Question 13 of 13: Poly(ester amide) Monomer Identification
Nivaar worked solution (AI-drafted; not reviewed by a licensed engineer)
Notes on this paper
National Exam 04-BS-12, Organic Chemistry — December 2017. 3 hours, closed-book
examination (no calculator required); NOTES on page 1 state that TEN (10) questions constitute a
complete exam paper and only the first 10 as they appear in the answer book are marked, but this
sitting prints 13 numbered questions — every question and sub-part below is answered in full.
Reference texts: McMurry, Organic Chemistry, 9th ed. (acid–base
strength of drugs, pharmacokinetics/lipophilicity, β-lactam reactivity, SN2
stereochemistry, Williamson-ether-type syntheses, alkyne alkylation, IR/NMR structure
elucidation, radical vs. ionic HBr addition, electrophilic aromatic substitution & synthesis
design, acid strength/resonance & induction, polymer/monomer identification). Every molecular
formula, mass balance, and stereochemical (R/S) assignment below.
Approach. Trace the backbone bond-by-bond, classifying every carbonyl-heteroatom
linkage as an amide (C(=O)–N) or an ester (C(=O)–O), and identify each stretch of
backbone between amide/ester junctions as a distinct monomer residue.
Diacid residue –C(=O)CH2CH2C(=O)– forms TWO amide
bonds ⇒ succinic acid, HOOC–CH2CH2–COOH. Both ends
of this four-carbon diacyl fragment terminate in –NH– on the backbone, so this monomer
contributes no ester linkage at all — it is a simple saturated diacid, the shortest
possible one that still separates its two carbonyls by a flexible –CH2CH2–
spacer.
Monomer 1: succinic acid (diacid)
Monomer 2: leucine (amino acid)
–NH–CH(CH2CH(CH3)2)–C(=O)–O–,
an isobutyl-bearing α-amino-acid residue whose amine forms an amide (with succinic acid)
and whose carboxyl forms an ester (with the diol) ⇒ leucine,
(CH3)2CHCH2CH(NH2)COOH. The
–CH2CH(CH3)2 side chain hanging off the backbone
α-carbon is leucine's diagnostic isobutyl group; using leucine's own –COOH as an
ester partner (rather than a second amide) is exactly what turns this from a simple
polyamide (nylon-type) into a poly(ester amide).
–O–CH2CH2–O– bridges two ester
carbonyls ⇒ ethylene glycol, HOCH2CH2OH. A
simple diol, the shortest one available, supplying the second oxygen needed to complete the
leucine ester on one side and a second amino-acid ester on the other.
The final backbone stretch — a long
–NH–(CH2)4–CH(–NH–)– chain with a
pendant benzyl ester (–C(=O)–O–CH2C6H5)
hanging off its own α-carbon — is lysine, used "in reverse".
Lysine, H2N–(CH2)4–CH(NH2)–COOH, is the
one natural amino acid with two amine groups (α and ε). Here both
amines are used as backbone amide partners (the ε-NH2 condenses with the second
succinic-acid diacyl unit; the α-NH2 continues the backbone onward), while
lysine's own α-carboxyl is capped as a benzyl ester (a protecting/pendant
group, not a backbone linkage) — this pendant hydrophobic benzyl group is exactly the kind
of tunable side chain that lets formulation chemists adjust the coating's hydrophobicity/degradation
rate.
Monomer 3: ethylene glycol (diol)
Monomer 4: lysine (amino acid, used "in reverse")
#
Monomer
Role in backbone
1
Succinic acid
diacid — two amide linkages
2
Leucine (amino acid)
amine→amide; carboxyl→ester
3
Ethylene glycol
diol — two ester linkages
4
Lysine (amino acid, "in reverse")
both amines→amide (backbone); carboxyl→pendant benzyl ester