NivaarExam PrepOfficial exam papers ↗

23-Chem-B4 Biochemical Engineering · Undated paper

Question 4 of 5: Geometric Scale-Up of a Cell-Culture Bioreactor

Nivaar worked solution (AI-drafted; not reviewed by a licensed engineer)

Notes on this paper

National Exam 16-Chem-B4, Biochemical Engineering — May 2019 (the header on page 1 reads "16-Chem-B4/May 2019"). 3 hours, Closed-Book Exam (approved Casio or Sharp calculator permitted). Per the exam notes, FIVE (5) questions constitute a complete paper and all five must be answered; each question is of equal value (20 marks) and short-essay-format answers are marked for clarity and organization.

Reference texts: Shuler & Kargi, Bioprocess Engineering: Basic Concepts, 2nd ed.; Bailey & Ollis, Biochemical Engineering Fundamentals, 2nd ed.; Fogler, Elements of Chemical Reaction Engineering, 4th ed. (Weisz–Prater / internal-diffusion criteria).

Interpretation notes: Two points where the printed question itself needs an interpretation are flagged where they are used: the meaning of p in the Question 1 solubility equation, and the definition of the observable Thiele modulus in Question 3.

Question 4: Geometric Scale-Up of a Cell-Culture Bioreactor (20 marks)

Question text not reproduced: the examination questions are © Engineers and Geoscientists BC. Open the official past paper (linked at the top of this page) to read the question, then follow the worked solution below.

Given.

QuantitySmall vesselLarge vessel
Working volumeV1=0.01 m³V2=50 m³
Tank diameterT1=0.3 mT2=?
Impeller diameterD1=0.1 mD2=?
Agitation speedN1=100 rpmN2=?

Find. The large-vessel tank diameter T2, impeller diameter D2, and agitation speed N2 under geometric similarity (constant H/T and constant D/T) with equal impeller tip speed.

Vessel 1 (small)V₁ = 0.01 m³T₁ = 0.3 m, D₁ = 0.1 mN₁ = 100 rpmgeometric similarityequal tip speedVessel 2 (large)V₂ = 50 m³T₂ = 5.13 m, D₂ = 1.71 mN₂ = 5.85 rpm
Fig. 3 — geometric scale-up from a 0.01 m³ bench vessel to a 50 m³ production vessel (schematic, not to true relative scale); every linear dimension scales by the same factor, agitation speed scales inversely to preserve tip speed.

Approach. Geometric similarity means every linear dimension of the vessel (tank diameter, impeller diameter, liquid height) scales by the same factor S, found from the volume ratio; then equal impeller tip speed fixes the large-vessel agitation speed.

  1. Linear scale factor from the volume ratio. Since $V\propto T^3$ under geometric similarity (constant H/T), $$S=\left(\frac{V_2}{V_1}\right)^{1/3}=\left(\frac{50}{0.01}\right)^{1/3}=(5000)^{1/3}$$ $$\boxed{S=17.10}$$
  2. Large-vessel tank and impeller diameters. Every linear dimension scales by S, so the impeller-to-tank ratio D/T=0.1/0.3=1/3 is automatically preserved: $$T_2=S\,T_1=17.10\times0.3=\boxed{5.130\ \text{m}}$$ $$D_2=S\,D_1=17.10\times0.1=\boxed{1.710\ \text{m}}$$ (Check: $T_2/D_2=5.130/1.710=3.00=T_1/D_1$ — geometric similarity confirmed.)
  3. Agitation speed from equal impeller tip speed. Impeller tip speed is $u_{tip}=\pi ND$; setting $u_{tip,1}=u_{tip,2}$, $$\pi N_1D_1=\pi N_2D_2\quad\Rightarrow\quad N_2=N_1\frac{D_1}{D_2}=\frac{N_1}{S}$$ $$N_2=\frac{100}{17.10}=\boxed{5.848\ \text{rpm}}$$ The tip speed held constant in both vessels is $u_{tip}=\pi\times(100/60)\times0.1=0.524$ m/s.
QuantityValue
Linear scale factor, S17.10
Large-vessel tank diameter, T25.130 m
Large-vessel impeller diameter, D21.710 m
Large-vessel agitation speed, N25.848 rpm