NivaarExam PrepOfficial exam papers ↗

16-Civ-A4 Geotechnical Materials and Analysis · Undated paper

Question 4 of 6: Consolidation Test — e–log σ′ Curve, p c and C c

Nivaar worked solution (AI-drafted; not reviewed by a licensed engineer)

Notes on this paper

National Examinations — May 2019  |  16-Civ-A4 Geotechnical Materials and Analysis  |  3 hours, open book  |  100 marks  |  Answer ALL questions (Q1–Q6).

Reference texts: Das & Sobhan, Principles of Geotechnical Engineering, 9th ed. (Cengage); Craig, Craig's Soil Mechanics, 8th ed.; Holtz, Kovacs & Sheahan, An Introduction to Geotechnical Engineering, 2nd ed. Canadian practice frame (CFEM 4th ed., EGBC).

Source-quality note. Flow-net field counts carry the usual ±½-field hand-sketch tolerance (Exam Note 3).

Question 4: Consolidation Test — e–log σ′ Curve, pc and Cc (20 marks)

Question text not reproduced: the examination questions are © Engineers and Geoscientists BC. Open the official past paper (linked at the top of this page) to read the question, then follow the worked solution below.

Given. Oedometer data (six load increments):

Given data — void ratio vs. effective pressure
$\sigma'$ (kN/m$^2$)2550100200400500
Void ratio $e$1.2101.1951.1501.0600.9800.925

Find. (a) the $e$–$\log\sigma'$ plot; (b) the preconsolidation pressure $p_c$ by Casagrande's construction; (c) the compression index $C_c$.

1010010000.900.951.001.051.101.151.201.25virgin line (slope C_c)p_c ~ 90 kPaEffective pressure, σ' (kN/m²) [log scale]Void ratio, e
Laboratory $e$–$\log\sigma'$ curve. The response is flat (recompression) below about 90 kPa and steepens into a straight virgin line above it; Casagrande's construction locates $p_c$ near the break.

Approach. Plot $e$ against $\log\sigma'$; apply Casagrande's construction at the point of maximum curvature to read $p_c$; take the slope of the straight virgin portion as $C_c$.

  1. (a) Plot. Plotting the six points shows the classic two-branch shape: a gently sloping recompression branch from 25–100 kPa ($e$ from 1.210 to 1.150) that bends into a much steeper straight virgin branch beyond 100 kPa (Figure above).
  2. (b) Casagrande's method for $p_c$. At the point of minimum radius of curvature (near $\sigma'\approx70$–90 kPa) draw (i) a horizontal line, (ii) a tangent, and (iii) the bisector of the angle between them. The straight virgin line, projected back, meets the bisector at the preconsolidation pressure: $$\boxed{p_c \approx 90\ \text{kN/m}^2\ \text{(graphical)}.}$$
  3. (c) Compression index $C_c$. $C_c$ is the slope of the virgin straight line. Reading two well-separated points on that branch ($\sigma'=100$, $e=1.150$ and $\sigma'=400$, $e=0.980$): $$C_c=\frac{e_1-e_2}{\log(\sigma_2'/\sigma_1')}=\frac{1.150-0.980}{\log(400/100)}=\frac{0.170}{0.602}=\boxed{0.28}.$$ (The 200–400 kPa pair gives 0.27, confirming the virgin-line slope $C_c\approx0.28$.)
Q4 — consolidation parameters
QuantityValueMethod
Preconsolidation pressure $p_c$≈ 90 kN/m$^2$Casagrande construction (graphical)
Compression index $C_c$0.28slope of virgin line (100–400 kPa)
Check: $p_c$ from Casagrande's construction is a graphical read and carries roughly ±15 kPa depending on where the maximum-curvature point is judged; the soil is lightly overconsolidated (the recompression branch precedes the virgin line). Empirically $C_c\approx0.009(LL-10)$ would imply a liquid limit near 40, consistent with a medium-plasticity clay.