NivaarExam PrepOfficial exam papers ↗

23-Ind-A1 Operations Research · Undated paper

Question 2 of 10: LP Formulation — Survey-Company Interview Bid

Nivaar worked solution (AI-drafted; not reviewed by a licensed engineer)

Notes on this paper

National Exams — May 2019 — 17-Ind-A1 Operations Research. Three-hour, open-book exam (any non-communicating calculator permitted); the paper totals 175 marks across 10 questions and only 100 marks are required, so a candidate would normally answer a subset — all ten are solved below for completeness.

Reference texts: Hillier & Lieberman, Introduction to Operations Research (11th ed., McGraw-Hill) — linear programming & the simplex method (ch. 3–4), duality & sensitivity analysis (ch. 6), dynamic programming (ch. 11), network optimization & CPM/PERT project crashing (ch. 9–10), queueing theory incl. finite-source (machine-repair) models (ch. 17), decision analysis & the value of information (ch. 15–16), Markov chains (ch. 16), Monte Carlo simulation (ch. 20). Nahmias, Production and Operations Analysis — deterministic EOQ inventory models with and without planned shortages.

Question 2: LP Formulation — Survey-Company Interview Bid (15 marks)

Question text not reproduced: the examination questions are © Engineers and Geoscientists BC. Open the official past paper (linked at the top of this page) to read the question, then follow the worked solution below.

Given data — cost per interview
PersonalTelephone
Day$2.00$1.00
Night$2.10$1.20

Given. Four interview types (personal/telephone × day/night) at the costs tabulated above; requirements: ≥300 personal interviews overall, ≥500 night interviews overall, day telephone interviews ≥60% of all day interviews, ≥1000 total interviews.

Find. Decision variables and the complete LP model (objective + constraints) for minimum-cost bidding. Do not solve.

Approach. Define one decision variable per (type, time) combination, translate each of the four bullet requirements into a linear constraint, and minimize total interview cost.

  1. Decision variables (number of interviews of each kind, all in units of interviews): $x_{PD}$ = personal interviews, day; $x_{PN}$ = personal interviews, night; $x_{TD}$ = telephone interviews, day; $x_{TN}$ = telephone interviews, night.
  2. Objective — minimize total interview cost: $$\min Z = 2.00x_{PD} + 2.10x_{PN} + 1.00x_{TD} + 1.20x_{TN}$$
  3. Constraint (a) — at least 300 personal interviews (day + night, personal): $$x_{PD}+x_{PN}\ge 300$$ Constraint (b) — at least 500 night interviews (personal + telephone, night): $$x_{PN}+x_{TN}\ge 500$$
  4. Constraint (c) — of the day interviews, ≥60% are by telephone. Day interviews total $x_{PD}+x_{TD}$, of which telephone must be at least 60%: $$x_{TD}\ge 0.6\,(x_{PD}+x_{TD})\ \Longrightarrow\ 0.4x_{TD}-0.6x_{PD}\ge 0\ \Longrightarrow\ \boxed{x_{TD}\ge 1.5\,x_{PD}}$$
  5. Constraint (d) — at least 1000 total interviews and non-negativity: $$x_{PD}+x_{PN}+x_{TD}+x_{TN}\ge 1000,\qquad x_{PD},x_{PN},x_{TD},x_{TN}\ge 0$$
Final results — Question 2 (LP model, not solved)
ItemValue
Decision variables$x_{PD},x_{PN},x_{TD},x_{TN}$ ≥ 0
Objectivemin $2.00x_{PD}+2.10x_{PN}+1.00x_{TD}+1.20x_{TN}$
Constraints$x_{PD}{+}x_{PN}\ge300$; $x_{PN}{+}x_{TN}\ge500$; $x_{TD}\ge1.5x_{PD}$; $\sum x\ge1000$