22-Mec-B2 Environmental Control in Buildings · December 2014
Question 1 of 8: Summer air conditioning of a clothing store
Nivaar worked solution (AI-drafted; not reviewed by a licensed engineer)
Notes on this paper
Paper format. Professional Engineers of
Ontario / Engineers Canada annual examination, 07-Mec-B2 Environmental Control
in Buildings, December 2014. Three hours, open book, any non-communicating
calculator. Eight problems of 20 points each; candidates are required to solve
five. ASHRAE psychrometric charts (SI and IP) and an HFC-134a
pressure-enthalpy diagram are attached to the paper. All eight problems are
solved here.
Reference texts.
ASHRAE, Handbook — Fundamentals (Ch. 1 Psychrometrics, Ch. 16
Ventilation and Infiltration, Ch. 18 Nonresidential Cooling and Heating Load
Calculations, Ch. 19 Energy Estimating, Ch. 21 Duct Design).
McQuiston, Parker & Spitler, Heating, Ventilating and Air Conditioning:
Analysis and Design, 6th ed., Wiley.
W. P. Jones, Air Conditioning Engineering, 5th ed., Butterworth-Heinemann.
Stoecker & Jones, Refrigeration and Air Conditioning, 2nd ed., McGraw-Hill.
Carrier Air Conditioning Company, Handbook of Air Conditioning System
Design, Part 1 (the ESHF / apparatus-dew-point method used in Problem 1).
CSA B52 Mechanical Refrigeration Code; Canada's Ozone-depleting
Substances and Halocarbon Alternatives Regulations (SOR/2016-137); National
Building Code of Canada (vapour and air barriers).
Reading the numbers. Chart properties here are
computed from the ASHRAE psychrometric formulations rather than scaled off the
printed chart, so a candidate working graphically should expect agreement to about
the width of a pencil line — roughly ±0.3 °F on a dew point and
±1 % on a humidity ratio.
Question 1: Summer air conditioning of a clothing store (20 points)
Given. A direct-expansion plant serving one retail zone, with the room and outdoor design states fixed and the load already split into room and outdoor-air components.
Given data — Problem 1
Quantity
Symbol
Value
Outdoor design state
$t_o$ / $t_{wb,o}$
$100^\circ\text{F}$ DB / $78^\circ\text{F}$ WB
Room design state
$t_r$ / RH
$75^\circ\text{F}$ DB / 50 % RH
Room sensible heat
RSH
265,000 Btu/hr
Outdoor-air sensible heat
OASH
90,500 Btu/hr
Room latent heat
RLH
71,500 Btu/hr
Outdoor-air latent heat
OALH
102,500 Btu/hr
Ventilation outdoor air
$\dot V_o$
3,500 cfm
Coil bypass factor
BF
0.084
Find. The room and grand sensible heat factors, the room and coil apparatus dew points, the supply and mixed-air temperatures, the total supply air quantity, the rate of moisture removed at the coil, and the refrigeration duty in tons.
Problem 1 — the plant plotted on the IP psychrometric chart. Outdoor air O mixes with return air at R to give the coil entering state M; the coil drives the air toward its apparatus dew point and delivers S, which picks up the room load back to R. The grey dashed line is the 50 % RH curve on which the room state sits.
Approach. Fix O and R from the chart, form the room sensible heat factor to locate the room apparatus dew point, then form the effective sensible heat factor — which charges the bypassed share of the outdoor-air load to the room — to locate the coil apparatus dew point, and read the supply air quantity, supply temperature, mixing state, moisture removal and refrigeration duty from that geometry.
Fix the two design states on the chart. At $75^\circ\text{F}$ and 50 % RH the room humidity ratio and enthalpy are $W_r = 0.00924\ \text{lb}/\text{lb}$ and $h_r = 28.11\ \text{Btu}/\text{lb}$. At $100^\circ\text{F}$ DB with a $78^\circ\text{F}$ wet bulb the outdoor state is $W_o = 0.01560\ \text{lb}/\text{lb}$, $h_o = 41.25\ \text{Btu}/\text{lb}$. These two points anchor everything that follows.
(a) Form the sensible heat factors. The room condition line is set by the loads the room itself sees, $$\mathrm{RSHF}=\frac{\mathrm{RSH}}{\mathrm{RSH}+\mathrm{RLH}}=\frac{265{,}000}{265{,}000+71{,}500}=\boxed{0.788}$$ while the coil, which also handles the ventilation load, works on the grand sensible heat factor $\mathrm{GSHF}=355{,}500/529{,}500=0.671$. Both are quoted because the question asks for “the SHF” and the two describe different lines on the chart.
(b) Locate the room apparatus dew point. Drawing the RSHF line through R until it meets the saturation curve gives $$t_{\mathrm{ADP},\ \mathrm{room}} = \boxed{50.3^\circ\text{F}}$$ This is the coil surface temperature that a system handling only the room load would need.
Charge the bypassed outdoor air to the room. A fraction BF of the air passes the coil untreated, so that share of the outdoor-air load arrives in the space. The effective room loads are $\mathrm{ERSH} = \mathrm{RSH} + \mathrm{BF}\cdot\mathrm{OASH} = 265{,}000 + 0.084(90{,}500) = 272{,}602\ \text{Btu}/\text{hr}$ and $\mathrm{ERLH} = 71{,}500 + 0.084(102{,}500) = 80{,}110\ \text{Btu}/\text{hr}$, whence $\mathrm{ESHF} = 272{,}602/352{,}712 = 0.773$.
(f) Coil apparatus dew point. The ESHF line drawn through R meets saturation at $$t_{\mathrm{ADP},\ \mathrm{coil}} = \boxed{49.7^\circ\text{F}}$$ slightly below the room ADP, which is the whole point of the effective-factor construction: the coil must run a little colder than the room line alone suggests because part of the outdoor air slips past it.
(d) Supply air quantity. With the apparatus dew point known, the air quantity follows from the effective room sensible heat, $$\dot V = \frac{\mathrm{ERSH}}{1.10\,(1-\mathrm{BF})\,(t_r - t_{\mathrm{ADP}})} = \frac{272{,}602}{1.10(0.916)(75-49.72)} = \boxed{10{,}700\ \text{cfm}}$$ of which 3,500 cfm is outdoor air and the remaining 7,204 cfm is recirculated.
(c) Temperature of the air leaving the coil. The supply air must remove the room sensible heat between S and R, $$t_s = t_r - \frac{\mathrm{RSH}}{1.10\,\dot V} = 75 - \frac{265{,}000}{1.10(10{,}704)} = \boxed{52.5^\circ\text{F}}$$ As an independent check, the bypass-factor definition gives the same answer from the other direction: $t_s = t_{\mathrm{ADP}} + \mathrm{BF}\,(t_m - t_{\mathrm{ADP}}) = 49.72 + 0.084(83.17-49.72) = 52.5^\circ\text{F}$. The two routes agreeing is the proof that the ESHF chain has been built correctly.
(e) Mixed air entering the coil. Mixing 3,500 cfm of outdoor air with 7,204 cfm of return air, $$t_m = \frac{3{,}500(100)+7{,}204(75)}{10{,}704} = \boxed{83.2^\circ\text{F}}$$ with a mixed humidity ratio $W_m = 0.01132\ \text{lb}/\text{lb}$.
(g) Moisture removal. The supply humidity ratio follows from the room latent load, $W_s = W_r - \mathrm{RLH}/(4{,}840\,\dot V) = 0.00786\ \text{lb}/\text{lb}$. Standard air at 10,704 cfm carries $\dot m_{da} = 60(10{,}704)(0.075) = 48{,}168\ \text{lb}/\text{hr}$ of dry air, so the coil condenses $$\dot m_w = \dot m_{da}\,(W_m - W_s) = 48{,}168\,(0.01132-0.00786) = \boxed{167\ \text{lb}/\text{hr}}$$
(h) Refrigeration duty. The coil must handle the grand total heat, $\mathrm{GTH} = 355{,}500+174{,}000 = 529{,}500\ \text{Btu}/\text{hr}$, so $$\mathrm{Tons} = \frac{529{,}500}{12{,}000} = \boxed{44.1\ \text{tons}}$$
Check: two defensible values for the moisture removal. Taking the difference of the chart humidity ratios across the coil gives 167 lb/hr. Working instead from the paper's own stated total latent load, $174{,}000/1{,}076 = 162\ \text{lb}/\text{hr}$. The 3 % gap exists because the tabulated outdoor-air latent load implies an outdoor state marginally drier than 100°F DB / 78°F WB actually is. The chart-state value is reported because parts (a)–(f) are all built on the chart states; either is creditable if the assumption is stated, as cover-page instruction 1 invites.
The design that emerges is conventional for a retail space of this size: a 44-ton direct-expansion plant, about 10,700 cfm of supply air of which roughly one third is outdoor air, and a coil surface running near 50°F. What the problem is really testing is the discipline of the effective sensible heat factor. A candidate who sizes the airflow from the room load alone, ignoring the bypassed outdoor air, arrives at about 9,900 cfm and a coil that cannot hold 50 % relative humidity in the space on a design day — a failure mode that shows up as summer humidity complaints rather than as a temperature complaint, and is correspondingly hard to diagnose after the fact.