04-BS-12 · December 2017
Nivaar worked solution (AI-drafted; not reviewed by a licensed engineer)
National Exam 04-BS-12, Organic Chemistry — December 2017. 3 hours, closed-book examination (no calculator required); NOTES on page 1 state that TEN (10) questions constitute a complete exam paper and only the first 10 as they appear in the answer book are marked, but this sitting prints 13 numbered questions — every question and sub-part below is answered in full.
Reference texts: McMurry, Organic Chemistry, 9th ed. (acid–base strength of drugs, pharmacokinetics/lipophilicity, β-lactam reactivity, SN2 stereochemistry, Williamson-ether-type syntheses, alkyne alkylation, IR/NMR structure elucidation, radical vs. ionic HBr addition, electrophilic aromatic substitution & synthesis design, acid strength/resonance & induction, polymer/monomer identification). Every molecular formula, mass balance, and stereochemical (R/S) assignment below.
Question text not reproduced: the examination questions are © Engineers and Geoscientists BC. Open the official past paper (linked at the top of this page) to read the question, then follow the worked solution below.
Every part below is a textbook back-side (SN2) attack: the nucleophile approaches opposite the leaving group, so any reaction at a genuine stereocentre inverts its configuration; reaction at a non-stereogenic (primary) carbon simply substitutes, with no stereochemical outcome to report.
a) (R)-2-Chlorobutane + sodium methoxide (NaOCH3).
Methoxide performs a clean back-side attack at the secondary stereocentre, displacing chloride. Because O and Cl are both the top-priority substituent at that carbon (out-ranking the ethyl, methyl and H groups), the physical inversion of spatial arrangement here is also seen as a flip of the CIP descriptor: (R)-2-chlorobutane → (S)-2-methoxybutane.
b) 1-Bromobutane + sodium hydroxide (NaOH).
The reacting carbon (C1) is primary and bears two identical H substituents, so it is not a stereocentre either before or after the reaction — there is no stereochemical outcome to specify, only the constitutional product 1-butanol. (A primary substrate is also the ideal SN2 case: minimal steric hindrance to the incoming hydroxide.)
c) (S)-2-Chlorobutane + sodium ethoxide (NaOCH2CH3).
The mirror-image substrate of part (a): back-side attack by ethoxide again inverts the stereocentre, giving (R)-2-ethoxybutane. This pair (a)/(c) is deliberately the two enantiomeric starting materials, so the two products are likewise enantiomers of one another — a useful self-check.
d) trans-1-Bromo-2-methylcyclopentane + sodium cyanide (NaCN).
Cyanide attacks C1 from the face opposite the departing bromide. Because the C2 methyl group does not move, inversion at C1 flips which face the new substituent occupies relative to the fixed methyl: a trans (opposite-face) starting halide gives a cis (same-face) nitrile product. This is the general rule for any ring SN2: trans-starting material → cis product and vice versa, because inversion is defined relative to the unchanging substituent next door, not to some fixed lab frame.
| Part | Product | Stereochemical outcome |
|---|---|---|
| a | 2-methoxybutane | inversion, (R)→(S) |
| b | 1-butanol | none (primary carbon, not stereogenic) |
| c | 2-ethoxybutane | inversion, (S)→(R) |
| d | 2-methylcyclopentane-1-carbonitrile | inversion flips trans→cis (ring) |