18-Env-A6 Solid Waste Engineering and Management · May 2013
Question 17 of 17: Break-Even Price for Diverted Paper
Nivaar worked solution (AI-drafted; not reviewed by a licensed engineer)
Notes on this paper
National Examination, May 2013 — 04-Env-A6 / 18-Env-A6, Solid Waste Engineering and Management. 3 hours duration, closed book, one letter-sized aid sheet permitted. All 17 questions constitute a complete paper (100 marks total).
Reference texts: Tchobanoglous, Theisen & Vigil, Integrated Solid Waste Management: Engineering Principles and Management Issues; Vesilind, Worrell & Reinhart, Solid Waste Engineering; Davis & Cornwell, Introduction to Environmental Engineering (6th ed.); CCME, Guidance Document on Landfill Gas Management.
Check: several questions on this paper (Q1, Q13, Q14, Q17) supply an incomplete data set and explicitly invite the candidate to "make and state" assumptions. Every assumed value below is called out where it is introduced and is chosen from standard solid-waste-engineering practice; the governing METHOD, not the specific assumed number, is what the exam is testing.
Question 17: Break-Even Price for Diverted Paper (6 marks)
Given. Incinerator feed 400 t/d MSW; 20% reduction in paper/cardboard reaching the incinerator due to source separation; NG cost \$0.40/m³; paper energy content 16,300 kJ/kg; NG energy content 37,300 kJ/m³.
Find. The minimum price per tonne the municipality must receive for the diverted paper to exactly offset the extra natural-gas cost (break-even).
Energy make-up balance: natural gas replaces exactly the heating value lost from the diverted paper so steam output is unchanged.
Approach. Compute the mass of paper actually diverted from the incinerator, convert its lost heating value to an equivalent natural-gas volume and cost, then divide that cost by the diverted paper tonnage to get the break-even price.
Check: this question does not state what fraction of the 400 t/d feed is paper/cardboard. Reusing this paper's own Q15 waste-composition analysis (Table 1: paper = 45% by mass) is the only composition data the exam supplies, and is assumed to represent this city's incinerator feed.
Paper mass diverted from the incinerator.
$$m_{paper,in} = 400\times0.45 = 180\ \text{t/d}, \qquad m_{diverted} = 0.20\times180 = \boxed{36\ \text{t/d}}$$
Heating value lost, and natural gas needed to replace it.
$$\Delta E = 36{,}000\ \text{kg/d}\times16{,}300\ \text{kJ/kg} = 5.868\times10^{8}\ \text{kJ/d}$$
$$V_{NG} = \dfrac{5.868\times10^{8}}{37{,}300} = \boxed{15{,}732\ \text{m}^3/\text{d}}$$
Extra natural-gas cost, and break-even paper price.
$$C_{NG} = 15{,}732\ \text{m}^3/\text{d}\times\$0.40/\text{m}^3 = \$6{,}293/\text{d}$$
$$\text{Price}_{paper} = \dfrac{\$6{,}293/\text{d}}{36\ \text{t/d}} = \boxed{\$175/\text{tonne}}$$