Question 3 of 7: Pb–Sn Lever Rule; Precipitate Coherency; Age-Hardening Candidates
Nivaar worked solution (AI-drafted; not reviewed by a licensed engineer)
Notes on this paper
National Exam 04-BS-11, Properties of Materials — December 2014. 3 hours,
closed-book examination (approved Casio or Sharp calculator only). Any five questions constitute
a complete paper; only the first five questions as they appear in the answer book are marked. All
seven questions are solved below for completeness.
Given. (a) At 200°C: solid $\alpha$ solubility $=18\%$ Sn; liquid solubility
$=43\%$ Pb ($=57\%$ Sn); alloy is 60% liquid + 40% solid $\alpha$ by mass. (c) A generic Y–Z
eutectic phase diagram with four labelled alloy compositions (1–4); $\beta$ forms a coherent
precipitate in $\alpha$.
Find. (a) Overall alloy composition. (b) Coherent vs. incoherent precipitates.
(c) Which alloys are age-hardenable, and the age-hardening procedure.
Fig. Q3c — reproduction of the source Y–Z eutectic diagram, drawn to the printed figure's own composition scale: the terminal $\alpha$ solubility falls between Alloys 1 and 2, and the maximum $\alpha$ solubility (at the eutectic isotherm) between Alloys 3 and 4. Alloys 2 and 3 (green) lie inside that window and are age-hardenable; Alloy 1 (red) is single-phase $\alpha$ at every temperature and Alloy 4 (red) is never single-phase $\alpha$, so neither is.
Approach
Part (a) is a direct lever-rule mass balance between the two phase compositions. Part (c) hinges
on recognizing that age hardening requires an alloy composition that is single-phase
$\alpha$ at some elevated temperature (so it can be solution-treated) but becomes
two-phase $\alpha+\beta$ on cooling to room temperature (so $\beta$ can precipitate) —
this is exactly the composition window between the room-temperature (terminal) solid solubility
limit and the maximum solid solubility at the eutectic temperature.
(a) Lever rule. Taking composition in %Sn: the solid $\alpha$ is $C_\alpha=18\%$
Sn (18% Sn dissolved in solid Pb) and the liquid is $C_L=100-43=57\%$ Sn (57% Sn / 43% Pb). With
mass fractions $f_L=0.60$, $f_\alpha=0.40$,
$$C_0=f_LC_L+f_\alpha C_\alpha=0.60(57)+0.40(18)=34.2+7.2=\boxed{41.4\%\ \text{Sn},\ 58.6\%\ \text{Pb}}.$$
(b) Coherent vs. incoherent precipitates. A coherent
precipitate has a crystal lattice that matches up atom-for-atom with the surrounding matrix lattice
across the interface; a small lattice mismatch is accommodated elastically (coherency strain)
rather than by a dislocation array, and it is exactly this coherency strain field that most
effectively obstructs dislocation motion — coherent zones (e.g. GP zones, $\theta''$ in
Al–Cu) give the strongest precipitation-hardening effect. An incoherent
precipitate has its own distinct crystal structure and orientation, separated from the matrix by a
sharp interphase boundary containing misfit dislocations; it is typically the coarser,
equilibrium-stage particle (e.g. overaged $\theta$ in Al–Cu) and strengthens mainly by
Orowan dislocation bypass, a weaker mechanism than coherency strengthening.
(c) Identifying the hardenable alloys. Age hardening needs both
conditions: the alloy must be two-phase ($\alpha+\beta$) at low temperature, so there is a $\beta$
precipitate to form, and it must be single-phase $\alpha$ at some higher temperature, so it
can be solution treated. On the Y–Z diagram the solvus (the right-hand boundary of the
$\alpha$ field) rises from the terminal solubility at the lowest temperature shown — which
falls between Alloy 1 and Alloy 2 — up to the maximum solubility at the
eutectic isotherm (the "knee" where solidus meets solvus), which falls between Alloy 3 and
Alloy 4. Reading each alloy's vertical line against those two limits:
Alloy 1 lies to the left of the terminal solubility limit, so its
vertical line never crosses the solvus: it is single-phase $\alpha$ at every temperature down to
the bottom of the diagram, never becomes supersaturated, and has no $\beta$ to precipitate —
not age-hardenable.
Alloys 2 and 3 fall between the terminal and maximum solubility limits: each
crosses the solvus on cooling (two-phase $\alpha+\beta$ at low temperature) yet lies inside the
single-phase $\alpha$ field just below the eutectic isotherm, so each can be solution treated,
quenched to trap a supersaturated solid solution, and aged to precipitate coherent $\beta$ —
both are age-hardenable.
Alloy 4 lies to the right of the knee (between the maximum solubility
composition and the eutectic composition): even at the highest sub-solidus temperature available
its overall composition exceeds the maximum $\alpha$ solubility, so it solidifies directly into an
$\alpha+\beta$ (proeutectic $\alpha$ plus eutectic) microstructure with no temperature at
which it exists as single-phase $\alpha$ — there is nothing to "solution treat," so it is
not age-hardenable by this mechanism.
Age-hardening procedure (for Alloys 2 and 3).
Solution heat treatment — heat above the alloy's solvus (but below the
eutectic/solidus) to dissolve all $\beta$ into a homogeneous single-phase $\alpha$ solid solution;
hold long enough for complete dissolution.
Quench — cool rapidly (e.g. water quench) to room temperature. This
suppresses diffusion so the $\beta$ phase cannot precipitate on cooling, trapping a metastable,
supersaturated single-phase $\alpha$.
Age — hold at room temperature (natural aging) or reheat to a moderate
intermediate temperature (artificial aging) to allow controlled, fine, coherent $\beta$
(or GP-zone) precipitation. This is the step that produces the actual strengthening; aging past the
peak-hardness point (overaging) coarsens the precipitate into the incoherent form and softens the
alloy again.
Quantity
Result
(a) Overall alloy composition
41.4% Sn, 58.6% Pb
(c) Age-hardenable alloys
Alloy 2 and Alloy 3
(c) Not age-hardenable
Alloy 1 (single-phase $\alpha$ at all temperatures) and Alloy 4 (never single-phase $\alpha$)