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18-Env-A4 Water and Wastewater Engineering · May 2017

Question 5 of 5: Primary Clarifier Design

Nivaar worked solution (AI-drafted; not reviewed by a licensed engineer)

Notes on this paper

National Exams — May 2017 — 04-Env-A4 / Water and Wastewater Engineering. 3 hours duration; closed book with one double-sided aid sheet; approved calculator permitted. Question 1 is compulsory; the paper instructs candidates to attempt any three of the remaining four questions — all five are solved below for completeness.

Reference texts. Metcalf & Eddy, Wastewater Engineering: Treatment and Resource Recovery (5th ed.) — oxygen sag/Streeter-Phelps, MLSS/MLVSS, population equivalent, primary clarifier design; Davis & Cornwell, Introduction to Environmental Engineering (6th ed.) — turbidity, alkalinity chemistry; MWH’s Water Treatment: Principles and Design (3rd ed.) — coagulation-flocculation, softening, disinfection by-products, pH; Guidelines for Canadian Drinking Water Quality (Health Canada).

Question 5: Primary Clarifier Design (25 marks)

Question text not reproduced: the examination questions are © Engineers and Geoscientists BC. Open the official past paper (linked at the top of this page) to read the question, then follow the worked solution below.

Given.

Primary clarifier influent and design parameters
QuantitySymbolValue
Average day flow$Q$10,000 m³/d
Influent TSS$TSS_{in}$250 mg/L
Influent VSS$VSS_{in}$200 mg/L
Influent BOD5$BOD_{in}$200 mg/L
TSS removal efficiency$R_{TSS}$60%
Sludge solids concentration$P_s$4%
Sludge specific gravity$SG$1.03
Surface overflow rate$SOR$60 m³/m²·d
Peak flow factor$PF$2.25
Side water depth$H$3.0 m

Find. The effluent TSS/VSS/BOD5 loads, the daily primary-sludge volume, the required clarifier surface area, and the HRT at average flow.

Approach. Apply the given 60% TSS removal to TSS directly; assume VSS is removed at the same fractional efficiency as TSS (settling does not discriminate strongly by volatility) and estimate BOD5 removal from the standard primary-clarifier TSS-vs-BOD5 removal correlation, then work the mass-balance, sludge-volume, overflow-rate and HRT calculations in sequence.

Check: BOD5 removal is not directly given. Metcalf & Eddy’s typical primary-clarifier performance curves put BOD5 removal roughly 25 percentage points below TSS removal over the normal design range (50–70% TSS / 25–40% BOD5); at 60% TSS removal this gives an assumed 35% BOD5 removal, used below. VSS removal is assumed equal to the stated TSS removal (60%), since a primary clarifier removes solids by settling velocity, not by volatile/fixed composition.
  1. Effluent concentrations. $TSS_{eff}=TSS_{in}(1-R_{TSS})=250(0.40)=\boxed{100\text{ mg/L}}$. $VSS_{eff}=200(0.40)=\boxed{80\text{ mg/L}}$. $BOD_{eff}=200(1-0.35)=\boxed{130\text{ mg/L}}$.
  2. Convert to loads. $Load\,(\text{kg/d}) = C\,(\text{mg/L}) \times Q\,(\text{m}^3\text{/d}) / 1000$. Influent: $TSS=2{,}500$, $VSS=2{,}000$, $BOD_5=2{,}000$ kg/d. Effluent: $TSS_{eff}=100(10{,}000)/1000=\boxed{1{,}000\text{ kg/d}}$, $VSS_{eff}=80(10{,}000)/1000=\boxed{800\text{ kg/d}}$, $BOD_{eff}=130(10{,}000)/1000=\boxed{1{,}300\text{ kg/d}}$.
  3. (II) Primary sludge volume. Mass of TSS removed, $M_{removed}=2{,}500-1{,}000=1{,}500$ kg/d (checks against $2{,}500\times0.60=1{,}500$). Sludge density $=SG\times1000=1{,}030$ kg/m³. $V_{sludge}=\dfrac{M_{removed}}{\rho_{sludge}\times P_s}=\dfrac{1{,}500}{1{,}030\times0.04}=\boxed{36.4\text{ m}^3\text{/d}}$.
  4. (III) Clarifier surface area. Peak flow $Q_{peak}=Q\times PF=10{,}000\times2.25=22{,}500$ m³/d. $A=\dfrac{Q_{peak}}{SOR}=\dfrac{22{,}500}{60}=\boxed{375\text{ m}^2}$.
  5. (IV) HRT at average flow. Clarifier volume $=A\times H=375\times3.0=1{,}125$ m³. $HRT=\dfrac{V}{Q}=\dfrac{1{,}125}{10{,}000}=0.1125\text{ d}=\boxed{2.7\text{ h}}$.
Question 5 — final results
QuantityValue
Effluent TSS / VSS / BOD5 load1,000 / 800 / 1,300 kg/d
Primary sludge volume36.4 m³/d
Clarifier surface area375 m²
HRT at average day flow0.1125 d (2.7 h)
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