NivaarExam PrepOfficial exam papers ↗

22-Mec-A4 Design and Manufacture of Machine Elements · December 2013

Question 1 of 8: Rib intersections in a cast machine-tool base, and feeding a sand-cast connecting rod

Nivaar worked solution (AI-drafted; not reviewed by a licensed engineer)

Notes on this paper

Paper format. National Examination, 07-Mec-A4 Design and Manufacture of Machine Elements, December 2013 — 3 hours, open book, any non-communicating calculator permitted. Eight questions on six pages, divided into Part A (manufacturing processes, Q1–Q4) and Part B (machine-element design, Q5–Q8). The rubric asks for three questions from Part A and two from Part B, five questions constituting a complete paper, all of equal value (20 % each). All eight questions are solved here.

Reference texts.

Check: Part B is figure-driven. Every dimension used below was read from the printed figures. Two readings are stated explicitly in Given so a grader can substitute a different interpretation without redoing the method: (i) in Figure A the low rivet is taken as lying on the same vertical centreline as the third rivet of the top row (75 + 75 = 150 mm from the left-hand rivet); (ii) in Figure D the dimension \(a\) is the horizontal spacing, measured along the operating lever, between the pin taking the upper shoe link and the pin taking the lower shoe link, with the 10 in operating arm measured from the lower-link pin.

Question 1: Rib intersections in a cast machine-tool base, and feeding a sand-cast connecting rod (20 marks)

Question text not reproduced: the examination questions are © Engineers and Geoscientists BC. Open the official past paper (linked at the top of this page) to read the question, then follow the worked solution below.

Part A — the intersecting-rib hot spot

Wherever two ribs cross, and especially where ribs on opposite faces of the flat cross at the same station, the metal is locally much thicker than the surrounding plate. The governing quantity in solidification is Chvorinov's rule, \(t_s = C\,(V/A)^n\) with \(n \approx 2\): the local solidification time scales with the square of the volume-to-surface-area ratio, so a junction whose inscribed circle is roughly twice the plate thickness takes about four times as long to freeze as the plate around it. That junction is therefore an isolated hot spot. It is the last metal to freeze, it is cut off from any feeder by the already-solid thin plate around it, and it consequently develops a centreline shrinkage cavity (or a cluster of shrinkage porosity) exactly where the designer intended the section to be strongest. A second, related defect appears at the same place: because the junction cools slowly while the surrounding plate is already rigid, the contraction of the junction is restrained and the casting can hot-tear along the fillets radiating from the crossing.

(a) As designed — ribs cross (b) Modifications hot spot — shrinkage cavity Inscribed circle at the junction ≈ 2t; t s ∝ (V/A)² ⇒ ≈ 4× the plate freezing time. Fillets also hot-tear (restrained contraction). 1. Stagger the ribs so no rib on one face lies opposite a rib on the other face. 2. Thin the rib (t rib ≈ 0.7–0.8 t plate), use generous fillets, and core out the junction.
Figure 1.1 — The crossing of ribs on opposite faces creates a locally thick junction (a) that freezes last and cavitates; staggering the ribs and thinning/coring the junction (b) removes the isolated heavy section.

Three modifications, in the order a foundry engineer would try them, are: (1) stagger the ribs so that a rib on the top face never lies directly opposite a rib on the bottom face — this alone halves the junction thickness and usually removes the hot spot entirely; (2) proportion the ribs thinner than the plate, typically \(t_{\text{rib}} \approx 0.7\!-\!0.8\,t_{\text{plate}}\), and blend them with generous fillets so that the inscribed circle at the junction never exceeds the plate thickness; and (3) core out (or dimple) the crossing so the junction becomes a ring of uniform thickness rather than a solid lump. Where geometry forbids all three, a chill placed against the junction will reverse the freezing order locally, and a small blind riser over the junction will feed it — but chilling and feeding are corrections applied because the design has failed the uniform-section rule, not substitutes for it.

Part B — feeding a sand-cast connecting rod

A connecting rod is the classic "two heavy ends joined by a thin bar" casting. Its two defects have different physics and therefore different remedies.

(I) Remedy for the heads — cavities. The heads are the heaviest sections; they freeze last and shrink about 3–4 % by volume on solidification, so with no external supply of liquid the shrinkage is taken internally as a cavity. The remedy is to place a riser (feeder) directly on each head, sized so that its modulus exceeds the head's modulus (a common rule is \(M_{\text{riser}} \ge 1.2\,M_{\text{casting section}}\)), so the riser stays liquid longer and pays the head's shrinkage into it.

(II) Two remedies for the shank — porosity. The shank is thin, freezes first, and is starved: it is both cut off from the risers (so it draws micro-shrinkage) and, being the last region to be filled, it traps evolved gas. Two independent fixes are:

riser riser chills shank tapered thicker towards each head → directional solidification freezing front runs this way ⟶ into the riser
Figure 1.2 — Risers on the two heavy heads pay their shrinkage; tapering the shank and chilling it forces solidification to run from mid-shank towards the risers instead of isolating pockets of liquid.
← Paper overview