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23-Chem-B6 Petroleum Refining and Petrochemicals · December 2015

Question 4 of 6: Alkylation Safety, Pour Point and a Distillation Split

Nivaar worked solution (AI-drafted; not reviewed by a licensed engineer)

Notes on this paper

Paper format: Closed-book, 3 hours; six “Problem” blocks of equal value (20 marks each), of which five constitute a complete paper (the first five in the answer book are marked). Sub-parts (a),(b),(c)… may be treated independently; most call for concise essay answers and several require calculations with all steps shown. All six problems are solved in full below.

Reference texts: Gary, Handwerk, Kaiser & Geddes, Petroleum Refining: Technology and Economics (5th ed., CRC Press) — refinery conversion processes and product properties; Fahim, Al-Sahhaf & Elkilani, Fundamentals of Petroleum Refining (Elsevier) — cracking, treating, alkylation, characterization factors; Felder, Rousseau & Bullard, Elementary Principles of Chemical Processes (4th ed., Wiley) — material balances, recycle/bypass, combustion and gas-law calculations; Smith, Van Ness & Abbott, Introduction to Chemical Engineering Thermodynamics — Raoult’s-law VLE; supporting property data from Perry’s Chemical Engineers’ Handbook (9th ed.).

Question 4: Alkylation Safety, Pour Point and a Distillation Split (20 marks — equal value)

Question text not reproduced: the examination questions are © Engineers and Geoscientists BC. Open the official past paper (linked at the top of this page) to read the question, then follow the worked solution below.

(a)(i) Main safety risks around an alkylation plant (4 marks)

Alkylation reacts light olefins with isobutane over a strong liquid-acid catalyst — either hydrofluoric acid (HF) or sulphuric acid (H₂SO₄) — while handling large inventories of volatile, flammable hydrocarbons under pressure. The dominant hazards are:

(a)(ii) Precautions (4 marks)

(b) Pour point of a crude oil (2 marks)

The pour point is the lowest temperature at which a crude oil (or product) will still flow or pour under standardized test conditions; a few degrees below it the oil stops moving as dissolved wax crystallizes into a gel. It indicates low-temperature pumpability/handling and reflects the paraffin-wax content — important for pipeline transport and cold-climate storage.

(c) Distillation-column split

Given. A binary feed is separated into an A-rich overhead and a B-rich bottom.

StreamRate / composition
Feed $F$100 mol/h — 60% A, 40% B
Distillate $D$90% A (10% B)
Bottoms $W$85% B (15% A)

Find. The distillate rate $D$ and bottoms rate $W$.

DistillationcolumnFeed F = 100 mol/h60% A, 40% BDistillate D90% ABottoms W85% B
Figure 3 — Distillation column: 100 mol/h feed (60% A) split into a 90%-A distillate overhead and an 85%-B bottoms.

Approach. Two independent balances — total moles and component A — solve for the two unknowns.

  1. Total and component-A balances. $F = D + W$ and $z_A F = x_{D,A} D + x_{W,A} W$:$$100 = D + W, \qquad 0.60(100) = 0.90\,D + 0.15\,W.$$
  2. Solve. Substituting $W = 100 - D$: $60 = 0.90D + 0.15(100-D) = 0.75D + 15$, so$$D = \frac{60-15}{0.75} = \boxed{60\ \text{mol/h}}, \qquad W = 100 - 60 = \boxed{40\ \text{mol/h}}.$$
  3. Check component B. B in $= 40$; B out $= 0.10(60) + 0.85(40) = 6 + 34 = 40$ mol/h — closes exactly.
QuantityResult
Distillate $D$ (90% A)60 mol/h
Bottoms $W$ (85% B)40 mol/h