22-Mec-A2 Kinematics and Dynamics of Machines · December 2013
Question 2 of 6: Cycloidal radial cam design
Nivaar worked solution (AI-drafted; not reviewed by a licensed engineer)
Notes on this paper
Paper: National Examinations — 07-Mec-A2 Kinematics and Dynamics of Machines, December 2013. Open-book, 3-hour paper; answer FIVE of six questions, all of equal value (20 marks). Part A (mechanisms & machine dynamics, Q1–Q4) and Part B (mechanical vibration, Q5–Q6). All six questions are solved here.
Reference texts: R. L. Norton, Design of Machinery (6th ed., McGraw-Hill) — velocity/acceleration analysis, cams, gear trains, engine balancing; C. E. Wilson & J. P. Sadler, Kinematics and Dynamics of Machinery (3rd ed.); S. S. Rao, Mechanical Vibrations (6th ed., Pearson) — Part B; J. E. Shigley & C. R. Mischke, Mechanical Engineering Design.
Note on the figure-based questions. Q1 (six-bar) is a scaled graphical problem (“Scale 1:5”) with no printed dimensions; its link geometry is read from the drawing, so angular results carry a graphical tolerance of a few percent and the linear accelerations carry the 1:5 length calibration (±5 %). Q3 (planetary box) is solved from the kinematic topology inferred from the sectioned schematic. Both interpretations are stated explicitly with each answer.
Given. Lift $h=20$ mm, $\omega=1000$ rpm $=104.72$ rad/s (constant). Rise angle $\beta_r=120^\circ=2.094$ rad; fall angle $\beta_f=240^\circ=4.189$ rad. Cycloidal (sine-acceleration) programme.
Find. s, v, a, j laws (rise & fall), $a_\mathrm{max}$ and $j_\mathrm{max}$ on the rise, a base-circle radius and profile for a flat-faced follower, and the pressure angles at 60°/240°/300°.
Approach. Write the standard cycloidal laws in the local angle of each segment, differentiate in time via $\dot\theta=\omega$ to get v, a, j, evaluate the closed-form peaks, then size $R_0$ from the flat-faced cusp condition and read off the (identically zero) pressure angle.
Cycloidal rise programme over [0°,120°]: displacement, velocity, acceleration and jerk. s and v are smooth and zero-ended; a is a full sine (zero at both ends); j is a cosine.
Peak acceleration and jerk on the rise. The sine peaks at $\theta=\beta_r/4$: $$a_\mathrm{max}=\frac{2\pi h\omega^{2}}{\beta_r^{2}}=\frac{2\pi(0.020)(104.72)^2}{2.094^2}=\;$$$a_\mathrm{max} = 314\ \text{m/s}^2$. The cosine peaks at the ends: $j_\mathrm{max}=\dfrac{4\pi^{2}h\omega^{3}}{\beta_r^{3}}=$ $9.87\times10^{4}\ \text{m/s}^3$.
Base circle for the flat-faced follower. The instantaneous radius of curvature is $\rho=R_0+s+\dfrac{d^{2}s}{d\theta^{2}}$; to avoid a cusp (undercut) this must stay positive. The minimum of $\left(s+s^{\prime\prime}\right)$ over the cycle is $-10.7$ mm, so $R_0>10.7$ mm; a practical choice with margin is $R_0=40$ mm.
Cam profile for the flat-faced follower generated from the cycloidal lift on a 40 mm base circle (dashed = base circle).
Pressure angles at 60°, 240°, 300°. For a translating flat-faced follower the contact normal is always parallel to the follower axis, so the pressure angle is identically zero at every cam angle: φ(60°) = φ(240°) = φ(300°) = 0°. (The point of contact shifts sideways by $s^{\prime}(\theta)=ds/d\theta$ from the axis, which sets the required minimum face width, but the force direction — hence the pressure angle — never tilts.)