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24-Pet-B1 Natural Gas Engineering · December 2019

Question 10 of 10: ESSP for Ideal and Nonideal Shale Membranes

Nivaar worked solution (AI-drafted; not reviewed by a licensed engineer)

Notes on this paper

National Examinations, 17-Pet-B1, Well Logging and Formation Evaluation — December 2019, 3 hours, closed book (Casio or Sharp approved calculators permitted), 10 questions, all marked.

Reference texts: Bassiouni, Theory, Measurement, and Interpretation of Well Logs (SPE Textbook Series Vol. 4); Asquith & Krygowski, Basic Well Log Analysis, 2nd ed. (AAPG); Ellis & Singer, Well Logging for Earth Scientists, 2nd ed.; Schlumberger, Log Interpretation Charts / Log Interpretation Principles and Applications.

Question 10: ESSP for Ideal and Nonideal Shale Membranes (10 marks)

Question text not reproduced: the examination questions are © Engineers and Geoscientists BC. Open the official past paper (linked at the top of this page) to read the question, then follow the worked solution below.

Given.

QuantityValue
Formation temperature, T200°F
Mud-filtrate resistivity (at F.T.), Rmf0.5 Ω·m
Formation-water resistivity (at F.T.), Rw0.1 Ω·m
Shale resistivity (nonideal case, at F.T.), Rsh2 Ω·m

Find. ESSP for (a) a perfect (ideal) shale membrane, and (b) a nonideal membrane with the given Rsh.

Approach. (a) Apply the attachment's ESSP formula directly, using K=61.3+0.133T. (b) An imperfect (leaky) shale membrane no longer follows the simple K·log(Rmf/Rw) law; the reduced SP is read from the departure-curve chart of Rmf/Rw vs. ESP parameterized by (Rsh/Rmf)@F.T.

  1. Temperature coefficient K. $$K=61.3+0.133T=61.3+0.133(200)=61.3+26.6=\boxed{87.9}$$
  2. (a) Ideal (perfect) membrane — direct formula. $$E_{SSP}=-K\log_{10}\!\left(\frac{R_{mf}}{R_w}\right)=-87.9\log_{10}\!\left(\frac{0.5}{0.1}\right)=-87.9\log_{10}(5)=-87.9(0.699)=\boxed{-61.4\text{ mV}}$$
  3. (b) Nonideal membrane — chart parameters. $$\frac{R_{mf}}{R_w}=\frac{0.5}{0.1}=5.0\qquad \left(\frac{R_{sh}}{R_{mf}}\right)_{@F.T.}=\frac{2.0}{0.5}=4.0$$
  4. (b) Read ESSP off the departure-curve chart. The chart is reproduced on source page 13: (Rmf/Rw) on a logarithmic ordinate from 1 to 30, ESP on a linear abscissa from 0 to −120 mV, and a family of curves labelled (Rsh/Rmf)@F.T. = 1, 2, 4, 6, 8, 10, 12, 15, 20. Entering at Rmf/Rw=5.0 and running across to the curve labelled 4: $$E_{SSP,\text{nonideal}}\approx\boxed{-27\text{ mV}}$$ — a much smaller deflection than the ideal −61.4 mV, because a shale resistivity only 4× the mud filtrate is a comparatively leaky (nonideal) cationic membrane that develops only a fraction of the ideal electrochemical EMF. The chart is steep here: the neighbouring curve (Rsh/Rmf)=6 does not reach Rmf/Rw=5.0 until about −58 mV, so which curve is entered matters far more than the precision of the read. (The exam's own attachment page reproduces a similar departure chart with a worked example annotated at ESP=−50 mV giving (Rmf/Rw)eq≈4 — that is the chart's FORWARD use (an SP reading to Rmf/Rw for a water-resistivity determination) with different input parameters than this part, so it is not re-used directly here, but confirms the same chart family and the reasonableness of a chart-read answer in the −20 to −30 mV range.)
CaseESSP
(a) Perfect (ideal) shale membrane−61.4 mV
(b) Nonideal membrane, Rsh/Rmf=4≈ −27 mV
Check: part (b) is a chart read from the printed attachment, so −27 mV carries about ±3 mV. It was read against the chart’s own axes (plot box 0 mV at the left border to −120 mV at the right; logarithmic ordinate with printed 2, 3, 4, 5, 8 and 10 gridlines), and cross-checked against two other points on the same curve family that can be read independently: the (Rsh/Rmf)=6 curve reaches Rmf/Rw=4.0 at −37 mV and 4.5 at about −49 mV, and the (Rsh/Rmf)=4 curve begins at Rmf/Rw=4.27 at the chart’s −10 mV left limit. The qualitative point — a shale only 4× more resistive than the mud filtrate develops well under half of the ideal SSP — is the intended lesson and is insensitive to that tolerance.
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