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17-Phys-B6 Applied Thermodynamics and Heat Transfer · December 2018

Question 3 of 8: Automotive Regenerative Gas-Turbine — Schematic, T-s Diagram, Efficiency, Air Flow

Nivaar worked solution (AI-drafted; not reviewed by a licensed engineer)

Notes on this paper

Paper format. 17-Phys-B6 Applied Thermodynamics and Heat Transfer, National Examination December 2018 — a three-hour open-book examination; candidates are expected to bring both a thermodynamics text and a heat-transfer text to make use of the property tables and graphs. A complete examination is five questions — either three from Part A (Thermodynamics, Q1–Q4) and two from Part B (Heat Transfer, Q5–Q8), or two from Part A and three from Part B — every question carrying equal value; all eight are solved below as a complete study set. Question 2 is solved as one connected narrative: the wet steam whose quality is measured by the throttling calorimeter in part (a) is the same steam entering the turbine in part (b), which is what makes part (c)'s "isentropic despite heat loss" observation checkable. Question 3 gives every cycle temperature directly from the printed diagram but no pressures, so it is solved purely from energy balances (constant specific heat, cold-air-standard) rather than isentropic pressure ratios — the intended reading, since no compressor/turbine pressure ratio is given anywhere on the page.

Reference texts. Y. A. Çengel and M. A. Boles, Thermodynamics: An Engineering Approach, 8th ed. (ideal-gas mixtures, air-standard Otto and Brayton cycles, throttling calorimeters, steam turbines, vapour-compression refrigeration); F. P. Incropera and D. P. DeWitt, Fundamentals of Heat and Mass Transfer, 7th ed. (composite cylindrical conduction with convection at both surfaces, heat generation in a solid cylinder, internal/external convection combined via an overall coefficient, effectiveness–NTU heat-exchanger analysis). Ammonia and steam saturation/superheat property values were computed (Bell et al., IAPWS-95 / REFPROP-quality equations of state) and cross-checked against the printed appendix tables on pages 5–6 of the source exam and standard steam tables, which they matched to 3–4 significant figures throughout.

Question 3: Automotive Regenerative Gas-Turbine — Schematic, T-s Diagram, Efficiency, Air Flow

Question text not reproduced: the examination questions are © Engineers and Geoscientists BC. Open the official past paper (linked at the top of this page) to read the question, then follow the worked solution below.

Given. A split-shaft regenerative Brayton-cycle automotive gas turbine: air enters the compressor at 30°C, exits at 425°C, is preheated in the regenerator to 1025°C, fuel is burned raising it to 1700°C entering the compressor-drive turbine (which is on the SAME shaft as the compressor, so its work exactly supplies the compressor's work), then expands further through a separate free power turbine to the rear axle, exiting at 1200°C into the regenerator's hot side, which is exhausted at 500°C. No pressures are printed anywhere on the page — every temperature is read directly off the diagram.

Given data (stations per the figure)
StationDescription$T$
1Compressor inlet (ambient)$30\,{}^{\circ}\text{C}$
2Compressor exit$425\,{}^{\circ}\text{C}$
3Regenerator (cold side) exit / combustor inlet$1025\,{}^{\circ}\text{C}$
4Combustor exit / compressor-turbine inlet$1700\,{}^{\circ}\text{C}$
6Power-turbine exit / regenerator (hot side) inlet$1200\,{}^{\circ}\text{C}$
7Regenerator (hot side) exit / exhaust$500\,{}^{\circ}\text{C}$

Find. (a) A schematic of the plant; (b) the cycle on a $T$–$s$ diagram; (c) the thermal efficiency; (d) the air flow rate for 50 kW at the rear axle.

AirCompressorRegeneratorCombustorCompressorTurbinePowerTurbine1: air in30°C2: 425°C3: 1025°C4: 1700°C5: (found)6: 1200°C → to regenerator (hot side)power torear wheels
(a) Schematic: ambient air → compressor → regenerator (cold side) → combustor → compressor turbine (drives the compressor via a shaft) → power turbine (drives the rear wheels) → regenerator (hot side) → exhaust.
Split-shaft cycle on T–s coordinates (schematic, not to scale)sT (°C)1234567
(b) The cycle on $T$–$s$ coordinates (schematic, not to scale): 1–2 compression, 2–3 regenerative preheat, 3–4 combustion (external heat input), 4–5 compressor-turbine expansion, 5–6 power-turbine expansion (net work output), 6–7 regenerator heat recovery to the incoming air.

Approach. Station 5 (between the two turbines) is not printed — find it from an energy balance on the shaft: the compressor-turbine's work output must exactly equal the compressor's work input (both on the same shaft, cold-air-standard, constant $c_p$). The regenerator recovers heat internally and is NOT counted as external heat input; the only external heat added is in the combustor (3→4), and the only useful net work is the power turbine's (5→6), since the compressor turbine's work is fully consumed driving the compressor.

  1. Station 5 — shaft energy balance (compressor turbine = compressor work). $$c_p(T_2-T_1)=c_p(T_4-T_5)\quad\Rightarrow\quad T_5=T_4-(T_2-T_1)$$ $$T_5=1973.15-(698.15-303.15)$$ $$\boxed{T_5=1578.2\text{ K}=1305.0\,{}^{\circ}\text{C}}$$
  2. Thermal efficiency. Net work = power-turbine work only; heat input = combustor only: $$\eta_{th}=\frac{\dot W_{net}}{\dot Q_{in}}=\frac{c_p(T_5-T_6)}{c_p(T_4-T_3)} =\frac{T_5-T_6}{T_4-T_3}=\frac{1578.2-1473.2}{1973.2-1298.2}$$ $$\boxed{\eta_{th}=\frac{105.0}{675.0}=0.1556=15.6\%}$$
  3. Air flow rate for 50 kW at the rear axle. The rear-axle power is exactly the power-turbine's net output: $$\dot W_{pt}=\dot m\,c_p(T_5-T_6)\quad\Rightarrow\quad\dot m=\frac{\dot W_{pt}}{c_p(T_5-T_6)}$$ $$\dot m=\frac{50}{1.005\times105.0}$$ $$\boxed{\dot m=0.474\text{ kg/s}}$$
Question 3 — results
QuantityValue
Station 5 temperature (compressor-turbine exit)1305.0°C (1578.2 K)
(c) Thermal efficiency $\eta_{th}$15.6%
(d) Air flow rate $\dot m$0.474 kg/s