22-Mec-A7 Advanced Strength of Materials · Undated paper
Nivaar worked solution (AI-drafted; not reviewed by a licensed engineer)
Paper format: National Exam — 16-Mec-A7 Advanced Strength of Materials (May 2019). Open-book; eight problems of equal value; any five constitute a complete paper. Every problem is solved as a study resource.
Reference texts: Boresi & Schmidt, Advanced Mechanics of Materials (6th ed.); Ugural & Fenster, Advanced Strength and Applied Elasticity; Timoshenko & Goodier, Theory of Elasticity; Hibbeler, Mechanics of Materials.
Question text not reproduced: the examination questions are © Engineers and Geoscientists BC. Open the official past paper (linked at the top of this page) to read the question, then follow the worked solution below.
Given. A semicircular curved cantilever, fixed at end B and free at end A, carries a horizontal force P at A. Its horizontal extension at A is limited to 0.1 mm.
| Mean radius, R | 510 mm |
| Second moment of area, I | $815\times10^{6}\ \text{mm}^4$ |
| Young's modulus, E | 205 GPa |
| Load line | horizontal at free end A |
| Limit on horizontal deflection at A | 0.1 mm |
Find. (a) the largest admissible P; (b) the magnitude and direction of the accompanying vertical deflection at A.
Approach. Use Castigliano's second theorem — only bending energy is retained for a slender arc — taking the bending moment as a function of the polar angle and integrating around the semicircle; a dummy vertical load at A extracts the vertical deflection.
The two deflections are locked in the ratio $\delta_V/\delta_H=4/\pi=1.273$, so limiting the horizontal movement automatically fixes the vertical one. The vertical component comes out positive in the direction of the upward dummy load, i.e. point A rises as the arc straightens under the pull.
| Allowable load, P | 80.2 kN |
| Vertical deflection at A | 0.127 mm, upward |
| Ratio $\delta_V/\delta_H$ | $4/\pi=1.273$ |