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24-MMP-B2 Rock Fragmentation · December 2016

Question 6 of 6: Quarry Blast Vibration-Compliant Loading Design

Nivaar worked solution (AI-drafted; not reviewed by a licensed engineer)

Notes on this paper

National Exams, 09-Mmp-B2 Rock Fragmentation, December 2016, 3 hours, closed book (one double-sided aid sheet permitted). Question 1 plus four (4) of Questions 2-6 constitute a complete paper; every question (1-6) is answered in full as a complete study resource.

Reference texts: Persson, Holmberg & Lee, Rock Blasting and Explosives Engineering; C.J. Konya & E.J. Walter, Rock Blasting and Overbreak Control (FHWA); ISEE, Blasters' Handbook, 18th ed.; W. Hustrulid, Blasting Principles for Open Pit Mining; SME Mining Engineering Handbook, 3rd ed., Ch. Drilling and Blasting; W.I. Duvall & C.F. Fogelson, USBM RI 5514 (cratering theory); D.E. Siskind et al., USBM RI 8507 (vibration/airblast).

Question 6: Quarry Blast Vibration-Compliant Loading Design (21 marks)

Question text not reproduced: the examination questions are © Engineers and Geoscientists BC. Open the official past paper (linked at the top of this page) to read the question, then follow the worked solution below.

(a) Vibration-compliant loading, 2 rows × 12 holes, limit 6 mm/s at 500 m

Given.

QuantityValue
Pattern2 rows × 12 holes, rectangular
Bench height, H12 m
Hole diameter, De165 mm
ExplosiveAN/FO, ρ=0.8 g/cm³
Distance to nearest property, R500 m
PPV limit6 mm/s
Attenuation (Fig. 4)PPV = 774.9(R/√W)−1.327

Find. The maximum charge mass per delay, Wmax, that keeps PPV ≤ 6 mm/s at 500 m, and how to load/deck/time the 24 holes to respect it.

Approach. Invert the given attenuation law for W at the limit; compute the full-column charge for one 165 mm hole using standard diameter-based burden/stemming/subdrill ratios (not otherwise given); compare and deck if the full charge exceeds Wmax.

  1. Solve for Wmax. $$6=774.9\left(\frac{500}{\sqrt{W}}\right)^{-1.327}\ \Rightarrow\ \frac{500}{\sqrt{W}}=\left(\frac{774.9}{6}\right)^{1/1.327}=39.0$$ $$\sqrt{W}=\frac{500}{39.0}=12.8\ \Rightarrow\ \boxed{W_{max}=165\ \text{kg per delay}}$$
Scaled distance R/√W (m/kg^0.5)PPV (mm/s)110100110100design point: SD=39.0, PPV=6 mm/sy = 774.9 x^-1.327
Fig. Q6(a) – vibration attenuation curve (Fig. 4 of the exam) with the design point (scaled distance 39.0 m/kg^0.5, PPV = 6 mm/s) marked.
  1. Full-column charge in one 165 mm hole. No burden/stemming is given, so use standard diameter-based design ratios: burden B≈30×De=4.95 m, stemming T≈20×De=3.30 m, subdrill≈8×De=1.32 m. Charge length = H+subdrill−T = 12+1.32−3.30=10.02 m; area = 0.02138 m²: $$Q_{hole}=10.02\times0.02138\times800=\boxed{171\ \text{kg}}$$ – a single hole fired instantaneously (171 kg) exceeds Wmax (165 kg), so the hole must be decked rather than fired as one full-column charge.
  2. Deck the charge. $$n_{decks}=\left\lceil\frac{171}{165}\right\rceil=2,\qquad \boxed{85.7\ \text{kg per deck}}$$ Two roughly-equal decks per hole (85.7 kg each), separated by an inert stemming plug, each fired on its own delay number – both stay comfortably under the 165 kg ceiling with margin for delay scatter.
QuantityValue
Max charge mass per delay, Wmax165 kg
Assumed pattern (De-based)B≈5.0 m, T≈3.3 m, subdrill≈1.3 m
Full-column charge, one 165 mm hole171 kg (exceeds limit)
Recommended loading2 decks per hole, ≈85.7 kg each, separate delays

Sequence and timing. With 24 holes each split into 2 decks (48 charge events), sequence the round so that no two decks anywhere in the pattern share, or fall within ≈8 ms of, the same delay number (Q1(j)) – e.g. a diagonal echelon stepping hole-by-hole and deck-by-deck at a nominal 25 ms interval from the corner closest to the open face. This keeps the instantaneous per-delay charge at the single-deck value (85.7 kg, well under the 165 kg ceiling) for every event in the round, while giving each row time to relieve into the void left by the row ahead of it.

Check: burden/stemming/subdrill are not given for this question, so standard diameter-based ratios (B≈30×De, T≈20×De, subdrill≈8×De) are assumed and stated explicitly; Wmax itself (from the given attenuation law) does not depend on this assumption.

(b) Will the design eliminate complaints? Additional steps

Meeting the 6 mm/s PPV limit reduces the risk of any real structural concern, but it does not guarantee zero complaints – human perception of blast-induced vibration and airblast is far more sensitive than the regulatory damage threshold (people routinely notice and are annoyed by ground motion and air overpressure well below levels that threaten structures), and low-frequency rattle, dust, and simply the unpredictability of blast timing are common complaint drivers independent of measured PPV. Additional steps: maintain margin below the 6 mm/s limit rather than designing exactly to it (delay scatter and geological variability can push an individual shot above a tightly-designed value); control airblast with adequate stemming and by avoiding uncovered detonating cord/exposed trunklines; blast at consistent, pre-announced times of day; issue pre-blast notifications to nearby residents; conduct a pre-blast survey of nearby structures (baseline documentation protects both the operator and residents); operate continuous, third-party-auditable vibration and airblast monitoring with results available on request; and provide a complaint hotline/log so recurring nuisance patterns (rather than just regulatory exceedances) can be identified and addressed proactively (e.g. shifting the blast time, adding a delay stage, or increasing decking further even though already compliant).

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