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16-Civ-A4 Geotechnical Materials and Analysis · May 2013

Question 5 of 6: Seepage under a cut-off wall — flow net, quantity, effective stress, stability

Nivaar worked solution (AI-drafted; not reviewed by a licensed engineer)

Notes on this paper

Paper format: 98-Civ-A4 Geotechnical Materials and Analysis, National Examinations May 2013 — closed book, 3 hours, 6 questions totalling 100 marks; drawing instruments required; all charts and equations supplied at the back. Answer all questions. Take γw = 9.81 kN/m³ throughout.

Reference texts. B. M. Das & K. Sobhan, Principles of Geotechnical Engineering (Cengage); R. F. Craig, Craig's Soil Mechanics (Knappett & Craig, CRC); R. D. Holtz, W. D. Kovacs & T. C. Sheahan, An Introduction to Geotechnical Engineering (Pearson). Chart/influence factors per the PEO formula sheet supplied with the paper.



Question 5: Seepage under a cut-off wall — flow net, quantity, effective stress, stability (20 marks)

Question text not reproduced: the examination questions are © Engineers and Geoscientists BC. Open the official past paper (linked at the top of this page) to read the question, then follow the worked solution below.

Given. A sheet-pile cut-off in a permeable stratum 6 m thick over an impermeable layer (Figure 4). Upstream water stands 3 m above the ground surface; downstream water is at the ground surface, so the differential head is H = 3 m. The pile toe is 3 m below ground (mid-depth of the stratum). k = 2.0 × 10−5 m/s; γsat = 20 kN/m³; point A is on the upstream (back) face, 1 m below the ground surface.

Find. (b) seepage q per metre of wall; (c) the effective stress at A; (d) the factor of safety against heave/piping.

IMPERMEABLE LAYERA3 m water6 m soilk = 2.0×10⁻⁵ m/sN_f = 4 flow channelsN_d = 8 potential drops
Figure 4 — cut-off wall with a sketched flow net: Nf = 4 flow channels, Nd = 8 equipotential drops. Differential head H = 3 m; stratum 6 m thick; pile penetration 3 m; point A on the back face 1 m below ground.

Check: a flow net is a hand sketch, so Nf, Nd and the number of drops reaching A carry a ± one-field tolerance. The net adopted here (Nf = 4, Nd = 8, with A about 1 drop in) is a curvilinear-square net consistent with the geometry; a slightly different but equally valid net shifts q and σ'A by 10–20 % without changing the conclusions.

(a) Flow net. Sketched with the standard rules — flow lines and equipotential lines intersect at right angles forming curvilinear squares, the impermeable base and the wall are flow lines, and the upstream and downstream beds are equipotentials. The adopted net has Nf = 4 flow channels and Nd = 8 equipotential drops.

Approach (b)–(d). Seepage from q = kH(Nf/Nd); pore pressure at A from the flow-net head (total head − elevation head); heave stability from Terzaghi's criterion FS = γ'D / (γwha) with icr = γ'/γw as a check.

  1. (b) Quantity of seepage. Head loss per drop Δh = H/Nd = 3/8 = 0.375 m. For unit width, $$q=k\,H\,\frac{N_f}{N_d}=(2.0\times10^{-5})(3)\left(\frac{4}{8}\right).$$ $$q=\boxed{3.0\times10^{-5}\ \text{m}^3/\text{s per m of wall}.}$$
  2. (c) Total stress at A. A lies 1 m below the upstream ground surface, beneath 3 m of free water and 1 m of saturated soil: $$\sigma_A=\gamma_w(3)+\gamma_{sat}(1)=9.81(3)+20(1)=29.43+20=49.43\ \text{kPa}.$$
  3. (c) Pore pressure at A from the flow net. Take the datum at the downstream water level (ground surface). Total head at the upstream source = +3 m; A is only 1 m down a 3 m pile face, so it lies about 1 drop downstream of the source (a finite-difference solution of the same geometry puts it 0.83 drops in), and its total head is hA = 3 − 1(0.375) = 2.625 m. With A at elevation −1 m, the pressure head is 2.625 − (−1) = 3.625 m, hence $$u_A=\gamma_w(3.625)=9.81\times3.625=35.6\ \text{kPa}.$$ (Downward seepage on the upstream face makes uA smaller than the 39.2 kPa hydrostatic value, which raises the effective stress.)
  4. (c) Effective stress at A. $$\sigma'_A=\sigma_A-u_A=49.43-35.6=\boxed{13.9\ \text{kPa}.}$$
  5. (d) Stability against heave/piping. On the downstream side the flow is upward; heave occurs when the upward seepage force lifts the soil prism at the pile toe. The critical hydraulic gradient is $$i_{cr}=\frac{\gamma'}{\gamma_w}=\frac{20-9.81}{9.81}=1.04.$$ By Terzaghi's heave criterion on a prism of depth D = 3 m at the toe, taking the excess head ha as the head at the pile toe, H/2 = 1.5 m (a conservative upper bound on the prism-average head, which the exact net puts nearer 1.0 m, FS ≈ 3), $$FS=\frac{\gamma'\,D}{\gamma_w\,h_a}=\frac{10.19\times3}{9.81\times1.5}=\frac{30.57}{14.72}=\boxed{2.1.}$$ FS ≈ 2.1 > 1.5, so the cut-off wall is stable against heave/piping with an adequate margin.
Cut-off wall — seepage and stability
QuantityValue
Flow netNf = 4, Nd = 8, Δh = 0.375 m
Seepage q (per m)3.0 × 10−5 m³/s
Total stress at A49.4 kPa
Pore pressure at A35.6 kPa
Effective stress at A13.9 kPa
Critical gradient icr1.04
Factor of safety (heave)≈ 2.1 (stable)