24-MMP-B4 Mine Ventilation and Occupational Hygiene · May 2014
Nivaar worked solution (AI-drafted; not reviewed by a licensed engineer)
National Exams (BC), 09-MMP-B4 Occupational Health, Safety and Loss Management (Mine Ventilation and Occupational Hygiene), May 2014, 3 hours, open book with calculator permitted. Answer any five of the six questions; every question (1-6) is answered in full as a complete study resource.
Reference texts: Crowl & Louvar, Chemical Process Safety: Fundamentals with Applications, 4th ed.; ACGIH, TLVs and BEIs and Industrial Ventilation: A Manual of Recommended Practice; OSHA 29 CFR 1904 Recordkeeping; WorkSafeBC/BC Health, Safety and Reclamation Code for Mines.
Question text not reproduced: the examination questions are © Engineers and Geoscientists BC. Open the official past paper (linked at the top of this page) to read the question, then follow the worked solution below.
Note: the source booklet labels both sub-parts of this question "a)"; the second is answered here as (b), and reads "Solvent A" after first naming the solvent "RXP" (the same substance) — treated as one solvent throughout, per the source's own inline note.
Part (a) — This sub-part uses the “average” mixing condition, expressed here as the reciprocal $k=1/5$ of the ACGIH mixing factor $K=5$, an equivalent mixing-efficiency convention.
Given. Evaporation rate 3.0 gal per 8-hour shift; TLV-TWA = 50 ppm; $T=77\ ^\circ\text{F}$, $P=1$ atm; $SG=0.85$; $MW=145$; mixing condition "average", $k=1/5$.
Find. The dilution air flow rate required to keep the area below the TLV.
Approach. Convert the liquid evaporation rate to a molar vapour generation rate, use the ideal gas law at the stated conditions to get the pure-vapour volumetric generation rate, then divide by the TLV (as a volume fraction) and scale up by the imperfect-mixing factor. The exam states this as an efficiency $k=1/5$ ("average" mixing is less than ideal), so the actual required airflow is the ideal (perfect-mixing) airflow divided by $k$ — equivalently, multiplied by $K=1/k=5$, ACGIH's usual "average" mixing-factor value expressed the more common way round.
| Quantity | Value |
|---|---|
| Vapour generation rate (pure solvent) | 0.12 ft³/min |
| Required dilution ventilation rate, $Q$ ($k=1/5$) | ≈ 11,982 ft³/min (≈ 339 m³/h) |
Roughly 12,000 cfm of dilution air is needed to hold this fugitive emission below its TLV even though the raw vapour generation rate is only about 0.12 ft³/min of pure solvent — the TLV of 50 ppm is a 20,000:1 dilution ratio on its own, and the imperfect-mixing factor multiplies that by another 5× because real room air never mixes perfectly with a point-source leak.
Part (b) — Risk management in a hazardous operation follows a cyclical, proactive sequence rather than a one-time calculation, and is best contrasted with the purely reactive (post-accident) response it is designed to replace:
Example. Applied to this paper's own Question 6(a) scenario: a Ni refinery first identifies the fugitive RXP/Solvent-A emission as a hazard (hazard ID), assesses that 3.0 gal/shift evaporating into an averagely-mixed process area drives the airborne concentration well above what a 50 ppm TLV allows without active control (risk assessment — this is exactly the calculation in part (a)), designs the 12,000 cfm dilution system plus, ideally, source controls such as better solvent-transfer containment (control design, preferring elimination of the fugitive path over ventilation alone), trains operators on leak detection and confirms the ventilation system's rated airflow against the design requirement before start-up (implementation), and then periodically re-measures airborne solvent concentration and ventilation performance to confirm the control remains effective as equipment ages or process rates change (audit and review) — demonstrating why risk management is a continuing operational discipline, not a single calculation performed once at design time.