22-Mec-A7 Advanced Strength of Materials · Undated paper
Question 8 of 8: Thick cylinder: Tresca vs Von Mises
Nivaar worked solution (AI-drafted; not reviewed by a licensed engineer)
Notes on this paper
Paper format: National Exam — 16-Mec-A7 Advanced Strength of Materials (May 2019). Open-book; eight problems of equal value; any five constitute a complete paper. Every problem is solved as a study resource.
Reference texts: Boresi & Schmidt, Advanced Mechanics of Materials (6th ed.); Ugural & Fenster, Advanced Strength and Applied Elasticity; Timoshenko & Goodier, Theory of Elasticity; Hibbeler, Mechanics of Materials.
Question 8: Thick cylinder: Tresca vs Von Mises (20 marks)
Approach. Evaluate the Lamé stresses at the inner wall (the critical radius), take the closed-end axial stress as the mean of radial and hoop, then apply each yield criterion at first yield.
Lamé stresses at the bore. With $r_i=55$, $r_o=87.5$ mm and $p_e=p_i/8$, $$\sigma_\theta=1.893\,p_i,\qquad \sigma_r=-p_i,\qquad \sigma_z=\tfrac12(\sigma_\theta+\sigma_r)=0.447\,p_i\ \text{(closed end)}.$$
Maximum-shear (Tresca). The extreme principals are $\sigma_\theta$ and $\sigma_r$, so $\sigma_\theta-\sigma_r=\sigma_Y$ gives $$2.893\,p_i=289\ \Rightarrow\ \boxed{p_i=99.9\ \text{MPa}}.$$
Von Mises. For $\sigma_z$ equal to the mean, $\sigma_{vM}=\tfrac{\sqrt3}{2}(\sigma_\theta-\sigma_r)=\sigma_Y$, hence $$p_i=\frac{289}{2.505}=\boxed{115.4\ \text{MPa}}.$$
Check: The source states neither a factor of safety nor the end condition. The closed-end assumption (σz = mean) is adopted, and "allowable" is taken as the first-yield pressure. If a factor of safety N is required, divide both results by N; an open-end vessel (σz = 0) would instead give pi,Tresca unchanged and a slightly higher Von Mises value.
Von Mises permits about 15% more pressure than Tresca — the fixed factor 2/√3 that always separates the two criteria when the axial stress is the intermediate principal. Tresca is the conservative choice for a code-compliant design.