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18-Geom-A1 Surveying · May 2019

Question 7 of 9: UTM Zone of a Control Point

Nivaar worked solution (AI-drafted; not reviewed by a licensed engineer)

Notes on this paper

National Exams — 04-Geom-A1 Surveying, May 2019. Closed-book; approved Casio or Sharp calculator permitted. Format: nine (9) questions of varied value totalling 100 marks constitute a complete paper; all nine are solved below. Elevations are referenced to the Canadian vertical frame (CGVD2013) and azimuths to NAD83(CSRS) unless the printed question states otherwise.

Reference texts: Wolf & Ghilani, Elementary Surveying: An Introduction to Geomatics (15th ed., Pearson); Ghilani, Adjustment Computations: Spatial Data Analysis (6th ed., Wiley); Kavanagh & Slattery, Surveying with Construction Applications (8th ed.); Federal Geodetic Control Subcommittee, Standards and Specifications for Geodetic Control Networks (1984).

Question 7: UTM Zone of a Control Point (10 marks)

Question text not reproduced: the examination questions are © Engineers and Geoscientists BC. Open the official past paper (linked at the top of this page) to read the question, then follow the worked solution below.

Given. Latitude $\phi = 43^\circ10'30.205''$ N; longitude $\lambda = 121^\circ30'45.638''$ W (i.e. $\lambda=-121.5127^\circ$).

Find. The UTM zone number (and hemisphere designation) containing BM.1.

Central meridian (k = 0.9996)Standard meridians (k = 1)3°W of CMk ≈ 1.00103°E of CMk ≈ 1.0010UTM zone width 6° longitude
A 6°-wide UTM zone: scale factor 0.9996 on the central meridian, unity on the two standard meridians ~180 km either side.

Approach. UTM divides the globe into 60 zones each $6^\circ$ wide, numbered 1–60 eastward from the antimeridian ($180^\circ$W). Apply the zone formula to the longitude.

  1. Longitude in decimal degrees. $$ \lambda = -\left(121 + \tfrac{30}{60} + \tfrac{45.638}{3600}\right) = -121.5127^\circ. $$
  2. Zone number. $$ Z = \left\lfloor \frac{\lambda + 180^\circ}{6^\circ} \right\rfloor + 1 = \left\lfloor \frac{58.4873}{6} \right\rfloor + 1 = 9 + 1 \;\Rightarrow\; \boxed{Z = 10} $$
  3. Extent and hemisphere. Zone 10 spans $126^\circ$W to $120^\circ$W with central meridian $123^\circ$W; $121.5^\circ$W lies within it, $1.5^\circ$ east of the CM. As $\phi$ is north, the designation is Zone 10N (MGRS latitude band T, $40^\circ$–$48^\circ$N).
QuantityValue
Longitude (decimal)$-121.5127^\circ$
UTM zone$10$ (10N)
Central meridian$123^\circ$W
MGRS latitude bandT