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24-MMP-B1 Applied Rock Mechanics · May 2014

Question 1 of 6: Direct Shear Box Test on a Planar Discontinuity

Nivaar worked solution (AI-drafted; not reviewed by a licensed engineer)

Notes on this paper

EGBC National Exam — Mining and Mineral Processing Engineering, 09-MMP-B1 Applied Rock Mechanics, 2014-May. 3 hours duration, open-book exam, any non-communicating calculator permitted.

Reference texts: Brady & Brown, Rock Mechanics for Underground Mining, 3rd ed. (direct shear and triaxial testing, Mohr-Coulomb and Hoek-Brown failure criteria, pillar design, Kirsch elastic-boundary-stress solution); Wyllie & Mah, Rock Slope Engineering (after Hoek & Bray), 4th ed. (plane failure analysis, tension-crack water pressure, rock-bolt slope reinforcement); Hoek, Kaiser & Bawden, Support of Underground Excavations in Hard Rock (mechanical point anchors, friction bolts, surface support systems); Hoek, Practical Rock Engineering (Hoek-Brown criterion background and worked plane-failure methodology).

Question 1: Direct Shear Box Test on a Planar Discontinuity (20 marks)

Question text not reproduced: the examination questions are © Engineers and Geoscientists BC. Open the official past paper (linked at the top of this page) to read the question, then follow the worked solution below.

1.1 — Shear stress–displacement response; peak and residual strength

Given. Sample 1 was tested at a constant normal stress σn = 200 kPa. The shear-box recorder gives ten (shear displacement, shear stress) pairs over the course of the test.

Direct shear box test — Sample 1 (σn = 200 kPa)
Shear displacement (mm)Shear stress (kPa)
0.05138
1.21186
3.52238
4.32234
8.78223
9.48206
11.56205
12.64199
17.54168
22.11168

Find. The peak shear strength and the residual (steady-state) shear strength of the discontinuity at this normal stress.

04812162024052104156208260Shear displacement (mm)Shear stress (kPa)peak = 238 kParesidual = 168 kPa
Shear stress vs. shear displacement, Sample 1 (σn = 200 kPa). Stress rises to a well-defined peak at small displacement, then softens and levels to a constant residual value at large displacement.

Approach. Read the maximum ordinate as the peak strength and the ordinate of the flat, displacement-independent tail as the residual strength.

  1. Identify the peak. The curve rises steeply from 138 kPa at 0.05 mm displacement to a maximum of $\tau_{peak}=238\ \text{kPa}$ at 3.52 mm displacement, then softens (234, 223, 206, 205, 199 kPa) as the discontinuity dilates and asperities shear off.
  2. Identify the residual. Beyond about 17 mm of displacement the stress has fallen to a constant plateau: $\tau=168\ \text{kPa}$ at both 17.54 mm and 22.11 mm, two consecutive readings identical to three significant figures, so $\boxed{\tau_{residual}=168\ \text{kPa}}$ is taken as the post-peak, fully-softened (residual) shear strength once asperities are worn flat and only frictional sliding on a smooth surface remains.
Question 1.1 — peak and residual shear strength at σn = 200 kPa
QuantityValue
Peak shear strength, τpeak238 kPa (at 3.52 mm displacement)
Residual shear strength, τresidual168 kPa (plateau beyond ≈17.5 mm)

1.2 — Peak/residual strength vs. normal stress; friction angles

Given. A single normal-stress level was tested, σn = 200 kPa, giving one (σn, τpeak) point at (200, 238) kPa and one (σn, τresidual) point at (200, 168) kPa.

Find. The peak and residual friction angles of the discontinuity.

Check: with only ONE normal-stress level tested, a Mohr-Coulomb line ($\tau = c' + \sigma_n\tan\phi'$) cannot be fitted uniquely from the data alone — two unknowns (c′, φ′) need two independent points. The standard assumption for a clean, planar, weathered-granite discontinuity with no significant infill is that cohesion is negligible, $c'=0$, so the strength envelope is a straight line through the origin. This is stated explicitly as the required assumption (per the question's own instruction to "note any assumptions").
050100150200250052104156208260Normal stress, sigma_n (kPa)Shear strength, tau (kPa)peak: phi'p = 50.0 deg (c=0)residual: phi'r = 40.0 deg (c=0)
Peak and residual shear strength vs. normal stress, with the assumed c′=0 envelope through the origin fitted to the single test point at σn=200 kPa.

Approach. With c′=0, the Mohr-Coulomb relation reduces to $\tau=\sigma_n\tan\phi'$, so each friction angle follows directly from $\phi'=\tan^{-1}(\tau/\sigma_n)$ at the single tested point.

  1. Peak friction angle. $\phi'_{peak}=\tan^{-1}\!\left(\dfrac{\tau_{peak}}{\sigma_n}\right)=\tan^{-1}\!\left(\dfrac{238}{200}\right)=\tan^{-1}(1.190)=\boxed{49.96^\circ\approx 50^\circ}$.
  2. Residual friction angle. $\phi'_{residual}=\tan^{-1}\!\left(\dfrac{\tau_{residual}}{\sigma_n}\right)=\tan^{-1}\!\left(\dfrac{168}{200}\right)=\tan^{-1}(0.840)=\boxed{40.03^\circ\approx 40^\circ}$. The 10° drop from peak to residual is consistent with wearing-down of the surface roughness (dilation) component of strength once the asperities have sheared through.
Question 1 — summary
QuantityValue
Peak shear strength (σn=200 kPa)238 kPa
Residual shear strength (σn=200 kPa)168 kPa
Peak friction angle, φ′peak (c′=0 assumed)≈50.0°
Residual friction angle, φ′residual (c′=0 assumed)≈40.0°
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