Nivaar worked solution (AI-drafted; not reviewed by a licensed engineer)
Notes on this paper
National Exams — 04-Geom-A1 Surveying, May 2019. Closed-book; approved Casio or Sharp calculator permitted. Format: nine (9) questions of varied value totalling 100 marks constitute a complete paper; all nine are solved below. Elevations are referenced to the Canadian vertical frame (CGVD2013) and azimuths to NAD83(CSRS) unless the printed question states otherwise.
Reference texts: Wolf & Ghilani, Elementary Surveying: An Introduction to Geomatics (15th ed., Pearson); Ghilani, Adjustment Computations: Spatial Data Analysis (6th ed., Wiley); Kavanagh & Slattery, Surveying with Construction Applications (8th ed.); Federal Geodetic Control Subcommittee, Standards and Specifications for Geodetic Control Networks (1984).
Question 7: UTM Zone of a Control Point (10 marks)
Given. Latitude $\phi = 43^\circ10'30.205''$ N; longitude $\lambda = 121^\circ30'45.638''$ W (i.e. $\lambda=-121.5127^\circ$).
Find. The UTM zone number (and hemisphere designation) containing BM.1.
A 6°-wide UTM zone: scale factor 0.9996 on the central meridian, unity on the two standard meridians ~180 km either side.
Approach. UTM divides the globe into 60 zones each $6^\circ$ wide, numbered 1–60 eastward from the antimeridian ($180^\circ$W). Apply the zone formula to the longitude.
Extent and hemisphere. Zone 10 spans $126^\circ$W to $120^\circ$W with central meridian $123^\circ$W; $121.5^\circ$W lies within it, $1.5^\circ$ east of the CM. As $\phi$ is north, the designation is Zone 10N (MGRS latitude band T, $40^\circ$–$48^\circ$N).