) 0 0.030 77% D₁ = 100 mm D₂ = 140 mm affinity parabola H=(H₁/Q₁²)Q² BEP₁ BEP₂
Impeller-trim family: reading the 100 mm curve's operating point and projecting to 140 mm along the affinity parabola through the origin.