Question 2 of 6: Triaxial Testing of Intact Granite — Mohr-Coulomb and Hoek-Brown Criteria
Nivaar worked solution (AI-drafted; not reviewed by a licensed engineer)
Notes on this paper
EGBC National Exam — Mining and Mineral Processing Engineering, 09-MMP-B1 Applied Rock Mechanics, 2014-May. 3 hours duration, open-book exam, any non-communicating calculator permitted.
Reference texts: Brady & Brown, Rock Mechanics for Underground Mining, 3rd ed. (direct shear and triaxial testing, Mohr-Coulomb and Hoek-Brown failure criteria, pillar design, Kirsch elastic-boundary-stress solution); Wyllie & Mah, Rock Slope Engineering (after Hoek & Bray), 4th ed. (plane failure analysis, tension-crack water pressure, rock-bolt slope reinforcement); Hoek, Kaiser & Bawden, Support of Underground Excavations in Hard Rock (mechanical point anchors, friction bolts, surface support systems); Hoek, Practical Rock Engineering (Hoek-Brown criterion background and worked plane-failure methodology).
Question 2: Triaxial Testing of Intact Granite — Mohr-Coulomb and Hoek-Brown Criteria (20 marks)
Given. Five triaxial tests on intact granite specimens, confining pressure σ3 from 5 to 25 MPa:
Triaxial test results, intact granite
σ3 (MPa)
σ1 (MPa)
5
255
10
310
15
375
20
420
25
446
σ1 vs. σ3 test data with fitted Mohr-Coulomb straight line and fitted Hoek-Brown curve.
2.1 — Mohr-Coulomb parameters and applicability
Find. The Mohr-Coulomb cohesion and friction angle from a least-squares fit of σ1 vs. σ3, and a comment on how well the linear criterion represents the data.
Approach. The Mohr-Coulomb failure envelope, expressed in principal-stress space, is the straight line $\sigma_1=\sigma_c+\sigma_3\tan^2\!\left(45^\circ+\tfrac{\phi'}{2}\right)$, where σc is the intercept (uniaxial compressive strength) and the slope gives the friction angle. Fit this line to the five points by least squares.
Least-squares slope and intercept. With $\bar\sigma_3=15$, $\bar\sigma_1=361.2$, $\sum\sigma_3\sigma_1=29{,}550$, $\sum\sigma_3^2=1375$ ($n=5$): slope $=\dfrac{n\sum\sigma_3\sigma_1-\sum\sigma_3\sum\sigma_1}{n\sum\sigma_3^2-(\sum\sigma_3)^2}=\dfrac{5(29{,}550)-75(1806)}{5(1375)-75^2}=\dfrac{12{,}300}{1250}=9.84$; intercept $=\bar\sigma_1-\text{slope}\cdot\bar\sigma_3=361.2-9.84(15)=213.6$. So $\sigma_1=213.6+9.84\,\sigma_3$ (MPa), giving the uniaxial compressive strength $\boxed{\sigma_c=213.6\ \text{MPa}}$.
Friction angle and cohesion. $\tan^2(45^\circ+\phi'/2)=9.84\Rightarrow 45^\circ+\phi'/2=\tan^{-1}\sqrt{9.84}=\tan^{-1}(3.137)=72.32^\circ\Rightarrow\boxed{\phi'=54.6^\circ}$. Cohesion follows from $\sigma_c=\dfrac{2c'\cos\phi'}{1-\sin\phi'}\Rightarrow c'=\dfrac{\sigma_c(1-\sin\phi')}{2\cos\phi'}=\dfrac{213.6(1-0.8154)}{2(0.5789)}=\boxed{34.0\ \text{MPa}}$.
Goodness of fit and applicability. The fitted line predicts σ1 = 262.8, 312.0, 361.2, 410.4, 459.6 MPa against the measured 255, 310, 375, 420, 446 MPa — a coefficient of determination $R^2=0.978$. The fit is good but systematically biased: it over-predicts strength at both ends of the tested range (262.8 fitted vs. 255 measured at σ3=5 MPa; 459.6 vs. 446 at σ3=25 MPa) and under-predicts in the middle (361.2 vs. 375 at σ3=15 MPa) — the classic signature of forcing a straight line through a data set that is genuinely curved (concave-down) in σ1–σ3 space, as intact rock strength envelopes almost always are. Mohr-Coulomb is therefore an adequate local linear approximation over this confining-stress range but is not the more fundamentally correct description of intact rock strength — see 2.2.
Question 2.1 — Mohr-Coulomb fit
Quantity
Value
Uniaxial compressive strength, σc
213.6 MPa
Friction angle, φ′
54.6°
Cohesion, c′
34.0 MPa
R² of linear fit
0.978
2.2 — Hoek-Brown criterion and applicability
Find. The Hoek-Brown intact-rock parameters σci and mi, and a comment on the criterion's applicability relative to Mohr-Coulomb.
Approach. For intact rock (s=1), the Hoek-Brown criterion $\sigma_1=\sigma_3+\sqrt{m_i\sigma_{ci}\sigma_3+\sigma_{ci}^2}$ is linearised by squaring: $(\sigma_1-\sigma_3)^2=m_i\sigma_{ci}\,\sigma_3+\sigma_{ci}^2$, a straight line in $\sigma_3$ vs. $(\sigma_1-\sigma_3)^2$ whose intercept is $\sigma_{ci}^2$ and whose slope is $m_i\sigma_{ci}$.
Transform and fit. $(\sigma_1-\sigma_3)^2$ = 62{,}500; 90{,}000; 129{,}600; 160{,}000; 177{,}241 at σ3 = 5, 10, 15, 20, 25 MPa. Least squares gives slope $=5989.6$, intercept $=34{,}024$, so $\boxed{\sigma_{ci}=\sqrt{34{,}024}=184.5\ \text{MPa}}$ and $\boxed{m_i=5989.6/184.5=32.5}$.
Sanity-check against published data. Hoek's tabulated $m_i$ for granite is $32\pm3$ — the fitted $m_i=32.5$ falls almost exactly on the published mean, a strong independent confirmation that the fit is physically sound and not an artefact of only five points.
Goodness of fit and applicability. The fitted curve predicts σ1 = 257.9, 316.5, 366.9, 412.2, 453.7 MPa against measured 255, 310, 375, 420, 446 MPa, $R^2=0.990$ (computed in σ1 space, on the same basis as the 0.978 quoted for Mohr-Coulomb above, so that the two are directly comparable; the linearised $(\sigma_1-\sigma_3)^2$ vs. σ3 regression used to obtain the parameters has its own $R^2=0.986$) — a closer match than the Mohr-Coulomb line at both ends of the tested range (σ3=5 and 25 MPa), because the Hoek-Brown power-law form directly reproduces the concave-down curvature (diminishing strength gain per unit increase in confinement) that a straight line cannot. For intact, unweathered granite tested over a wide confining-stress range, the Hoek-Brown criterion is therefore the more applicable and more widely recommended failure criterion; Mohr-Coulomb remains useful as a locally linearised approximation (e.g. for hand slope-stability calculations at a known, narrow stress range, as used with a single c′/φ′ pair in Questions 3 and 6 of this exam).
Question 2.2 — Hoek-Brown fit
Quantity
Value
Intact uniaxial strength, σci
184.5 MPa
Material constant, mi
32.5
R² of Hoek-Brown fit (in σ1 space)
0.990
Preferred criterion for this data set
Hoek-Brown (better fit, correct curvature, mi matches published granite value)