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24-Pet-A2 Petroleum Reservoir Fluids · December 2019

Question 4 of 7: Gas Z-Factor, Original Gas In Place, and Gas Viscosity

Nivaar worked solution (AI-drafted; not reviewed by a licensed engineer)

Notes on this paper

EGBC National Exam — Petroleum Engineering, 17-Pet-A2 Petroleum Reservoir Fluids, 2019-Dec. 3 hours duration, closed book (ruler and approved calculator only). SEVEN questions are printed on the paper; per the exam notes, FIVE questions constitute a complete exam paper and only the first five as answered are marked. Every question is solved in full below (all seven, not just the five a candidate would normally submit) so this set also serves as complete study material.

Reference texts: McCain, W.D., The Properties of Petroleum Fluids, 3rd ed. (PennWell); Ahmed, T., Reservoir Engineering Handbook, 5th ed.; Craft, B.C. & Hawkins, M.F., Applied Petroleum Reservoir Engineering, 3rd ed.; Standing, M.B., Volumetric and Phase Behavior of Oil Field Hydrocarbon Systems; Danesh, A., PVT and Phase Behaviour of Petroleum Reservoir Fluids.

Check: Questions 2 and 6 are built around two classic published P–T phase-diagram figures (the ethane/n-heptane system of Kay, Ind. Eng. Reading exact bubble/dew/critical points off these charts, as the exam intends, is not possible from this source. Every requested quantity in Q2 and Q6 is instead computed analytically: pseudo-critical properties via Kay's mixing rule (the exam's own formula sheet supplies exactly this rule) and bubble/dew points via the standard Wilson K-value correlation, $K_i = (P_{ci}/P)\exp[5.373(1+\omega_i)(1-T_{ci}/T)]$ — the textbook approximate method for hand/exam flash calculations. This gives fully verifiable, reproducible numbers in place of a chart reading, but they are engineering estimates, not a literal digitization — flagged at each affected step below.

Question 4: Gas Z-Factor, Original Gas In Place, and Gas Viscosity (20 marks)

Question text not reproduced: the examination questions are © Engineers and Geoscientists BC. Open the official past paper (linked at the top of this page) to read the question, then follow the worked solution below.

Given.

Gas composition and component properties
Componentmol%$T_c$, °R$P_c$, psiaM, lb/lb-mol$\mu$ @ 1 atm, cp
Methane97.12343.33666.416.040.0128
Ethane2.42549.92706.530.070.0110
Propane0.31666.06616.044.100.0098
i-Butane0.05734.46527.958.120.0091
n-Butane0.02765.60550.658.120.0094
i-/n-Pentanetrace——72.150.0080/0.0082
Hexanes0.02913.60436.986.180.0078
Heptanes+0.0610823721280.0068

$h=21$ ft, $\phi=0.18$, $S_w=0.33$, spacing $=700$ acres, $P_i=3810$ psia, $T=194\,{}^{\circ}\text{F}$.

Find. (i) $Z$ at initial conditions, (ii) original gas in place per well drainage area, (iii) gas viscosity at 1 atm and 194°F.

Approach. Mix pseudo-criticals directly from the composition (Kay's rule, given as-is since Tc/Pc are supplied per component, including for the heptanes-plus fraction); solve for $Z$ via the DAK correlation; convert drainage-area bulk rock volume to hydrocarbon pore volume and divide by $B_g$ for OGIP; combine atmospheric-pressure component viscosities with the Herning–Zipperer mixing rule (per the formula sheet).

(i) Gas Z-factor at initial reservoir condition

  1. Pseudo-critical properties. $$T_{pc}=\sum y_iT_{ci} = 0.9712(343.33)+0.0242(549.92)+0.0031(666.06)+0.0005(734.46)+0.0002(765.60)+0.0002(913.60)+0.0006(1082) = 350.2\,{}^{\circ}\text{R}$$ $$P_{pc}=\sum y_iP_{ci} = 666.9\text{ psia}$$
  2. Reduced properties. $$T_r=\frac{194+460}{350.2}=1.868\qquad P_r=\frac{3810}{666.9}=5.713$$
  3. Solve DAK for $Z$: $$\boxed{Z \approx 0.951}$$
Check: the heptanes-plus specific gravity is printed in the paper as "0.0758," an order of magnitude too low for a C7+ fraction (physically plausible range ≈0.68–0.85) – almost certainly a misprint for 0.758. This does not affect the calculation above, since $T_c$ and $P_c$ for heptanes-plus (1082°R, 372 psia) are given directly in the table rather than derived from the SG/MW via a correlation.

(ii) Original gas in place, single well's 700-acre drainage area

  1. Bulk and pore volume. $$V_b = 700\text{ ac}\times43{,}560\text{ ft}^2/\text{ac}\times21\text{ ft} = 6.403\times10^8\text{ ft}^3$$ $$V_p = V_b\phi = 1.153\times10^8\text{ ft}^3\qquad V_{hc}=V_p(1-S_w)=7.722\times10^7\text{ ft}^3$$
  2. Gas FVF at initial conditions. $$B_{gi}=0.02827\frac{ZT}{p}=0.02827\times\frac{0.951\times654}{3810}=0.004615\ \text{ft}^3/\text{scf}$$
  3. Original gas in place. $$G = \frac{V_{hc}}{B_{gi}} = \frac{7.722\times10^7}{0.004615} = \boxed{1.673\times10^{10}\ \text{scf} \approx 16.73\ \text{Bscf}}$$

(iii) Gas viscosity at 1 atm, 194°F – Herning–Zipperer rule

  1. Mixing rule (formula sheet). $$\mu_g = \frac{\sum_j \mu_{gj}\,y_j\sqrt{M_j}}{\sum_j y_j\sqrt{M_j}}$$ Trace i-/n-pentane contribute negligibly and are omitted.
  2. Evaluate. Using the table's atmospheric-pressure component viscosities and molecular weights: $$\boxed{\mu_g(1\text{ atm}, 194\,{}^{\circ}\text{F}) \approx 0.01271\ \text{cp}}$$
QuantityValue
$T_{pc}$, $P_{pc}$350.2°R, 666.9 psia
(i) $Z$ (initial conditions)0.951
(ii) $G$ (single well, 700 ac)1.673×10¹⁰ scf (16.73 Bscf)
(iii) $\mu_g$ (1 atm, 194°F)0.01271 cp