25-Nav-A4 Ship Structure and Strength of Ships · May 2016
Question 6 of 6: Shear in Ships
Nivaar worked solution (AI-drafted; not reviewed by a licensed engineer)
Notes on this paper
National Exams — May 2016 — 98-Nav-A4 Ship Structure and Strength of Ships. Three-hour, closed-book exam (no notes permitted); Casio/Sharp non-programmable calculator and simple drawing equipment allowed. Format: six compulsory questions, marks indicated per sub-part, totalling 100; some formulae (beam bending relations, section modulus, shear flow, deflection/slope tables) and a Normal (cumulative) distribution table are supplied at the end of the exam and are used directly below. All six are solved in full.
Reference texts: Hughes, O.F. & Paik, J.K., Ship Structural Analysis and Design (2nd ed., SNAME, 2010) — hull-girder strength, panel/plate structure, section properties and shear flow in thin-walled hull sections; Hibbeler, R.C., Mechanics of Materials (10th ed., Pearson) — beam bending/deflection, stress–strain behaviour and fatigue basics; Muckle, W., Muckle’s Naval Architecture (2nd ed., Butterworths) — hydrostatics, Bonjean curves and structural terminology; Ang, A.H-S. & Tang, W.H., Probability Concepts in Engineering (2nd ed., Wiley) — structural reliability, load/resistance margin; IACS Common Structural Rules — steel grades, fatigue design (S–N curves, Paris Law).
Given. An open channel section (centreline dimensions): top flange 200 mm long × 7 mm thick, web 150 mm tall × 5 mm thick, bottom flange 200 mm long × 5 mm thick; vertical shear $V=100\text{ kN}$. Point B is the top of the web, at the flange-web junction (marked on the source figure).
Check
Dimensions are taken as the printed (centreline) lengths directly, per standard thin-wall shear-flow practice; the shear stress at B uses the web thickness (5 mm), since the marked point sits on the web immediately below the flange-web corner.
Find. Shear flow $q(s)$ around the open section and the shear stress at B.
Approach. Locate the section's neutral axis and $I_{NA}$ (composite-section method, as in Q3a), then apply the open-section shear-flow formula $q=VQ/I$ starting from each free edge (where $q=0$) and building up toward the web.
(a) Section properties. $A_{top}=200(7)=1400$, $A_{bot}=200(5)=1000$, $A_{web}=150(5)=750\ \text{mm}^2$; $A_{tot}=3150\ \text{mm}^2$. Neutral axis (from the bottom flange centreline): $$\bar y=\frac{1400(150)+1000(0)+750(75)}{3150}=\boxed{84.5\text{ mm}}$$ Moment of inertia (parallel-axis theorem on all three pieces): $$\boxed{I_{NA}=14.63\times10^6\ \text{mm}^4}$$
Shear flow entering the web from the top flange (at B). Sweeping the full top flange from its free tip to the web junction, $Q_B=A_{top}\,d_{top}=1400(65.5)=91{,}667\ \text{mm}^3$ (with $d_{top}=150-84.5=65.5\text{ mm}$): $$q_B=\frac{VQ_B}{I_{NA}}=\frac{100{,}000(91{,}667)}{14.63\times10^6}=\boxed{626.6\text{ N/mm}}$$
Shear flow entering the web from the bottom flange. $Q_C=A_{bot}\,d_{bot}=1000(84.5)=84{,}524\ \text{mm}^3$: $$q_C=\frac{VQ_C}{I_{NA}}=\frac{100{,}000(84{,}524)}{14.63\times10^6}=\boxed{577.8\text{ N/mm}}$$
Maximum shear flow (at the neutral axis, within the web). Adding the web area below the N.A. to $Q_C$: $Q_{max}=102{,}385\ \text{mm}^3$, giving $$q_{max}=\frac{V\,Q_{max}}{I_{NA}}=\boxed{699.9\text{ N/mm}}$$ — consistent with the general result that shear flow peaks at the neutral axis. Shear flow is zero at both free flange tips and rises monotonically toward the web in each flange, then continues rising through the web to its maximum at the N.A.
(b) Shear stress at B. Dividing the shear flow entering the web at B by the web thickness: $$\tau_B=\frac{q_B}{t_{web}}=\frac{626.6}{5}=\boxed{125.3\text{ MPa}}$$
Figure 6.1 — channel-section shear flow diagram: zero at both free flange tips, rising through each flange to the web, peaking at the neutral axis.