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17-Phys-B1 Radiation Physics · December 2016

Question 7 of 7: Radioiodine ( 131 I) Thyroid Dosimetry for Graves' Disease

Nivaar worked solution (AI-drafted; not reviewed by a licensed engineer)

Notes on this paper

Paper format. 98-Phys-B1 Radiation Physics, National Examination December 2016 — a three-hour open-book examination in which any non-communicating calculator is permitted (the candidate must record the calculator's make and model on the first sheet). The cover page states the exam has 7 questions worth a total of 87 points, of which only 80 points' worth need be answered for full marks; every question and sub-part is nonetheless answered in full below so the paper remains a complete study resource. The cover page's own marking-scheme summary (13+9+8+10+19+10+18 = 87) is internally consistent with the stated total. The cover page also invites the candidate to submit a written statement of any assumptions made where a question is open to interpretation — this licence is used below in Question 2 (ICRP-60 neutron weighting factors are assumed for the thermal/fast neutron energy brackets, since none are given explicitly), Question 4 (the source's printed comparison wavelength "10 pm" for a carbon-dioxide laser photon is read as the real CO2-laser wavelength, 10 μm, since no laser emits at 10 picometres), Question 5(f) (shield thicknesses are order-of-magnitude illustrative estimates, since the source gives no source strength/dose-rate target to size against), and Question 5(g) (the fission-energy-distribution percentages are standard textbook illustrative values, since the source gives no numeric data of its own to compute them from).

Reference texts. K. S. Krane, Introductory Nuclear Physics (nuclear reaction equations, fission energetics, mass–energy conservation); F. H. Attix, Introduction to Radiological Physics and Radiation Dosimetry (photon/EM interactions, non-ionizing radiation, shielding); J. R. Cember and T. E. Johnson, Introduction to Health Physics, 5th ed. (internal dosimetry, radiation weighting factors, MIRD absorbed-fraction formalism, ALARA); J. E. Turner, Atoms, Radiation, and Radiation Protection, 3rd ed. (neutron detection/shielding, Compton scattering, radiation protection tenets).

Question 7: Radioiodine (131I) Thyroid Dosimetry for Graves' Disease (18 marks)

Question text not reproduced: the examination questions are © Engineers and Geoscientists BC. Open the official past paper (linked at the top of this page) to read the question, then follow the worked solution below.

Given. Administered activity $A_0=100$ MBq; $T_p=8$ d, $T_b=2$ d; thyroid uptake $60\%$, immediate; mean $\bar E_\beta=192$ keV, $\bar E_\gamma=370$ keV per decay; infinite-medium dose-rate constants $k_\beta=27.72\times10^{-15}$ Sv·kg/(Bq·s), $k_\gamma=48.55\times10^{-15}$ Sv·kg/(Bq·s); thyroid mass $m=16$ g; gamma absorbed-fraction table above.

Given data
QuantitySymbolValue
Administered activity$A_0$100 MBq
Physical half-life$T_p$8 d
Biological half-life$T_b$2 d
Thyroid uptake$u$60%
Thyroid mass$m$16 g
Beta dose-rate constant$k_\beta$$27.72\times10^{-15}$ Sv·kg/(Bq·s)
Gamma dose-rate constant$k_\gamma$$48.55\times10^{-15}$ Sv·kg/(Bq·s)

Find. (a) rationale for iodine; (b) time to $A_0/8$; (c) cumulative (time-integrated) thyroid activity; (d) gamma absorbed fraction at 370 keV; (e) cumulative gamma dose; (f) cumulative beta dose; (g) which radiation best suits treatment.

Approach. Combine physical and biological clearance into an effective half-life, use it to answer the elapsed-time question (b) and to time-integrate the thyroid's activity concentration (c). Interpolate the absorbed-fraction table to the actual 370 keV gamma energy (d); since beta particles have a range of only fractions of a millimetre they are essentially fully absorbed locally in a 16 g organ (absorbed fraction $\approx1$), while penetrating gammas mostly escape, so only the gamma dose needs the absorbed-fraction correction (e)–(f). Compare the two cumulative doses to answer (g).

  1. Part (a) — why iodine. The thyroid gland actively and selectively concentrates iodine from the bloodstream as the essential raw material for synthesizing thyroid hormones (T3/T4); radioactive $^{131}$I is chemically identical to stable iodine, so the gland takes it up by the same natural physiological pathway. This gives a highly selective, targeted radiation dose to thyroid tissue itself, with comparatively little uptake or dose to other organs — exactly the selectivity a systemic (whole-body-administered) radiotherapy needs.
  2. Part (b) — time to decay to one-eighth. Physical and biological clearance act in parallel, combining into an effective half-life: $$\frac{1}{T_{\text{eff}}} = \frac{1}{T_p}+\frac{1}{T_b} = \frac{1}{8}+\frac{1}{2} = \frac{5}{8}\ \text{d}^{-1}$$ $$T_{\text{eff}} = \frac{8}{5} = 1.6\ \text{days}$$ A decrease to one-eighth is exactly three half-lives ($\left(\tfrac12\right)^3=\tfrac18$), so: $$\boxed{t_{1/8} = 3\,T_{\text{eff}} = 3(1.6) = 4.8\ \text{days}}$$
  3. Part (c) — cumulative activity in the thyroid. With immediate uptake, the activity resident in the thyroid at $t=0$ is $A_{0,\text{thy}}=u\,A_0=0.60(100\ \text{MBq}) =60$ MBq, decaying with the effective (physical + biological clearance) rate. The time-integral of an exponentially decaying activity is $A_0\times\tau_{\text{eff}}$, where $\tau_{\text{eff}}=T_{\text{eff}}/\ln2$ is the mean life: $$\tau_{\text{eff}} = \frac{T_{\text{eff}}}{\ln2} = \frac{1.6\times86{,}400\ \text{s}}{0.6931} \approx 1.994\times10^{5}\ \text{s}$$ $$\tilde A = A_{0,\text{thy}}\times\tau_{\text{eff}} = (60\times10^{6}\ \text{Bq})(1.994\times10^{5}\ \text{s})$$ $$\boxed{\tilde A \approx 1.197\times10^{13}\ \text{Bq}\cdot\text{s}}$$
  4. Part (d) — gamma absorbed fraction at 370 keV. The table gives the per-gram absorbed fraction at 200 keV and 500 keV, bracketing the actual 370 keV emission; interpolating linearly: $$\phi_{370}(\text{per g}) = 1.55\times10^{-3} + \frac{370-200}{500-200} \left(1.66\times10^{-3}-1.55\times10^{-3}\right) \approx 1.612\times10^{-3}\ \text{g}^{-1}$$ Scaling by the thyroid's 16 g mass gives the total fraction of emitted gamma energy actually absorbed in the whole gland: $$\boxed{\phi_{370,\text{total}} = 1.612\times10^{-3}\times16 \approx 0.0258\ \ (2.58\%)}$$ — i.e. only about 2.6% of the emitted gamma energy is absorbed within the small thyroid; the rest escapes the organ entirely, which is exactly what "absorbed fraction" quantifies for a penetrating, weakly-interacting photon in a small target.
  5. Part (e) — cumulative gamma dose to the thyroid. The given dose-rate constant $k_\gamma$ already assumes full local absorption (the "infinitely large" tissue premise), so it must be scaled down by the actual absorbed fraction from part (d) to reflect the finite 16 g thyroid. Using the activity concentration $c_0=A_{0,\text{thy}}/m=60\times10^6/ 0.016=3.75\times10^9$ Bq/kg and the same $\tau_{\text{eff}}$ from part (c): $$D_{\gamma,\infty} = k_\gamma\, c_0\, \tau_{\text{eff}} = (48.55\times10^{-15})(3.75\times10^{9})(1.994\times10^{5}) \approx 36.3\ \text{Sv}$$ $$\boxed{D_\gamma = D_{\gamma,\infty}\times\phi_{370,\text{total}} \approx 36.3\times0.0258 \approx 0.937\ \text{Sv}}$$
  6. Part (f) — cumulative beta dose to the thyroid. Beta particles of this energy have a range in tissue of only fractions of a millimetre, far smaller than the thyroid itself, so essentially all emitted beta energy is absorbed locally — no absorbed-fraction correction is needed (absorbed fraction $\approx1$): $$\boxed{D_\beta = k_\beta\, c_0\, \tau_{\text{eff}} = (27.72\times10^{-15})(3.75\times10^{9})(1.994\times10^{5}) \approx 20.7\ \text{Sv}}$$
  7. Part (g) — which radiation is best suited to treatment. Beta radiation delivers roughly 22 times the local thyroid dose of gamma radiation for the same administered activity ($20.7$ Sv vs. $0.937$ Sv), precisely because its short range confines essentially all of its energy to the target organ itself, while the penetrating gamma rays mostly escape the small thyroid and are largely "wasted" — delivering unwanted dose to surrounding tissue, other organs, and people nearby, rather than doing therapeutic work. Both findings point the same direction: $$\boxed{\text{Beta radiation is the therapeutically effective component}}$$ — it is what actually ablates the overactive thyroid tissue, consistent with why $^{131}$I is chosen precisely for its beta emission for Graves' disease therapy, with its gamma emission being useful mainly for imaging/dosimetry confirmation rather than treatment itself.
Question 7 — results
PartResult
(a)Thyroid physiologically concentrates iodine (T3/T4 synthesis) → selective targeting
(b) $t_{1/8}$4.8 days ($T_{\text{eff}}=1.6$ d)
(c) $\tilde A$$\approx1.197\times10^{13}$ Bq·s
(d) $\phi_{370,\text{total}}$$\approx0.0258$ (2.58%)
(e) $D_\gamma$$\approx0.937$ Sv
(f) $D_\beta$$\approx20.7$ Sv
(g)Beta ($\approx22\times$ the gamma dose; short range confines energy to the thyroid)
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