22-Mec-A7 Advanced Strength of Materials · December 2013
Question 5 of 7: Thick-Walled Cylinder — von Mises and Tresca Pressure Limits
Nivaar worked solution (AI-drafted; not reviewed by a licensed engineer)
Notes on this paper
Paper format: National Exams, December 2013 — 07-Mech-A7 Advanced Strength of Materials. Open-book, 3 hours; any five of the seven problems constitute a complete paper and all problems are of equal value. All seven problems are solved as a study resource.
Reference texts. R.C. Hibbeler, Mechanics of Materials, 10th ed. (thermal & indeterminate axial members Ch. 4, plane stress/strain Ch. 9–10, energy methods Ch. 14); A.P. Boresi & R.J. Schmidt, Advanced Mechanics of Materials, 6th ed. (thick-walled cylinders Ch. 11, thin-walled open sections & torsional buckling Ch. 6&12); J.M. Gere & B.J. Goodno, Mechanics of Materials (strain rosettes, columns). Yield criteria follow the von Mises and Tresca formulations standard to these texts.
Question 5: Thick-Walled Cylinder — von Mises and Tresca Pressure Limits (20 marks)
Given. A closed thick cylinder with a fixed pressure ratio pi = 4.5 pe, sized by yield at the bore.
Given data
Radii
a = 60 mm (bore), b = 85 mm (outer)
Material
Elastic limit σY = 300 MPa, ν = 0.3
Loading
pi = 4.5 pe (internal / external pressure)
Assumption
Closed ends ⇒ σz = (σr+σθ)/2 (intermediate principal stress)
Find. The allowable internal pressure pi from (a) von Mises and (b) maximum-shear (Tresca).
Bore radius a, outer radius b; internal pressure pi, external pe = pi/4.5. Yield governs at r = a.
Approach. Lamé’s solution gives σr, σθ, and σz = (σr+σθ)/2 as multiples of pi at the most-stressed point (the bore). Setting each yield criterion equal to σY gives the allowable pi.
Lamé constants. With pe = pi/4.5, a2 = 3600, b2 = 7225,
$$A=\frac{p_ia^{2}-p_eb^{2}}{b^{2}-a^{2}}=0.5502\,p_i,\qquad B=\frac{(p_i-p_e)a^{2}b^{2}}{b^{2}-a^{2}}=5582\,p_i.$$
Principal stresses at the bore (r = a).
$$\sigma_\theta=A+\tfrac{B}{a^{2}}=2.100\,p_i,\qquad \sigma_r=A-\tfrac{B}{a^{2}}=-p_i,\qquad \sigma_z=A=0.550\,p_i.$$
Maximum-shear (Tresca) criterion (part b). The extreme principal stresses are σθ and σr:
$$\sigma_\theta-\sigma_r=3.100\,p_i=\sigma_Y\ \Longrightarrow\ \boxed{p_i=\frac{300}{3.100}=96.8\ \text{MPa}.}$$
von Mises criterion (part a). With all three principal stresses,
$$\sigma_{vM}=\sqrt{\tfrac12\big[(\sigma_\theta-\sigma_r)^2+(\sigma_r-\sigma_z)^2+(\sigma_z-\sigma_\theta)^2\big]}=2.685\,p_i=\sigma_Y,$$
$$\boxed{p_i=\frac{300}{2.685}=111.7\ \text{MPa}.}$$
Compare. von Mises permits about 15 % more pressure than Tresca (111.7 vs 96.8 MPa); the maximum-shear criterion is the more conservative (safe) design value. The corresponding external pressures are pe = 24.8 MPa and 21.5 MPa.