NivaarExam PrepOfficial exam papers ↗

18-Geol-A5 Rock Mechanics · December 2013

Question 2 of 5: Mohr-Coulomb Parameters from Triaxial Compression Data

Nivaar worked solution (AI-drafted; not reviewed by a licensed engineer)

Notes on this paper

National Exams — December 2013 — 04-Geol-A5 Rock Mechanics. Three-hour, closed-book exam; one of two approved calculators permitted, plus two sheets of the candidate's own rock-mechanics formulae/notes. Five questions of equal value (20 marks each); the paper instructs candidates to answer only the first 4 of 5 questions appearing in the answer book — all five are answered here as a complete study resource. Selected equations, RMR tables (Bieniawski 1989) and the Modified Lauffer stand-up-time chart are supplied at the back of the exam and are reproduced where used.

Reference texts: Bieniawski, Engineering Rock Mass Classifications (Wiley, 1989) — the RMR system, discontinuity-condition guidelines, and excavation/support tables used in Q1; Hoek, Practical Rock Engineering — Mohr-Coulomb strength parameters from triaxial data, Kirsch stress solutions around circular openings, and thick-wall liner design used in Q2/Q3/Q5; Brady & Brown, Rock Mechanics for Underground Mining (3rd ed.) — tributary-area pillar stress analysis and elastic pillar deformation used in Q4; EGBC Geoscience Professional Practice Guidelines for assumption-disclosure conventions.

Question 2: Mohr-Coulomb Parameters from Triaxial Compression Data (20 marks)

Question text not reproduced: the examination questions are © Engineers and Geoscientists BC. Open the official past paper (linked at the top of this page) to read the question, then follow the worked solution below.

Given. Five triaxial failure pairs $(\sigma_3,\sigma_1)$ in MPa: (16.8, 159.3), (13.2, 154.5), (25.0, 198.0), (9.7, 140.1), (20.0, 168.0). The Mohr-Coulomb straight-line failure locus $\sigma_1=\sigma_3\tan^2\Psi+S_c$, with $\Psi=45^{\circ}+\phi/2$ and $S_c=2C\tan\Psi$.

Triaxial test results
Confining stress $\sigma_3$ (MPa)Failure axial stress $\sigma_1$ (MPa)
16.8159.3
13.2154.5
25.0198.0
9.7140.1
20.0168.0

Find. (a) Cohesion $C$, friction angle $\phi$, failure-plane angle $\Psi$ and UCS $S_c$. (b) Data-quality issues evident from the fit. (c) Failure axial stress at $\sigma_3=5,15,22.5$ MPa. (d) An independent check on part (c).

Approach. The Mohr-Coulomb failure locus $\sigma_1=\sigma_3\tan^2\Psi+S_c$ is linear in $\sigma_3$, so a least-squares regression of the five $(\sigma_3,\sigma_1)$ pairs gives the slope ($\tan^2\Psi$) and intercept ($S_c$) directly; $\phi$ and $C$ follow from the standard relations. The fitted line is then simply evaluated at the three new confining stresses for part (c).

  1. Linear regression of the failure data. With $\bar\sigma_3=16.94$ MPa, $\bar\sigma_1=163.98$ MPa, $$\text{slope}=\tan^2\Psi=\frac{\sum(\sigma_{3,i}-\bar\sigma_3)(\sigma_{1,i}-\bar\sigma_1)}{\sum(\sigma_{3,i}-\bar\sigma_3)^2}=3.520,\qquad \text{intercept}=S_c=\bar\sigma_1-\text{slope}\times\bar\sigma_3=\boxed{104.3\ \text{MPa}}$$ The coefficient of determination is $R^2=0.940$ — a reasonably tight but imperfect fit to a straight line.
  2. Failure angle and friction angle. $$\Psi=\arctan\sqrt{3.520}=\boxed{61.9^{\circ}},\qquad \phi=2(\Psi-45^{\circ})=\boxed{33.9^{\circ}}$$
  3. Cohesion. $$C=\frac{S_c}{2\tan\Psi}=\frac{104.3}{2\tan(61.9^{\circ})}=\boxed{27.8\ \text{MPa}}$$
  4. Part (b) — problems evident from the data. The fit is good ($R^2=0.940$) but not exact — the largest residual is at $\sigma_3=25.0$ MPa, where the measured 198.0 MPa sits noticeably off the fitted line, hinting that the true envelope may curve slightly (a common real-rock departure from a strictly linear Mohr-Coulomb locus, especially toward the high-confinement end). More fundamentally, only five specimens were tested with NO repeat tests at any single confining stress, so there is no way to separate genuine specimen-to-specimen strength variability from a real nonlinearity in the failure locus — the $R^2$ of 0.940 is the only available proxy for data quality, not a true measurement-repeatability estimate.
  5. Part (c) — failure axial stress at new confining stresses. Evaluating the fitted line $\sigma_1=3.520\,\sigma_3+104.3$: $$\sigma_3=5\ \text{MPa}:\ \sigma_1=3.520(5)+104.3=\boxed{122.0\ \text{MPa}}$$ $$\sigma_3=15\ \text{MPa}:\ \sigma_1=3.520(15)+104.3=\boxed{157.1\ \text{MPa}}$$ $$\sigma_3=22.5\ \text{MPa}:\ \sigma_1=3.520(22.5)+104.3=\boxed{183.6\ \text{MPa}}$$
  6. Part (d) — verifying the predicted values. Run the three additional triaxial tests (at $\sigma_3=5,15,22.5$ MPa) and compare the measured failure stresses against the predicted 122.0/157.1/183.6 MPa; independently, an unconfined compression test ($\sigma_3=0$) should return a UCS close to the regression intercept of 104.3 MPa, and a direct-shear or Brazilian tensile test ($S_T=C/\tan\phi\approx18.4$ MPa) provides a cross-check on $C$ and $\phi$ from a wholly different loading path.
QuantityResult
(a) Failure-plane angle $\Psi$61.9°
(a) Friction angle $\phi$33.9°
(a) Cohesion $C$27.8 MPa
(a) UCS $S_c$ (intercept)104.3 MPa
(c) $\sigma_1$ at $\sigma_3=5$ MPa122.0 MPa
(c) $\sigma_1$ at $\sigma_3=15$ MPa157.1 MPa
(c) $\sigma_1$ at $\sigma_3=22.5$ MPa183.6 MPa