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18-Geol-A6 Soil Mechanics · December 2014

Question 1 of 6: Classification

Nivaar worked solution (AI-drafted; not reviewed by a licensed engineer)

Notes on this paper

National Exams — December 2014 — 04-Geol-06, Soil Mechanics. Three-hour, closed-book exam; one of two approved calculators permitted. Six questions of equal value (20 marks each, Q6 split 5 marks per sub-part); the paper instructs candidates to answer only the first five questions appearing in the answer book — all six are answered here as a complete study resource.

Reference texts: Das, Principles of Geotechnical Engineering — USCS classification (Q1), phase relations (Q2, Q6d), consolidation theory (Q4), flow nets and seepage (Q5), permeability testing (Q6a/c); Craig, Craig's Soil Mechanics — lateral earth pressure coefficients and limit-equilibrium slope stability (Q3), effective stress and consistency limits (Q6b); EGBC Geoscience Professional Practice Guidelines for assumption-disclosure conventions.

Question 1: Classification (20 marks)

Question text not reproduced: the examination questions are © Engineers and Geoscientists BC. Open the official past paper (linked at the top of this page) to read the question, then follow the worked solution below.

Given. Sieve analysis (percent finer) for Soil A and Soil B (Table Q1); Soil A: $w_L=9\%$, $w_P=7\%$; Soil B: $w_L=70\%$, $w_P=25\%$.

Table Q1 — Percent Finer
Metric SieveUS SieveSoil A (%)Soil B (%)
75 mm3 in100100
50 mm2 in100100
25 mm1 in90100
19 mm0.75 in86100
9.5 mm0.375 in80100
4.76 mmNo. 465100
2.38 mmNo. 850100
0.84 mmNo. 2030100
420 μmNo. 401595
250 μmNo. 601082
150 μmNo. 100980
75 μmNo. 200675

Find. The USCS group symbol for Soil A and for Soil B, with the gradation and plasticity data supporting each.

Approach. Plot both curves on the semi-log grain-size chart, read $D_{10}$, $D_{30}$, $D_{60}$ where needed, split each soil into gravel/sand/fines by the No. 4 and No. 200 sieves, then apply the USCS coarse- or fine-grained branch (gradation coefficients or the plasticity chart / A-line) as appropriate.

0.001 0.01 0.1 1 10 0 10 20 30 40 50 60 70 80 90 100 #200 #4 Particle Size (mm, log scale) Percent Finer (%) Soil A Soil B
Figure Q1 — grain-size distribution curves for Soil A and Soil B, with the No. 200 and No. 4 sieve lines marking the silt–sand and sand–gravel boundaries.
  1. Soil A — split into gravel, sand and fines. Percent finer than the No. 4 sieve (4.76 mm) is 65%, so percent retained on No. 4 (gravel) is $100-65=35\%$. Percent finer than the No. 200 sieve (75 μm) is 6% (fines). Sand is the remainder between the two sieves. $$\text{Gravel}=100-65=\boxed{35\%},\qquad \text{Sand}=65-6=\boxed{59\%},\qquad \text{Fines}=\boxed{6\%}$$ Sand (59%) exceeds gravel (35%), so more than half of the coarse fraction is smaller than 4.76 mm → Soil A is a sand (S). Fines = 6% falls in the 5–12% borderline band, which the USCS chart requires a dual symbol for.
  2. Soil A — gradation coefficients. Reading $D_{10}$, $D_{30}$, $D_{60}$ from the curve (log-linear interpolation between bracketing sieve points): $D_{30}=0.84\text{ mm}$ lands exactly at the No. 20 sieve point (30% finer); $D_{10}=0.25\text{ mm}$ lands exactly at the No. 60 sieve point (10% finer); $D_{60}$ interpolates between the No. 8 (2.38 mm, 50%) and No. 4 (4.76 mm, 65%) points. $$C_u=\frac{D_{60}}{D_{10}}=\frac{3.78}{0.25}=\boxed{15.1},\qquad C_c=\frac{D_{30}^2}{D_{10}D_{60}}=\frac{0.84^2}{0.25\times3.78}=\boxed{0.75}$$ The sand well-graded criteria are $C_u>6$ and $1SP (poorly graded).
  3. Soil A — fines qualifier and final symbol. $I_P=w_L-w_P=9-7=\boxed{2\%}$. With $I_P<4$, the fines plot below the A-line (non-plastic, silt-like) → qualifier M. Combining the borderline fines content (5–12%) with the poorly-graded sand and non-plastic fines gives the dual symbol $$\boxed{\text{Soil A} = SP\text{-}SM}$$ (poorly graded sand with silt).
  4. Soil B — coarse/fine split and plasticity. Percent finer than the No. 200 sieve is 75%, so more than half the sample is finer than 75 μm → Soil B is fine-grained (silt or clay), classified from the Atterberg limits rather than the gradation curve. $I_P=w_L-w_P=70-25=\boxed{45\%}$. The A-line value at $w_L=70\%$ is $$I_{P,\text{A-line}}=0.73(w_L-20)=0.73(70-20)=\boxed{36.5\%}$$ Since $I_P=45\%>36.5\%$, Soil B plots above the A-line, and $w_L=70\%>50\%$ places it in the high-plasticity band.
  5. Soil B — final symbol. Above the A-line with $w_L>50\%$ → inorganic clay of high plasticity. $$\boxed{\text{Soil B} = CH}$$ (fat clay).
QuantityResult
Soil A — $D_{10}$, $D_{30}$, $D_{60}$0.25 mm, 0.84 mm, 3.78 mm
Soil A — $C_u$, $C_c$15.1, 0.75
Soil A — gravel / sand / fines35% / 59% / 6%
Soil A — USCS groupSP-SM
Soil B — $I_P$ / A-line $I_P$45% / 36.5%
Soil B — USCS groupCH
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