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23-Chem-B6 Petroleum Refining and Petrochemicals · December 2015

Question 2 of 6: Octane Numbers, Flash Point and a Butadiene Dehydrogenation with Recycle

Nivaar worked solution (AI-drafted; not reviewed by a licensed engineer)

Notes on this paper

Paper format: Closed-book, 3 hours; six “Problem” blocks of equal value (20 marks each), of which five constitute a complete paper (the first five in the answer book are marked). Sub-parts (a),(b),(c)… may be treated independently; most call for concise essay answers and several require calculations with all steps shown. All six problems are solved in full below.

Reference texts: Gary, Handwerk, Kaiser & Geddes, Petroleum Refining: Technology and Economics (5th ed., CRC Press) — refinery conversion processes and product properties; Fahim, Al-Sahhaf & Elkilani, Fundamentals of Petroleum Refining (Elsevier) — cracking, treating, alkylation, characterization factors; Felder, Rousseau & Bullard, Elementary Principles of Chemical Processes (4th ed., Wiley) — material balances, recycle/bypass, combustion and gas-law calculations; Smith, Van Ness & Abbott, Introduction to Chemical Engineering Thermodynamics — Raoult’s-law VLE; supporting property data from Perry’s Chemical Engineers’ Handbook (9th ed.).

Question 2: Octane Numbers, Flash Point and a Butadiene Dehydrogenation with Recycle (20 marks — equal value)

Question text not reproduced: the examination questions are © Engineers and Geoscientists BC. Open the official past paper (linked at the top of this page) to read the question, then follow the worked solution below.

Check — printed reaction
The source prints the reaction as “$C_4H_4 \rightarrow C_4H_6 + 2H_2$”, but both the surrounding text (“pure normal butane C₄H₁₀”) and hydrogen balance require the reactant to be n-butane, C₄H₁₀. The dehydrogenation is therefore taken as $C_4H_{10} \rightarrow C_4H_6 + 2H_2$, which is what makes the stoichiometry (2 mol H₂ per mol butane) consistent with the stream data.

(a)(i) Difference between the MON and RON methods (4 marks)

Both octane numbers are measured on the same standardized single-cylinder, variable-compression CFR (Cooperative Fuel Research) engine, by matching the test fuel’s knock to reference blends of iso-octane (2,2,4-trimethylpentane, ON = 100) and n-heptane (ON = 0). The methods differ only in severity of the test conditions:

Because the MON conditions are more demanding, MON is always lower than RON for the same fuel; the gap (RON − MON) is the fuel’s sensitivity. North-American pump ratings quote the antiknock index AKI = (RON + MON)/2.

(a)(ii) What the octane numbers represent (4 marks)

An octane number is a measure of a gasoline’s antiknock quality — its resistance to knock, the spontaneous, uncontrolled autoignition of the unburned end-gas ahead of the spark-initiated flame front, which produces damaging pressure spikes. A fuel of octane number X knocks, under the test conditions, exactly like a blend of X vol% iso-octane with (100−X)% n-heptane. A higher octane number means greater knock resistance, which allows the engine to run at a higher compression ratio and more advanced spark timing — and hence deliver more power and efficiency — without knocking.

(b) Flash point (2 marks)

The flash point is the lowest temperature at which a fuel gives off vapour in sufficient concentration to form an ignitable mixture with air just above its surface, so that a momentary flash occurs when a small flame is applied (it need not sustain burning — that is the higher fire point). It is a volatility/flammability index used for safe handling, storage and classification, measured by closed-cup (Pensky–Martens/Abel) or open-cup (Cleveland) apparatus.

(c) Butadiene dehydrogenation with recycle

Given. Fresh feed is pure n-butane. The reactor–separator recycles part of the product back to a mixer.

StreamComposition / rate
ReactionC₄H₁₀ → C₄H₆ + 2 H₂
Product (leaving process)65 mol/hr H₂, 15 mol/hr C₄H₁₀, n mol/hr C₄H₆
Recycle20 mol/hr total: 20% C₄H₁₀ (4 mol/hr), 80% C₄H₆ (16 mol/hr)
Fresh feedpure C₄H₁₀, rate F (unknown)

Find. (i) fresh-feed rate F; (ii) product C₄H₆ rate n; (iii) single-pass conversion of butane.

MixerCatalyticdehydrogenationreactorSeparatorFeed Fpure C4H10Products65 H2, 15 C4H10, n C4H6Recycle 20 mol/hr20% C4H10, 80% C4H6
Figure 2 — Dehydrogenation flowsheet: fresh C₄H₁₀ and the recycle blend combine in the mixer, react in the catalytic reactor, and the separator splits the effluent into the product stream and the 20 mol/hr recycle.

Approach. Draw the envelope around the whole process (recycle is then internal): overall balances on hydrogen and on C₄ units give F and n; a balance across the reactor alone gives the single-pass conversion.

  1. Overall hydrogen balance ⇒ feed rate. Every mole of butane that reacts (overall) releases 2 mol H₂, and all H₂ leaves in the product. With fresh feed F entering and 15 mol/hr butane leaving unreacted, butane reacted overall $= F-15$, so$$H_{2,\text{out}} = 2(F-15) \;\Rightarrow\; 65 = 2(F-15) \;\Rightarrow\; \boxed{F = 47.5\ \text{mol/hr}}.$$
  2. Overall C₄ balance ⇒ product butadiene. Each butane converts to one butadiene, so all C₄ units are conserved: $F = (\text{C}_4\text{H}_{10}\ \text{out}) + (\text{C}_4\text{H}_6\ \text{out})$, giving$$n = F - 15 = 47.5 - 15 = \boxed{32.5\ \text{mol/hr C}_4\text{H}_6}.$$(Consistent with the H₂ balance, as it must be.)
  3. Butane entering the reactor. The mixer combines fresh feed with the recycle butane: $47.5 + 4 = 51.5$ mol/hr into the reactor.
  4. Butane leaving the reactor. The reactor effluent is split into product + recycle, so its butane equals the sum of the two: $15 + 4 = 19$ mol/hr. Butane converted in one pass $= 51.5 - 19 = 32.5$ mol/hr.
  5. Single-pass conversion. Referenced to the butane fed to the reactor:$$X_{\text{single}} = \frac{51.5 - 19}{51.5} = \frac{32.5}{51.5} = \boxed{0.631\ (63.1\%)}.$$
QuantityResult
(i) Fresh feed of pure C₄H₁₀47.5 mol/hr
(ii) Product flow of C₄H₆32.5 mol/hr
(iii) Single-pass conversion of butane63.1%
Butane to reactor / converted per pass51.5 / 32.5 mol/hr