Question 7 of 7: Radioiodine ( 131 I) Thyroid Dosimetry for Graves' Disease
Nivaar worked solution (AI-drafted; not reviewed by a licensed engineer)
Notes on this paper
Paper format. 98-Phys-B1 Radiation Physics, National Examination
December 2016 — a three-hour open-book examination in which any
non-communicating calculator is permitted (the candidate must record the calculator's make and
model on the first sheet). The cover page states the exam has 7 questions worth a total
of 87 points, of which only 80 points' worth need be answered for full marks; every
question and sub-part is nonetheless answered in full below so the paper remains a complete
study resource. The cover page's own marking-scheme summary (13+9+8+10+19+10+18 = 87)
is internally consistent with the stated total. The cover page also invites the candidate to
submit a written statement of any assumptions made where a question is open to interpretation
— this licence is used below in Question 2 (ICRP-60 neutron weighting factors are assumed
for the thermal/fast neutron energy brackets, since none are given explicitly), Question 4 (the
source's printed comparison wavelength "10 pm" for a carbon-dioxide laser photon is read as the real CO2-laser wavelength, 10 μm, since no laser emits at
10 picometres), Question 5(f) (shield thicknesses are order-of-magnitude illustrative estimates,
since the source gives no source strength/dose-rate target to size against), and Question 5(g)
(the fission-energy-distribution percentages are standard textbook illustrative values, since the
source gives no numeric data of its own to compute them from).
Reference texts. K. S. Krane, Introductory Nuclear Physics (nuclear
reaction equations, fission energetics, mass–energy conservation); F. H. Attix,
Introduction to Radiological Physics and Radiation Dosimetry (photon/EM interactions,
non-ionizing radiation, shielding); J. R. Cember and T. E. Johnson, Introduction to Health
Physics, 5th ed. (internal dosimetry, radiation weighting factors, MIRD absorbed-fraction
formalism, ALARA); J. E. Turner, Atoms, Radiation, and Radiation Protection, 3rd ed.
(neutron detection/shielding, Compton scattering, radiation protection tenets).
Find. (a) rationale for iodine; (b) time to $A_0/8$; (c) cumulative
(time-integrated) thyroid activity; (d) gamma absorbed fraction at 370 keV; (e) cumulative gamma
dose; (f) cumulative beta dose; (g) which radiation best suits treatment.
Approach. Combine physical and biological clearance into an effective
half-life, use it to answer the elapsed-time question (b) and to time-integrate the thyroid's
activity concentration (c). Interpolate the absorbed-fraction table to the actual 370 keV
gamma energy (d); since beta particles have a range of only fractions of a millimetre they are
essentially fully absorbed locally in a 16 g organ (absorbed fraction $\approx1$), while
penetrating gammas mostly escape, so only the gamma dose needs the absorbed-fraction correction
(e)–(f). Compare the two cumulative doses to answer (g).
Part (a) — why iodine. The thyroid gland actively and selectively
concentrates iodine from the bloodstream as the essential raw material for synthesizing thyroid
hormones (T3/T4); radioactive $^{131}$I is chemically identical to stable iodine, so the gland
takes it up by the same natural physiological pathway. This gives a highly selective, targeted
radiation dose to thyroid tissue itself, with comparatively little uptake or dose to other
organs — exactly the selectivity a systemic (whole-body-administered) radiotherapy needs.
Part (b) — time to decay to one-eighth. Physical and biological
clearance act in parallel, combining into an effective half-life:
$$\frac{1}{T_{\text{eff}}} = \frac{1}{T_p}+\frac{1}{T_b} = \frac{1}{8}+\frac{1}{2}
= \frac{5}{8}\ \text{d}^{-1}$$
$$T_{\text{eff}} = \frac{8}{5} = 1.6\ \text{days}$$
A decrease to one-eighth is exactly three half-lives ($\left(\tfrac12\right)^3=\tfrac18$), so:
$$\boxed{t_{1/8} = 3\,T_{\text{eff}} = 3(1.6) = 4.8\ \text{days}}$$
Part (c) — cumulative activity in the thyroid. With immediate uptake,
the activity resident in the thyroid at $t=0$ is $A_{0,\text{thy}}=u\,A_0=0.60(100\ \text{MBq})
=60$ MBq, decaying with the effective (physical + biological clearance) rate. The time-integral
of an exponentially decaying activity is $A_0\times\tau_{\text{eff}}$, where
$\tau_{\text{eff}}=T_{\text{eff}}/\ln2$ is the mean life:
$$\tau_{\text{eff}} = \frac{T_{\text{eff}}}{\ln2} = \frac{1.6\times86{,}400\ \text{s}}{0.6931}
\approx 1.994\times10^{5}\ \text{s}$$
$$\tilde A = A_{0,\text{thy}}\times\tau_{\text{eff}} = (60\times10^{6}\ \text{Bq})(1.994\times10^{5}\ \text{s})$$
$$\boxed{\tilde A \approx 1.197\times10^{13}\ \text{Bq}\cdot\text{s}}$$
Part (d) — gamma absorbed fraction at 370 keV. The table gives the
per-gram absorbed fraction at 200 keV and 500 keV, bracketing the actual 370 keV emission;
interpolating linearly:
$$\phi_{370}(\text{per g}) = 1.55\times10^{-3} + \frac{370-200}{500-200}
\left(1.66\times10^{-3}-1.55\times10^{-3}\right) \approx 1.612\times10^{-3}\ \text{g}^{-1}$$
Scaling by the thyroid's 16 g mass gives the total fraction of emitted gamma energy actually
absorbed in the whole gland:
$$\boxed{\phi_{370,\text{total}} = 1.612\times10^{-3}\times16 \approx 0.0258\ \ (2.58\%)}$$
— i.e. only about 2.6% of the emitted gamma energy is absorbed within the small thyroid;
the rest escapes the organ entirely, which is exactly what "absorbed fraction" quantifies for a
penetrating, weakly-interacting photon in a small target.
Part (e) — cumulative gamma dose to the thyroid. The given dose-rate
constant $k_\gamma$ already assumes full local absorption (the "infinitely large" tissue
premise), so it must be scaled down by the actual absorbed fraction from part (d) to reflect the
finite 16 g thyroid. Using the activity concentration $c_0=A_{0,\text{thy}}/m=60\times10^6/
0.016=3.75\times10^9$ Bq/kg and the same $\tau_{\text{eff}}$ from part (c):
$$D_{\gamma,\infty} = k_\gamma\, c_0\, \tau_{\text{eff}}
= (48.55\times10^{-15})(3.75\times10^{9})(1.994\times10^{5}) \approx 36.3\ \text{Sv}$$
$$\boxed{D_\gamma = D_{\gamma,\infty}\times\phi_{370,\text{total}}
\approx 36.3\times0.0258 \approx 0.937\ \text{Sv}}$$
Part (f) — cumulative beta dose to the thyroid. Beta particles of
this energy have a range in tissue of only fractions of a millimetre, far smaller than the
thyroid itself, so essentially all emitted beta energy is absorbed locally — no
absorbed-fraction correction is needed (absorbed fraction $\approx1$):
$$\boxed{D_\beta = k_\beta\, c_0\, \tau_{\text{eff}}
= (27.72\times10^{-15})(3.75\times10^{9})(1.994\times10^{5}) \approx 20.7\ \text{Sv}}$$
Part (g) — which radiation is best suited to treatment. Beta
radiation delivers roughly 22 times the local thyroid dose of gamma radiation for the same
administered activity ($20.7$ Sv vs. $0.937$ Sv), precisely because its short range confines
essentially all of its energy to the target organ itself, while the penetrating gamma rays
mostly escape the small thyroid and are largely "wasted" — delivering unwanted dose to
surrounding tissue, other organs, and people nearby, rather than doing therapeutic work. Both
findings point the same direction: $$\boxed{\text{Beta radiation is the therapeutically
effective component}}$$ — it is what actually ablates the overactive thyroid tissue,
consistent with why $^{131}$I is chosen precisely for its beta emission for Graves' disease
therapy, with its gamma emission being useful mainly for imaging/dosimetry confirmation rather
than treatment itself.