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16-Civ-A4 Geotechnical Materials and Analysis · May 2013

Question 2 of 6: Effective stress under an added load — drained vs undrained

Nivaar worked solution (AI-drafted; not reviewed by a licensed engineer)

Notes on this paper

Paper format: 98-Civ-A4 Geotechnical Materials and Analysis, National Examinations May 2013 — closed book, 3 hours, 6 questions totalling 100 marks; drawing instruments required; all charts and equations supplied at the back. Answer all questions. Take γw = 9.81 kN/m³ throughout.

Reference texts. B. M. Das & K. Sobhan, Principles of Geotechnical Engineering (Cengage); R. F. Craig, Craig's Soil Mechanics (Knappett & Craig, CRC); R. D. Holtz, W. D. Kovacs & T. C. Sheahan, An Introduction to Geotechnical Engineering (Pearson). Chart/influence factors per the PEO formula sheet supplied with the paper.



Question 2: Effective stress under an added load — drained vs undrained (10 marks)

Question text not reproduced: the examination questions are © Engineers and Geoscientists BC. Open the official past paper (linked at the top of this page) to read the question, then follow the worked solution below.

Given. A saturated soil element (S = 100 %) carrying total vertical stress σ, with a static pore-water pressure us registered by the stand-pipe; a further total stress Δσ is then applied at the surface.

Find. The effective stress σ' immediately after loading (undrained) and after full drainage (drained), expressed through σ, Δσ, us and ue, with commentary.

Saturated soilσu_sH
Figure 1 — saturated soil in a rigid container; the stand-pipe records the pore-water pressure us. The applied total stress σ (later σ + Δσ) acts on the top.

Approach. Apply Terzaghi's effective-stress principle σ' = σ − u, and split the pore pressure into the static part us plus the load-induced excess part ue; for a saturated soil the pore-pressure parameter B = 1, so the instant of loading transfers all of Δσ to the water.

  1. Initial (reference) state. Before Δσ, the pore pressure is purely static and $$\sigma' = \sigma - u_s.$$ This is the effective stress the skeleton already carries.
  2. Undrained instant — the water takes the load. The container is saturated and closed, so no water can leave. For a saturated soil the excess pore pressure equals the applied total-stress increment (B = 1): $$u_e = \Delta\sigma .$$ The pore pressure becomes u = us + ue = us + Δσ, and the total stress becomes σ + Δσ. Hence $$\sigma'_{\text{undrained}} = (\sigma + \Delta\sigma) - (u_s + \Delta\sigma) = \boxed{\,\sigma - u_s\,}.$$ The effective stress is unchanged from the initial value; the entire increment Δσ is momentarily carried by the pore water.
  3. Drained end state — the excess dissipates. Given time, the excess pressure drains away, ue → 0, and the pore pressure returns to the static value us. With the total stress still σ + Δσ, $$\sigma'_{\text{drained}} = (\sigma + \Delta\sigma) - u_s = \boxed{\,(\sigma - u_s) + \Delta\sigma\,}.$$ The effective stress has now risen by exactly Δσ.

Comparing the two: the added stress Δσ is first parked entirely in the pore water and only later transferred to the soil skeleton as the water drains. Because it is the effective stress that controls volume change and shear strength, the soil experiences no immediate compression or strength gain (undrained), whereas the long-term effective stress increases by the full Δσ, producing the consolidation settlement and strength gain. This is precisely Terzaghi's one-dimensional consolidation picture: settlement is time-dependent because σ' grows only as ue decays.

Effective stress after applying Δσ
ConditionPore pressure uEffective stress σ'
Initialusσ − us
Undrained (t = 0)us + Δσσ − us (unchanged)
Drained (t = ∞)us(σ − us) + Δσ