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04-BS-12 · December 2017

Question 8 of 13: IR Spectrum Matching

Nivaar worked solution (AI-drafted; not reviewed by a licensed engineer)

Notes on this paper

National Exam 04-BS-12, Organic Chemistry — December 2017. 3 hours, closed-book examination (no calculator required); NOTES on page 1 state that TEN (10) questions constitute a complete exam paper and only the first 10 as they appear in the answer book are marked, but this sitting prints 13 numbered questions — every question and sub-part below is answered in full.

Reference texts: McMurry, Organic Chemistry, 9th ed. (acid–base strength of drugs, pharmacokinetics/lipophilicity, β-lactam reactivity, SN2 stereochemistry, Williamson-ether-type syntheses, alkyne alkylation, IR/NMR structure elucidation, radical vs. ionic HBr addition, electrophilic aromatic substitution & synthesis design, acid strength/resonance & induction, polymer/monomer identification). Every molecular formula, mass balance, and stereochemical (R/S) assignment below.

Question 8: IR Spectrum Matching (20 marks)

Question text not reproduced: the examination questions are © Engineers and Geoscientists BC. Open the official past paper (linked at the top of this page) to read the question, then follow the worked solution below.

Check: the six condensed formulas are read bond-by-bond from the drawn structures. Compound A is drawn with a carbonyl double bond and terminal –OH — i.e. butanoic acid, CH3CH2CH2C(=O)OH, not an alcohol (1-butanol) — and compound B's chain carries four CH2 units after the branch point (2-methylhex-1-ene, C7H14), not three. Reading A as an alcohol would invert the O–H-region reasoning for compound A (alcohol vs. acid bands are qualitatively different) below.
LabelCompound (corrected)FormulaKey functional group
Abutanoic acid, CH3CH2CH2C(=O)OHC4H8O2carboxylic acid
B2-methylhex-1-ene, CH2=C(CH3)CH2CH2CH2CH3C7H14terminal alkene
Ccumene (isopropylbenzene), C6H5CH(CH3)2C9H12aromatic ring, no C=O/OH
Ddiisopropyl ether, (CH3)2CHOCH(CH3)2C6H14Oether
Etert-butyl acetate, CH3C(=O)OC(CH3)3C6H12O2ester
Ftriethylmethanol (given), (CH3CH2)3COHC7H16O3° alcohol

Approach. Work spectrum-by-spectrum from the most diagnostic (rarest/most distinctive) absorptions first — the broad carboxylic-acid O–H, the sharp ester C=O, the aromatic ring-stretch pair, and the alkene's C=C/vinylic C–H — leaving the two featureless aliphatic spectra (ether, tertiary alcohol) to be distinguished last by their O–H presence/absence.

  1. Spectrum [5] → A (butanoic acid). This is the only spectrum with the unmistakable carboxylic-acid signature: a very broad, deep O–H absorption spanning roughly 2500–3300 cm−1 (H-bonded carboxylic-acid dimer, far broader than any simple alcohol O–H) merging directly into the C–H stretches, plus a strong, sharp C=O band near 1710 cm−1 (conjugated with the O–H, hydrogen-bonded acid C=O sits lower than an ester's).
  2. Spectrum [4] → E (tert-butyl acetate, ester). No O–H at all, but a strong, sharp carbonyl band appreciably higher than the acid's (esters absorb ≈1735–1750 cm−1, since there is no H-bonding to lower the C=O force constant), plus the two strong C–O–C stretch bands (asymmetric/symmetric, ≈1150–1250 cm−1) characteristic of an ester's acyl-oxygen linkage.
  3. Spectrum [3] → C (cumene, aromatic). No O–H, no C=O; instead a weak C–H stretch just above 3000 cm−1 (aromatic/vinylic C–H) and the diagnostic pair of aromatic ring-stretch bands near 1600 and 1500 cm−1, unique to the benzene ring.
  4. Spectrum [6] → B (2-methylhex-1-ene, alkene). A weak absorption just above 3000 cm−1 (vinylic =C–H, weaker/sharper than an aromatic C–H), a medium C=C stretch near 1640–1650 cm−1, and a dense cluster of aliphatic C–H bending/fingerprint peaks reflecting the longer saturated chain — no O–H, no C=O, no aromatic pair.
  5. Spectrum [2] → F (triethylmethanol, 3° alcohol). A broad, moderately deep O–H band centred near 3300–3400 cm−1 (hydrogen-bonded alcohol, narrower and shallower than the acid's in spectrum [5]) with no accompanying carbonyl anywhere in the fingerprint region.
  6. Spectrum [1] → D (diisopropyl ether), by elimination. No O–H, no C=O, no aromatic pair, no alkene C=C — the only remaining candidate, confirmed by the very strong, broad C–O–C asymmetric-stretch band near 1100–1150 cm−1 (the single most intense feature in the whole spectrum, as expected for a simple dialkyl ether).
SpectrumCompoundDiagnostic band(s)
[1]D – diisopropyl etherno O–H/C=O; strong C–O–C ≈1100–1150
[2]F – triethylmethanolbroad 3° alcohol O–H ≈3300–3400, no C=O
[3]C – cumenearomatic C–H >3000; ring bands 1600/1500
[4]E – tert-butyl acetatesharp ester C=O ≈1740; C–O–C pair
[5]A – butanoic acidvery broad acid O–H 2500–3300 + C=O ≈1710
[6]B – 2-methylhex-1-eneweak vinylic C–H >3000; C=C ≈1640