21-Mat-A4 Deformation Behaviour and Properties of Materials · December 2016
Nivaar worked solution (AI-drafted; not reviewed by a licensed engineer)
Paper format. National Exams, December 2016 — 10-Met-A4, Structure of Materials. Three hours, closed book, one approved calculator (Casio or Sharp). Seven questions of 20 marks each (Roman numerals I–VII); the rubric asks for any five, with only the first five in the answer book marked. All seven are solved here, because this set is a study resource rather than an exam script. All necessary equations, constants and an error-function table are provided in the exam's own appendix (reproduced where used below).
Note on the exam title. The printed exam header reads 10-Met-A4, Structure of Materials. Only Question VI (dislocation theory) is genuinely deformation/mechanical-properties content; the paper as a whole is a broad introductory materials-science survey — electron structure, bonding, crystal structure, crystallographic directions/planes, solid solubility, XRD, microscopy and phase diagrams — and is answered as such below.
Reference texts. The answers below are keyed to the works normally recommended for this syllabus code:
Question text not reproduced: the examination questions are © Engineers and Geoscientists BC. Open the official past paper (linked at the top of this page) to read the question, then follow the worked solution below.
Given. BCC iron; $\{110\}$ peak at $2\theta=44.704^{\circ}$; wavelength $\lambda=0.1541$ nm.
Find. Lattice constant $a$; the diffraction (incidence) angle $\theta$ for $\{211\}$.
Approach. Bragg's law $\lambda=2d\sin\theta$ gives the $\{110\}$ interplanar spacing $d_{110}$; the cubic spacing relation $d_{hkl}=a/\sqrt{h^2+k^2+l^2}$ (appendix) then gives $a$. The same $a$ substituted back into the spacing relation for $\{211\}$, then into Bragg's law, gives the new angle. (Both reflections satisfy the BCC selection rule $h+k+l=$ even: $1{+}1{+}0=2$ and $2{+}1{+}1=4$, so both are genuinely allowed BCC peaks.)
| Quantity | Result |
|---|---|
| $d_{110}$ | 0.2026 nm |
| Lattice constant $a$ | 0.2865 nm |
| $d_{211}$ | 0.1170 nm |
| Incidence angle $\theta_{211}$ | 41.2° |
| SEM | TEM | |
|---|---|---|
| (a) Physical principle | A finely focused electron beam is rastered across the sample surface; secondary and backscattered electrons ejected from near the surface are collected to build a point-by-point image. | A broad, high-energy electron beam is transmitted through an electron-transparent thin foil sample; the transmitted/diffracted beam intensity, magnified by projector lenses, forms the image (analogous to an optical slide projector). |
| (b) Typical electron energy | ∼1–30 keV | ∼100–300 keV (needs enough energy to punch through a thin foil) |
| (c) Resolution / magnification | ∼1–10 nm resolution; up to about 100,000× | ∼0.1–0.2 nm (near-atomic) resolution; up to about 1,000,000× |
| (d) 3-D imaging | Yes — large depth of field gives images with a strongly three-dimensional, topographic appearance. | No — the image is a 2-D projection through the full foil thickness; depth information is lost (though can be partly recovered by tomography/tilt series). |
Sub-surface dislocation activity. TEM is the technique that reveals it. Because the electron beam is transmitted through a (typically 50–200 nm thick) electron-transparent foil, diffraction contrast from the strain field around each dislocation is imaged throughout the foil's full thickness — not just its outer surface — making TEM the standard technique for directly imaging dislocation lines, networks and their evolution under load. SEM, imaging only secondary/backscattered electrons from a shallow near-surface layer, cannot see dislocation structure buried beneath the surface.