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22-Mec-A7 Advanced Strength of Materials · December 2013

Question 5 of 7: Thick-Walled Cylinder — von Mises and Tresca Pressure Limits

Nivaar worked solution (AI-drafted; not reviewed by a licensed engineer)

Notes on this paper

Paper format: National Exams, December 2013 — 07-Mech-A7 Advanced Strength of Materials. Open-book, 3 hours; any five of the seven problems constitute a complete paper and all problems are of equal value. All seven problems are solved as a study resource.

Reference texts. R.C. Hibbeler, Mechanics of Materials, 10th ed. (thermal & indeterminate axial members Ch. 4, plane stress/strain Ch. 9–10, energy methods Ch. 14); A.P. Boresi & R.J. Schmidt, Advanced Mechanics of Materials, 6th ed. (thick-walled cylinders Ch. 11, thin-walled open sections & torsional buckling Ch. 6&12); J.M. Gere & B.J. Goodno, Mechanics of Materials (strain rosettes, columns). Yield criteria follow the von Mises and Tresca formulations standard to these texts.

Question 5: Thick-Walled Cylinder — von Mises and Tresca Pressure Limits (20 marks)

Question text not reproduced: the examination questions are © Engineers and Geoscientists BC. Open the official past paper (linked at the top of this page) to read the question, then follow the worked solution below.

Given. A closed thick cylinder with a fixed pressure ratio pi = 4.5 pe, sized by yield at the bore.

Given data
Radiia = 60 mm (bore), b = 85 mm (outer)
MaterialElastic limit σY = 300 MPa, ν = 0.3
Loadingpi = 4.5 pe (internal / external pressure)
AssumptionClosed ends ⇒ σz = (σr+σθ)/2 (intermediate principal stress)

Find. The allowable internal pressure pi from (a) von Mises and (b) maximum-shear (Tresca).

b=85 a=60 pi
Bore radius a, outer radius b; internal pressure pi, external pe = pi/4.5. Yield governs at r = a.

Approach. Lamé’s solution gives σr, σθ, and σz = (σr+σθ)/2 as multiples of pi at the most-stressed point (the bore). Setting each yield criterion equal to σY gives the allowable pi.

  1. Lamé constants. With pe = pi/4.5, a2 = 3600, b2 = 7225, $$A=\frac{p_ia^{2}-p_eb^{2}}{b^{2}-a^{2}}=0.5502\,p_i,\qquad B=\frac{(p_i-p_e)a^{2}b^{2}}{b^{2}-a^{2}}=5582\,p_i.$$
  2. Principal stresses at the bore (r = a). $$\sigma_\theta=A+\tfrac{B}{a^{2}}=2.100\,p_i,\qquad \sigma_r=A-\tfrac{B}{a^{2}}=-p_i,\qquad \sigma_z=A=0.550\,p_i.$$
  3. Maximum-shear (Tresca) criterion (part b). The extreme principal stresses are σθ and σr: $$\sigma_\theta-\sigma_r=3.100\,p_i=\sigma_Y\ \Longrightarrow\ \boxed{p_i=\frac{300}{3.100}=96.8\ \text{MPa}.}$$
  4. von Mises criterion (part a). With all three principal stresses, $$\sigma_{vM}=\sqrt{\tfrac12\big[(\sigma_\theta-\sigma_r)^2+(\sigma_r-\sigma_z)^2+(\sigma_z-\sigma_\theta)^2\big]}=2.685\,p_i=\sigma_Y,$$ $$\boxed{p_i=\frac{300}{2.685}=111.7\ \text{MPa}.}$$
  5. Compare. von Mises permits about 15 % more pressure than Tresca (111.7 vs 96.8 MPa); the maximum-shear criterion is the more conservative (safe) design value. The corresponding external pressures are pe = 24.8 MPa and 21.5 MPa.
Results — Question 5
CriterionAllowable piCorresponding pe
von Mises111.7 MPa24.8 MPa
Maximum shear (Tresca)96.8 MPa21.5 MPa